Warning: input could be > 10000...

Solution by segment tree:

struct Node
{
Node(int s, int e) : start(s), end(e), cnt(), left(nullptr), right(nullptr)
{};
int start;
int end;
int cnt;
//
Node *left;
Node *right;
};
class Solution {
Node *pRoot; void update(int v)
{
Node *p = pRoot; while(p)
{
p->cnt ++;
if(p->start == p->end) break;
int mid = (p->start + p->end) / ;
if(v <= mid)
{
if(!p->left)
{
p->left = new Node(p->start, mid);
}
p = p->left;
}
else
{
if(!p->right)
{
p->right = new Node(mid + , p->end);
}
p = p->right;
}
}
}
int query(Node *p, int v)
{
if(!p) return ; int mid = (p->start + p->end) / ;
if(v < mid)
{
return query(p->left, v);
}
else if(v == mid)
{
return p->left ? p->left->cnt : ;
}
// v > mid
return (p->left ? p->left->cnt : ) + query(p->right, v);
}
public:
/**
* @param A: An integer array
* @return: Count the number of element before this element 'ai' is
* smaller than it and return count number array
*/
vector<int> countOfSmallerNumberII(vector<int> &A) { pRoot = new Node(, ); vector<int> ret;
for(auto v : A)
{
ret.push_back(query(pRoot, v - ));
update(v);
}
return ret;
}
};

LintCode "Count of Smaller Number before itself"的更多相关文章

  1. Lintcode: Count of Smaller Number

    Give you an integer array (index from 0 to n-1, where n is the size of this array, value from 0 to 1 ...

  2. LeetCode "Count of Smaller Number After Self"

    Almost identical to LintCode "Count of Smaller Number before Self". Corner case needs to b ...

  3. Lintcode249 Count of Smaller Number before itself solution 题解

    [题目描述] Give you an integer array (index from 0 to n-1, where n is the size of this array, data value ...

  4. Lintcode248 Count of Smaller Number solution 题解

    [题目描述] Give you an integer array (index from 0 to n-1, where n is the size of this array, value from ...

  5. Count of Smaller Number before itself

    Give you an integer array (index from 0 to n-1, where n is the size of this array, value from 0 to 1 ...

  6. [Swift]LeetCode315. 计算右侧小于当前元素的个数 | Count of Smaller Numbers After Self

    You are given an integer array nums and you have to return a new countsarray. The counts array has t ...

  7. leetcode 315. Count of Smaller Numbers After Self 两种思路(欢迎探讨更优解法)

    说来惭愧,已经四个月没有切 leetcode 上的题目了. 虽然工作中很少(几乎)没有用到什么高级算法,数据结构,但是我一直坚信 "任何语言都会过时,只有数据结构和算法才能永恒". ...

  8. [LeetCode] 315. Count of Smaller Numbers After Self (Hard)

    315. Count of Smaller Numbers After Self class Solution { public: vector<int> countSmaller(vec ...

  9. leetcode 315. Count of Smaller Numbers After Self 两种思路

    说来惭愧,已经四个月没有切 leetcode 上的题目了. 虽然工作中很少(几乎)没有用到什么高级算法,数据结构,但是我一直坚信 "任何语言都会过时,只有数据结构和算法才能永恒". ...

随机推荐

  1. 转载blog_Linux下Tomcat日志定期清理 及 logrotate 配置

    服务器上的tomcat的catalina.out文件越来越大,查看起来很不方便,以前每次都是想起来的时候手工清理一下(cat /dev/null > catalina.out),后来发现了log ...

  2. JS中offsetLeft,Left,clientLeft的区别(纯转贴)

    假设 obj 为某个 HTML 控件. obj.offsetTop 指 obj 相对于版面或由 offsetParent 属性指定的父坐标的计算上侧位置,整型,单位像素. obj.offsetLeft ...

  3. OpenHCI - Data Transfer Types

    There are four data transfer types defined in USB(USB中有4种数据传输类型). Each type is optimized to match th ...

  4. Linux系统入门学习:在CentOS上安装phpMyAdmin

    问题:我正在CentOS上运行一个MySQL/MariaDB服务,并且我想要通过网络接口来用phpMyAdmin来管理数据库.在CentOS上安装phpMyAdmin的最佳方法是什么? phpMyAd ...

  5. Apache CXF 101 Win Eclipse开发环境搭建

    前言 博客草稿中“SOA生态系统初探”一文一直没有进展,感觉要将SOA.Web Service(WS).REST等概念阐述清楚还需要一些酝酿. 顶天须得立地,这里记录一些“下里巴人”的实践,主要考察A ...

  6. json数据的jquery操作和asp.net后台操作

    jquery操作 json对象创建 var item0={"a":"val1","b":"val2"}; json对象字 ...

  7. Codeforces Round #285 (Div. 2) A B C 模拟 stl 拓扑排序

    A. Contest time limit per test 1 second memory limit per test 256 megabytes input standard input out ...

  8. Welcome to MacJournal!

    Welcome to MacJournal 6 To get started, create a new entry by clicking on "New Entry" in t ...

  9. Matlab神经网络工具箱学习之二

    螃蟹的分类 这个例子的目的是根据螃蟹的品种.背壳的长宽等等属性来判断螃蟹的性别,雄性还是雌性. 训练数据一共有六个属性: species, frontallip, rearwidth, length, ...

  10. HTTP详解(3)-http1.0 和http1.1 区别

    HTTP详解(3)-http1.0 和http1.1 区别 分类: 网络知识2013-03-17 16:51 1685人阅读 评论(0) 收藏 举报   目录(?)[+]   翻了下HTTP1.1的协 ...