A water problem

Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 774    Accepted Submission(s): 397

Problem Description

Two planets named Haha and Xixi in the universe and they were created with the universe beginning.

There is 73 days in Xixi a year and 137 days in Haha a year.

Now you know the days N after Big Bang, you need to answer whether it is the first day in a year about the two planets.

 

Input

There are several test cases(about 5 huge test cases).

For each test, we have a line with an only integer N(0≤N), the length of N is up to 10000000.

 

Output

For the i-th test case, output Case #i: , then output "YES" or "NO" for the answer.
 

Sample Input

10001
0
333
 

Sample Output

Case #1: YES
Case #2: YES
Case #3: NO
 
大数取模
 //2016.8.16
#include<cstdio>
#include<cstring> using namespace std; char s[]; int main()
{
long long n, m, pos;
int kase = , len;
while(scanf("%s", s)!=EOF)
{
pos = n = m = ;
len = strlen(s);
while(pos < len)
{
for(int i = ; i < && pos<len; i++, pos++)
{
n = n*+(s[pos]-'');
m = m*+(s[pos]-'');
}
n %= ;
m %= ;
}
if(!n&&!m)printf("Case #%d: YES\n", ++kase);
else printf("Case #%d: NO\n", ++kase);
} return ;
}
 

HDU5832的更多相关文章

  1. hdu5832 A water problem

    A water problem Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)T ...

  2. A water problem (hdu-5832)

    不多说就是一个数对两个数的乘积求模运算 不得不说vj上这个题的翻译版本真是太暴力了 难点 主要还是时间的控制,这题太容易TLE了.用到的算法就是大数求余数的ans=(ans*10-a[i]-'0')% ...

  3. HDU 5832A water problem

    大数 判断整除 /* *********************************************** Author :guanjun Created Time :2016/8/14 1 ...

随机推荐

  1. Android学习笔记之Broadcast Receiver

    可程序间通信 注册通信,注销通信,发送消息 package com.jiahemeikang.helloandroid; import com.jiahemikang.service.EchoServ ...

  2. PAT (Advanced Level) 1006. Sign In and Sign Out (25)

    简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> ...

  3. [iOS]C语言技术视频-05-程序循环结构(do{}while();)

    下载地址: 链接: http://pan.baidu.com/s/1c02ke3m 密码: x97w

  4. Java 内存回收机制 -说到点上了

    下面这个图,很清楚地说明对象在new的时候是怎样开辟内存空间的 其中对象new出来的,是栈内存,变量的开辟是堆内存 Java的一个重要优点就是通过垃圾收集器GC (Garbage Collection ...

  5. 【转】C/CPP之static

    静态变量作用范围在一个文件内,程序开始时分配空间,结束时释放空间,默认初始化为0,使用时可以改变其值. 静态变量或静态函数只有本文件内的代码才能访问它,它的名字在其它文件中不可见.用法1:函数内部声明 ...

  6. Nodejs的多线程

    转: http://snoopyxdy.blog.163.com/blog/static/60117440201349352443/

  7. 字符串处理,NSNumber转换

    more:http://www.superqq.com/blog/categories/ioskai-fa/ 1.判断字符串是否为空 if ([text lenght] == 0) {     //  ...

  8. composer 安装和修改中国镜像

    参考:http://docs.phpcomposer.com/00-intro.html#Using-Composer http://www.phpcomposer.com/ 下载安装 下载并且运行 ...

  9. spark中数据的读取与保存

    1.文本文件 (1)读取文本文件 JavaRDD<String> input =sc.textFile(dir) (2)保存文本文件 result.saveAsTextFile(dir)) ...

  10. IE6中让png的icon图标也透明的完整代码段

    一个引用了在IE6中让img图标也可引用png图片的js插件代码的html是这样写的,兼容IE6: <a class="btn btn-select" href=" ...