hdu-1012-u Calculate e(水题)

 #include <iostream>
 using namespace std;
 int main() {
     int jiecheng[];
     jiecheng[] = jiecheng[] = ;
     for (int i=; i<; i++) {
         jiecheng[i] = jiecheng[i-] * i;
     }
     printf("n e\n");
     printf("- -----------\n");
     printf("0 1\n");
     printf("1 2\n");
     printf("2 2.5\n");
     double num[];
     num[] = 2.5;
     for (int i=; i<; i++) {
         num[i] = 1.0/jiecheng[i] + num[i-];
         printf("%d %.9lf\n", i,num[i]);
     }
     return ;
 }