Trie-648. Replace Words
In English, we have a concept called root, which can be followed by some other words to form another longer word - let's call this word successor. For example, the root an, followed by other, which can form another word another.
Now, given a dictionary consisting of many roots and a sentence. You need to replace all the successor in the sentence with the root forming it. If a successor has many roots can form it, replace it with the root with the shortest length.
You need to output the sentence after the replacement.
Example 1:
Input: dict = ["cat", "bat", "rat"]
sentence = "the cattle was rattled by the battery"
Output: "the cat was rat by the bat"
Note:
- The input will only have lower-case letters.
- 1 <= dict words number <= 1000
- 1 <= sentence words number <= 1000
- 1 <= root length <= 100
- 1 <= sentence words length <= 1000
class Solution {
public:
string replaceWords(vector<string>& dict, string sentence) {
set<string> myDict;
for(int i=;i<dict.size();i++)
myDict.insert(dict[i]);
vector<string> mySentence;
for(int i=,j=;i<sentence.size() && j<=sentence.size();j++)//把字符串分成单词
{
if(sentence[j]==' ' || j==sentence.size())
{
mySentence.push_back(sentence.substr(i,j-i));
i=j+;
}
}
string res="";
for(int i=;i<mySentence.size();i++)
{
for(int j=;j<mySentence[i].size();j++)
{
if(myDict.find(mySentence[i].substr(,j+)) != myDict.end())
{
mySentence[i]=mySentence[i].substr(,j+);
break;
}
}
res+=(mySentence[i]+" ");
}
return res.substr(,res.size()-);
}
};
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