设计一个支持以下两个操作的数据结构:
void addWord(word)
bool search(word)
search(word) 可以搜索文字或正则表达式字符串,字符串只包含字母 . 或 a-z 。 . 意味着它可以代表任何一个字母。
例如:
addWord("bad")
addWord("dad")
addWord("mad")
search("pad") -> false
search("bad") -> true
search(".ad") -> true
search("b..") -> true
注意事项:
你可以假设所有单词都是由小写字母 a-z 组成的。

详见:https://leetcode.com/problems/add-and-search-word-data-structure-design/description/

Java实现:

class TrieNode {
public TrieNode[] children;
public boolean isWord = false;
public TrieNode(){
children=new TrieNode[26];
}
} class WordDictionary {
private TrieNode root; /** Initialize your data structure here. */
public WordDictionary() {
root=new TrieNode();
} /** Adds a word into the data structure. */
public void addWord(String word) {
TrieNode node = root;
for (char ch: word.toCharArray()) {
if (node.children[ch-'a'] == null) {
node.children[ch-'a'] = new TrieNode();
}
node = node.children[ch-'a'];
}
node.isWord = true;
} /** Returns if the word is in the data structure. A word could contain the dot character '.' to represent any one letter. */
public boolean search(String word) {
return helper(word, 0, root);
} private boolean helper(String word, int start, TrieNode node) {
if (start == word.length()){
return node.isWord;
}
char ch = word.charAt(start);
if (ch == '.') {
for (int i = 0; i < 26; i++) {
if (node.children[i] != null && helper(word, start+1, node.children[i])) {
return true;
}
}
} else {
return node.children[ch-'a'] != null && helper(word, start+1, node.children[ch-'a']);
}
return false;
}
} /**
* Your WordDictionary object will be instantiated and called as such:
* WordDictionary obj = new WordDictionary();
* obj.addWord(word);
* boolean param_2 = obj.search(word);
*/

C++实现:

class TrieNode {
public:
TrieNode *next[26];
char c;
bool isWord;
TrieNode() : isWord(false) {
for (auto & c: next)
{
c=nullptr;
}
}
TrieNode(char _c):c(_c),isWord(false)
{
for(auto &c:next)
{
c=nullptr;
}
}
};
class WordDictionary {
public:
WordDictionary() {
root = new TrieNode();
} // Adds a word into the data structure.
void addWord(string word) {
TrieNode *p = root;
for (auto &c : word)
{
int i = c - 'a';
if (!p->next[i])
{
p->next[i] = new TrieNode(c);
}
p = p->next[i];
}
p->isWord = true;
} // Returns if the word is in the data structure. A word could
// contain the dot character '.' to represent any one letter.
bool search(string word) {
return searchWord(word, root, 0);
} bool searchWord(string &word, TrieNode *p, int i) {
if (i == word.size())
{
return p->isWord;
}
if (word[i] == '.')
{
for (auto &c : p->next)
{
if (c && searchWord(word, c, i + 1))
{
return true;
}
}
return false;
}
else
{
return p->next[word[i] - 'a'] && searchWord(word, p->next[word[i] - 'a'], i + 1);
}
} private:
TrieNode *root;
}; // Your WordDictionary object will be instantiated and called as such:
// WordDictionary wordDictionary;
// wordDictionary.addWord("word");
// wordDictionary.search("pattern");

参考:https://www.cnblogs.com/grandyang/p/4507286.html

211 Add and Search Word - Data structure design 添加与搜索单词 - 数据结构设计的更多相关文章

  1. 【LeetCode】211. Add and Search Word - Data structure design 添加与搜索单词 - 数据结构设计

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:Leetcode, 力扣,211,搜索单词,前缀树,字典树 ...

  2. [LeetCode] 211. Add and Search Word - Data structure design 添加和查找单词-数据结构设计

    Design a data structure that supports the following two operations: void addWord(word) bool search(w ...

  3. Leetcode211. Add and Search Word - Data structure design 添加与搜索单词 - 数据结构设计

    设计一个支持以下两种操作的数据结构: void addWord(word) bool search(word) search(word) 可以搜索文字或正则表达式字符串,字符串只包含字母 . 或 a- ...

  4. [LeetCode] Add and Search Word - Data structure design 添加和查找单词-数据结构设计

    Design a data structure that supports the following two operations: void addWord(word) bool search(w ...

  5. [leetcode]211. Add and Search Word - Data structure design添加查找单词 - 数据结构设计

    Design a data structure that supports the following two operations: void addWord(word) bool search(w ...

  6. 字典树(查找树) leetcode 208. Implement Trie (Prefix Tree) 、211. Add and Search Word - Data structure design

    字典树(查找树) 26个分支作用:检测字符串是否在这个字典里面插入.查找 字典树与哈希表的对比:时间复杂度:以字符来看:O(N).O(N) 以字符串来看:O(1).O(1)空间复杂度:字典树远远小于哈 ...

  7. 【LeetCode】211. Add and Search Word - Data structure design

    Add and Search Word - Data structure design Design a data structure that supports the following two ...

  8. 【刷题-LeetCode】211. Add and Search Word - Data structure design

    Add and Search Word - Data structure design Design a data structure that supports the following two ...

  9. Java for LeetCode 211 Add and Search Word - Data structure design

    Design a data structure that supports the following two operations: void addWord(word)bool search(wo ...

随机推荐

  1. SQLite Expert表分离和解决SQLite Expert删除表后大小不变的问题

    最后要使用到号码归属地的查询,在网上找到一个数据库文件.大小有12M多,压缩成zip也有1.9M,这样对于一个apk的大小非常不利,后来看了一下数据库的内容,发现有非常多冗余.特别是中文字符占用非常大 ...

  2. Java 实现桥接(Bridge)模式

    类图: watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvamp3d21scDQ1Ng==/font/5a6L5L2T/fontsize/400/fill/I0 ...

  3. C#&.NET高级面试题

    转自http://chaoyouzhuo.blog.163.com/blog/static/1263760012011109114131316/ 1. DateTime.Parse(myString) ...

  4. mount: wrong fs type

    # mount -t nfs -o nolock 192.168.1.84:/home/jason/filesys /mnt/nfsmount: wrong fs type, bad option, ...

  5. iPhone开发关于UDID和UUID的一些理解【转】

    原文地址:http://blog.csdn.net/xunyn/article/details/13629071 一.UDID(Unique Device Identifier) UDID是Uniqu ...

  6. list if else 遍历 特征合并

    特征合并 import re l = ['a', 'b1'] ll = [i if re.search('\d', i) is None else i[0:re.search('\d', i).end ...

  7. 编译FreePascal源代码(摘录自邮件询问)

    为了尝试编译FreePascal,我搜了官方文档,并给几位作者都发了邮件询问,目前结果如下: http://wiki.lazarus.freepascal.org/Getting_Lazarus#Co ...

  8. Latex 3: 解决LaTeX编译卡顿问题

    1.问题: 最近在编译latex时,老是在tulmr.fd处编译很久,但是以前不这样啊,那肯定就是我最近做了什么导致这样的了,是什么呢? 2.解决: 后来google下发现了解决办法,原来是我新安装了 ...

  9. js连等运算

    1.var a = b = 20; 连等的第二个变量属于全局变量2.a.x = a = {n:2}; 连等是从右往左执行的3.a.x = a = {n:2}; js语句执行前会保存之前的索引

  10. MongoDB相关的一些技术文章

    安装 win7下安装和配置MongoDB的总结---阿冬专栏