暴力破解zip文件

 #coding=utf-8

 """
 用户输入-z参数指定要破解的zip文件，输入-d参数输入字典文件，即可暴力破解加密的zip文件
 """

 import optparse,zipfile,threading

 foundpassword = False   #当密码找到后，将此置为True，避免继续验证字典中的其它word,提高效率

 def extract_zipfile(a_zipfile,password):
    global foundpassword
    try:
       a_zipfile.extractall(pwd=password)  #若密码不对，会返回异常
       print('找到密码：',password.decode('utf-8'))
       foundpassword = True
    except:
       pass

 def main():
    usage = 'Usage: %prog -z <zipfile> -d <dictionaryfile>'
    parser = optparse.OptionParser(usage,version='v1.0')
    parser.add_option('-z',dest='zname',
                      help='待破解的zip文件')
    parser.add_option('-d',dest='dname',
                      help='指定字典文件')
    (options,args) = parser.parse_args()
    if options.zname == None or options.dname == None:
       print(parser.usage)
       exit(0)
    else:
       zname = options.zname
       dname = options.dname
    a_zipfile = zipfile.ZipFile(zname)
    dictFile = open(dname,'rb')
    for word in dictFile:
       password = word.strip(b'\r\n')
       t = threading.Thread(target=extract_zipfile,args=(a_zipfile,password))
       t.start()
       if foundpassword == True:
          exit(0)

 if __name__ == '__main__':
    main()
    

运行后的结果为：

 c:\Python34\python.exe CrackZipfile.py  -z e:\Archive.zip -d e:\dictionary.txt
 找到密码： 1q3e5t