Find Minimum in Rotated Sorted Array II

Follow up for "Find Minimum in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

The array may contain duplicates.

class Solution{
public:
    int findMin(vector<int>& nums){
        int size = nums.size();
        int left = ;
        int right = size - ;
        int mid;
        while(left < right){
            mid = (left + right)/;
            if(nums[mid] > nums[right])
                left = mid+;
            else if(nums[mid] < nums[right])
                right = mid;
            else
                right--;
        }
        return nums[left];
    }
};