HDU 6143 Killer Names DP+快速密
Killer Names
>
> When Marek died in 2 BBY, shortly after the formation of the Alliance, Vader endeavored to recreate his disciple by utilizing the cloning technologies of the planet Kamino. The accelerated cloning process—an enhanced version of the Kaminoan method which allowed for a rapid growth rate within its subjects—was initially imperfect and many clones were too unstable to take Marek's place as the Dark Lord's new apprentice. After months of failure, one particular clone impressed Vader enough for him to hope that this version might become the first success. But as with the others, he inherited Marek's power and skills at the cost of receiving his emotions as well, a side effect of memory flashes used in the training process.
>
> — Wookieepedia
Darth Vader is finally able to stably clone the most powerful soilder in the galaxy: the Starkiller. It is the time of the final strike to destroy the Jedi remnants hidden in every corner of the galaxy.
However, as the clone army is growing, giving them names becomes a trouble. A clone of Starkiller will be given a two-word name, a first name and a last name. Both the first name and the last name have exactly n characters, while each character is chosen from an alphabet of size m. It appears that there are m2n possible names to be used.
Though the clone process succeeded, the moods of Starkiller clones seem not quite stable. Once an unsatisfactory name is given, a clone will become unstable and will try to fight against his own master. A name is safe if and only if no character appears in both the first name and the last name.
Since no two clones can share a name, Darth Vader would like to know the maximum number of clones he is able to create.
Each test case contains two integers n and m (1≤n,m≤2000).
Output the answer mod 109+7
3 2
2 3
18
#include<bits/stdc++.h>
using namespace std;
#define ls i<<1
#define rs ls | 1
#define mid ((ll+rr)>>1)
#define pii pair<int,int>
#define MP make_pair
typedef long long LL;
typedef unsigned long long ULL;
const long long INF = 1e18+1LL;
const double pi = acos(-1.0); const int N=+,M=1e6+,inf=; const LL MOD = 1e9 + 7LL; LL quick_pow(LL x,LL p) {
if(!p) return 1LL;
LL ans = quick_pow(x,p>>);
ans = ans*ans%MOD;
if(p & ) ans = ans*x%MOD;
return ans;
} LL dp[N][N],ans,fn[N],fn1[N];
int n,m;
void init() { for(int i = ; i <= m; ++i) fn[i] = quick_pow(i,n) % MOD;
fn[] = ;
memset(dp,,sizeof(dp));
dp[][] = 1LL;
for(int i = ; i < n; ++i) {
for(int j = ; j <= i; ++j) { if(m>=j)dp[i+][j+] += dp[i][j] * (m - j) % MOD;
dp[i+][j] += dp[i][j]*j%MOD;
dp[i+][j+] %= MOD;
dp[i+][j] %= MOD;
}
}
for(int j = ; j <= n; ++j){
if(m>j)ans = (ans + (dp[n][j] * fn[m-j])%MOD)%MOD;
}
}
int main() {
int T;
scanf("%d",&T);
while(T--) {
scanf("%d%d",&n,&m);
ans = ;
init();
printf("%lld\n",ans);
}
return ;
}
HDU 6143 Killer Names DP+快速密的更多相关文章
- HDU 6143 - Killer Names | 2017 Multi-University Training Contest 8
/* HDU 6143 - Killer Names [ DP ] | 2017 Multi-University Training Contest 8 题意: m个字母组成两个长为n的序列,两序列中 ...
- 2017ACM暑期多校联合训练 - Team 8 1011 HDU 6143 Killer Names (容斥+排列组合,dp+整数快速幂)
题目链接 Problem Description Galen Marek, codenamed Starkiller, was a male Human apprentice of the Sith ...
- HDU 6143 Killer Names
Killer Names Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Tota ...
- HDU - 6143 Killer Names(dp记忆化搜索+组合数)
题意:从m种字母中选取字母组成姓名,要求姓和名中不能有相同的字母,姓和名的长度都为n,问能组成几种不同的姓名. 分析: 1.从m种字母中选取i种组成姓,剩下m-i种组成名. 2.i种字母组成长度为n的 ...
- HDU 6143 Killer Names(容斥原理)
http://acm.hdu.edu.cn/showproblem.php?pid=6143 题意: 用m个字母去取名字,名字分为前后两部分,各由n个字符组成,前后两部分不能出现相同字符,问合法的组成 ...
- 2017多校第8场 HDU 6143 Killer Names 容斥,组合计数
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6143 题意:m种颜色需要为两段长度为n的格子染色,且这两段之间不能出现相同的颜色,问总共有多少种情况. ...
- hdu 6143: Killer Names (2017 多校第八场 1011)
题目链接 题意,有m种颜色,给2n个位置染色,使左边n个和右边n个没有共同的颜色. 可以先递推求出恰用i种颜色染n个位置的方案数,然后枚举两边的染色数就可以了,代码很简单. #include<b ...
- HDU 6143 17多校8 Killer Names(组合数学)
题目传送:Killer Names Problem Description > Galen Marek, codenamed Starkiller, was a male Human appre ...
- hdu6143 Killer Names 容斥+排列组合
/** 题目:hdu6143 Killer Names 链接:http://acm.hdu.edu.cn/showproblem.php?pid=6143 题意:有m种字符(可以不用完),组成两个长度 ...
随机推荐
- 组合数学的卡特兰数 TOJ 3551: Game of Connections
这个就是卡特兰数的经典问题 直接用这个公式就好了,但是这个题涉及大数的处理h(n)=h(n-1)*(4*n-2)/(n+1) 其实见过好几次大数的处理了,有一次他存的恰好不多于30位,直接分成两部分l ...
- iOS学习笔记21-推送证书与秘钥申请
---恢复内容开始--- 一.iOS证书 iOS常用的证书包括开发证书和发布证书,无论是真机调试还是最终发布应用到App Store这两个证书都是必须的,它是iOS开发的基本证书.Xcode7以后真机 ...
- cf287D Shifting
John Doe has found the beautiful permutation formula. Let's take permutation p = p1, p2, ..., pn. Le ...
- day1之校花网小试牛刀
一 利用生成器来完成爬去校花网视频 import requests import re import os import hashlib import time DOWLOAD_PATH=r'D:\D ...
- UVa10214 Trees in a Wood.
先算第一象限能看到的树,答案乘以4就是四个象限的数的总数,再加上坐标轴上四棵树,就是总共能看到的树. 树的总数为(2*a+1)*(2*b+1)-1 ←矩形面积除去原点位置 设一棵树的坐标是(x,y) ...
- 【BZOJ2653】middle(主席树,二分)
题意:一个长度为n的序列a,设其排过序之后为b,其中位数定义为b[n/2],其中a,b从0开始标号,除法取下整. 给你一个长度为n的序列s. 回答Q个这样的询问:s的左端点在[a,b]之间,右端点在[ ...
- python中单引号,双引号,三引号的比较 转载
本文转载自http://blog.sina.com.cn/s/blog_6be8928401017lwy.html 先说1双引号与3个双引号的区别,双引号所表示的字 符串通常要写成一行 如: s1 = ...
- linux网络性能评估
Linux网络性能评估 参考自:自学it网,http://www.zixue.it/. 网络性能评估(1)通过ping命令检测网络的连通性.(2)通过netstat -i 组合检测网络接口状况.(3) ...
- go初识
for循环 ; i < ; i++ { fmt.Println(i*i) } ls := "agd" for _, arg := range ls{ fmt.Println( ...
- python练习之-计算器
学习以堆栈模式编写-计算器 堆栈特点:先进后出, 如下: #!/opt/python3/bin/python3 # Author: yong import re def is_symbol(eleme ...