Almost identical to LintCode "Count of Smaller Number before Self". Corner case needs to be taken care of.

class Solution {
//////////////////
// Fenwick Tree //
vector<long long> ft;
void update(int i, long long x)
{
if (i == )
{
ft[] ++;
return;
}
if ((i + ) > ft.size()) return;
for (; i < ft.size(); i += (i & -i))
ft[i] += x;
} long long query(int i)
{
if (i == ) return ft[]; i = min(i, int(ft.size() - ));
long long s = ;
for (; i > ; i -= (i & -i))
s += ft[i];
return s + ft[];
}
//////////////////
public:
vector<int> countSmaller(vector<int>& nums) {
ft.assign(, );
vector<int> ret;
if(nums.size() < ) return {};
// handling neg
auto r = minmax_element(nums.begin(), nums.end());
int minv = *r.first;
int maxv = *r.second;
int d = ;
vector<long long> ns;
if (minv < )
{
d = -minv + ;
}
for (auto v : nums)
ns.push_back(v + d);
// for (int i = ns.size() - ; i >= ; i--)
{
int v = ns[i];
int r = query(v - );
update(v, );
ret.push_back(r);
}
reverse(ret.begin(), ret.end());
return ret;
}
};

LeetCode "Count of Smaller Number After Self"的更多相关文章

  1. Lintcode249 Count of Smaller Number before itself solution 题解

    [题目描述] Give you an integer array (index from 0 to n-1, where n is the size of this array, data value ...

  2. [LeetCode] Count of Smaller Numbers After Self 计算后面较小数字的个数

    You are given an integer array nums and you have to return a new counts array. The counts array has ...

  3. LeetCode Count of Smaller Numbers After Self

    原题链接在这里:https://leetcode.com/problems/count-of-smaller-numbers-after-self/ 题目: You are given an inte ...

  4. Lintcode: Count of Smaller Number

    Give you an integer array (index from 0 to n-1, where n is the size of this array, value from 0 to 1 ...

  5. LintCode "Count of Smaller Number before itself"

    Warning: input could be > 10000... Solution by segment tree: struct Node { Node(), left(nullptr), ...

  6. Count of Smaller Number before itself

    Give you an integer array (index from 0 to n-1, where n is the size of this array, value from 0 to 1 ...

  7. Lintcode248 Count of Smaller Number solution 题解

    [题目描述] Give you an integer array (index from 0 to n-1, where n is the size of this array, value from ...

  8. leetcode 315. Count of Smaller Numbers After Self 两种思路(欢迎探讨更优解法)

    说来惭愧,已经四个月没有切 leetcode 上的题目了. 虽然工作中很少(几乎)没有用到什么高级算法,数据结构,但是我一直坚信 "任何语言都会过时,只有数据结构和算法才能永恒". ...

  9. leetcode 315. Count of Smaller Numbers After Self 两种思路

    说来惭愧,已经四个月没有切 leetcode 上的题目了. 虽然工作中很少(几乎)没有用到什么高级算法,数据结构,但是我一直坚信 "任何语言都会过时,只有数据结构和算法才能永恒". ...

随机推荐

  1. xampp访问403 Access forbidden 解决办法

    本地可以访问,换一台机子就不行了,是因为权限没有开启,安装目录xampp\apache\conf\extra内有个httpd-xampp.conf文件,打开, 最后一段是 # # New XAMPP ...

  2. Open vSwitch FAQ (三)

    Quality of Service (QoS) Q: How do I configure Quality of Service (QoS)? A: Suppose that you want to ...

  3. Qt之镜像旋转

    简述 Qt中可以对图片进行任何处理,改变亮度.灰度.透明度.大小.形状等,当然也可以进行镜像旋转! 简单的几行代码,有时就可以事半功倍...甚至图片不用经过美工处理就可以直接拿来使用! 简述 实现 原 ...

  4. centos6.4安装配置vpn服务器步骤详解

      centos6.4安装配置vpn服务器步骤详解,从安装VPN到配置VPN服务器.配置VPN服务器的路由转发功能,每一步都很详细   一.VPN服务器环境说明 操作系统:CentOS release ...

  5. 如何让Visual Studio 清除最近打开项目 关闭上次未关闭的标签窗口

    删除最近打开的文件: 打开HKEY_CURRENT_USER\Software\Microsoft\VisualStudio\9.0\FileMRUList 删除最近打开的项目: 打开HKEY_CUR ...

  6. Java-->用递归方法复制目录、子目录以及文件(文件用到IO流)

    package com.dragon.java.newcopyfile; import java.io.File; import java.io.FileInputStream; import jav ...

  7. Deep Learning论文笔记之(四)CNN卷积神经网络推导和实现(转)

    Deep Learning论文笔记之(四)CNN卷积神经网络推导和实现 zouxy09@qq.com http://blog.csdn.net/zouxy09          自己平时看了一些论文, ...

  8. linux缓冲的概念fopen /open,read/write和fread/fwrite区别

    fopen /open区别 UNIX环境下的C 对二进制流文件的读写有两套班子:1) fopen,fread,fwrite ; 2) open, read, write这里简单的介绍一下他们的区别.1 ...

  9. activiti 任务节点 处理人设置【转】

    转自http://blog.csdn.net/qq_30739519/article/details/51225067 1.1.1. 前言 分享牛原创(尊重原创 转载对的时候第一行请注明,转载出处来自 ...

  10. 海量字符串查找——bloom filter,c

    对于海量字符串的查找,一般有两种方法,一种是建树,还有一种就是bf算法,即布隆过滤器,这个从原来上讲比较简单,也易于实现,主要就是根据哈希算法来实现. int len(char *ch) { int ...