Painting Fence

Painting Fence

Time Limit:1000MS     Memory Limit:524288KB     64bit IO Format:%I64d & %I64u

Submit Status

Description

Bizon the Champion isn't just attentive, he also is very hardworking.

Bizon the Champion decided to paint his old fence his favorite color, orange. The fence is represented as n vertical planks, put in a row. Adjacent planks have no gap between them. The planks are numbered from the left to the right starting from one, the i-th plank has the width of 1 meter and the height of a_i meters.

Bizon the Champion bought a brush in the shop, the brush's width is 1 meter. He can make vertical and horizontal strokes with the brush. During a stroke the brush's full surface must touch the fence at all the time (see the samples for the better understanding). What minimum number of strokes should Bizon the Champion do to fully paint the fence? Note that you are allowed to paint the same area of the fence multiple times.

Input

The first line contains integer n(1 ≤ n ≤ 5000) — the number of fence planks. The second line contains n space-separated integersa₁, a₂, ..., a_n(1 ≤ a_i ≤ 10⁹).

Output

Print a single integer — the minimum number of strokes needed to paint the whole fence.

Sample Input

Input

5
2 2 1 2 1

Output

3

Input

2
2 2

Output

2

Input

1
5

Output

1

#include<cstdio>
#include<algorithm>
using namespace std;
const int MAXN = ;
int a[MAXN];
int solve(int l, int r)
{
    int k = l;
    if(l > r) return ;
    for(int i = l; i <= r; i++)
        if(a[i] < a[k])
            k = i;
    int tmp = a[k];
    for(int i = l; i <= r; i++)
        a[i] -= tmp;
    return min(r-l+, solve(l, k-) + solve(k+, r) + tmp);
}
int main()
{
    int n;
    scanf("%d",&n);
    for(int i = ; i < n; i++)
        scanf("%d",&a[i]);
    printf("%d\n", solve(, n-));
    return ;
}  

递归，每次做的到操作都是比较全部横着涂完和全部竖着涂完的涂刷到次数较小的次数，递归出答案。