判断一棵树是否是红黑树,按题给条件建树,dfs判断即可~

#include<bits/stdc++.h>
using namespace std;
const int maxn=;
struct node {
int data;
node * left=NULL;
node * right=NULL;
};
void insert (node * &root,int x) {
if (root==NULL) {
root=new node;
root->data=x;
return;
}
if (abs(x)<abs(root->data)) insert (root->left,x);
else insert (root->right,x);
}
int getnum (node * root) {
if (root==NULL) return ;
if (root->data>)
return max(getnum(root->left),getnum(root->right))+;
else return max(getnum(root->left),getnum(root->right));
}
int flag=;
void dfs (node * root) {
if (root==NULL) return;
if (root->data<&&root->left&&root->left->data<) flag++;
if (root->data<&&root->right&&root->right->data<) flag++;
if (getnum(root->left)!=getnum(root->right)) flag++;
dfs (root->left);
dfs (root->right);
}
int main () {
int T;
scanf ("%d",&T);
int N,x;
while (T--) {
node * root=NULL;
scanf ("%d",&N);
for (int i=;i<N;i++) {
scanf ("%d",&x);
insert (root,x);
}
flag=;
if (root->data<) flag++;
dfs (root);
if (flag==) printf ("Yes\n");
else printf ("No\n");
}
return ;
}

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