2018/3/2晚11点30分写的程序(C++)
程序目标:输入一个字符串,竖向输出该字符串。使用string和动态分配内存机制。代码如下:
#include<iostream>
#include "stdafx.h"
#include<cstring>
int main()
{
using namespace std;
string s= cin.getline;
char * a = new char[sizeof(s)];
for (int m = 0;m < sizeof(s);m++)
a[m] = s[m];
for (int n = 0;n < sizeof(s);n++)
cout << a[n] << endl;
delete[] a;
cin.get();
cin.get();
return 0;
}
编译器:Visual Studio 2015
显示编译错误,但是不知道怎么修改。先记录在这。希望大神不吝赐教。
错误信息:
严重性 代码 说明 项目 文件 行 禁止显示状态
错误 C2146 语法错误: 缺少“;”(在标识符“s”的前面) MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 10
错误 C2065 “s”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 10
错误 C2065 “cin”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 10
错误 C2228 “.getline”的左边必须有类/结构/联合 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 10
错误 C2065 “s”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 11
错误 C2065 “s”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 12
错误 C2065 “s”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 13
错误 C2065 “s”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 14
错误 C2065 “cout”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 15
错误 C2065 “endl”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 15
错误 C2065 “cin”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 17
错误 C2228 “.get”的左边必须有类/结构/联合 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 17
错误 C2065 “cin”: 未声明的标识符 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 18
错误 C2228 “.get”的左边必须有类/结构/联合 MyProject_001 c:\users\administrator\documents\visual studio 2015\projects\myproject_01\myproject_001\myproject_001\myproject_001.cpp 18
####希望用一个错误来开始我的博客园之旅,只有不停的纠错,才能提高####
2018/3/2晚11点30分写的程序(C++)的更多相关文章
- 大一C语言学习笔记(11)---编程篇--写一个程序,可以获取从键盘上输入的的三个数,并能够判断是否可以以这三个数字作为边长来构成一个三角形,如果可以的话,输出此三角形的周长及面积,要求 0 bug;
考核内容: 写一个程序,可以获取从键盘上输入的的三个数,并能够判断是否可以以这三个数字作为边长来构成一个三角形,如果可以的话,输出此三角形的周长及面积: 答案: #include<stdio.h ...
- PTA 07-图5 Saving James Bond - Hard Version (30分)
07-图5 Saving James Bond - Hard Version (30分) This time let us consider the situation in the movie ...
- PAT A1127 ZigZagging on a Tree (30 分)——二叉树,建树,层序遍历
Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can ...
- 1127 ZigZagging on a Tree (30 分)
1127 ZigZagging on a Tree (30 分) Suppose that all the keys in a binary tree are distinct positive in ...
- 【PAT】1053 Path of Equal Weight(30 分)
1053 Path of Equal Weight(30 分) Given a non-empty tree with root R, and with weight Wi assigned t ...
- 1053 Path of Equal Weight (30 分)
Given a non-empty tree with root R, and with weight Wi assigned to each tree node Ti. The weig ...
- pta5-9 Huffman Codes (30分)
5-9 Huffman Codes (30分) In 1953, David A. Huffman published his paper "A Method for the Const ...
- A1095 Cars on Campus (30)(30 分)
A1095 Cars on Campus (30)(30 分) Zhejiang University has 6 campuses and a lot of gates. From each gat ...
- PTA 11-散列4 Hard Version (30分)
题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/680 5-18 Hashing - Hard Version (30分) Given ...
随机推荐
- javabean内省
何为JavaBean? JavaBean 是一种JAVA语言写成的可重用组件.为写成JavaBean,类必须是具体的和公共的,并且具有无参数的构造器.JavaBean 通过提供符合一致性设计模式的公共 ...
- linkin大话数据结构--Collection和Iterator
linkin大话数据结构--Collection和Iterator Java 集合就像一种容器,可以把多个对象的引用放入容器中.Java 集合类可以用于存储数量不等的多个对象,还可用于保存具有映射关系 ...
- How to get started with GIT and work with GIT Remote Repo
https://www.ntu.edu.sg/home/ehchua/programming/howto/Git_HowTo.html#zz-7. 1. Introduction GIT is a ...
- 2. getline()和get()
1.面向行输入:getline() ---其实还可以接受第三个参数. getline()函数读取整行,调用该方法 使用cin.getline().该函数有两个参数, 第一个参数是是用来存储输入行的数组 ...
- Java并发系列[4]----AbstractQueuedSynchronizer源码分析之条件队列
通过前面三篇的分析,我们深入了解了AbstractQueuedSynchronizer的内部结构和一些设计理念,知道了AbstractQueuedSynchronizer内部维护了一个同步状态和两个排 ...
- rabbitmq的构架和原理(三)
前面两篇博文已经将环境安装和相关配置介绍了,现在开始正式学习rabbitmq的使用了: rabbitMQ的构架 rabbitmq作为消息队列,一条消息从发布到订阅消费的完整流程为: 消息 --> ...
- 正则匹配url中的query参数信息
var url = 'name=xiaoming&age=10&school=xinhua'; var reg = /([^&=]+)=?([^&]*)/g;
- echarts中视觉映射器(visualMap)与时间轴(timeline)混用的实现方法
1.简述 echarts中的 timeline 组件,提供了在多个 ECharts option 间进行切换.播放等操作的功能. 与其他组件些不同,它需要操作『多个option』. 所以除了基准的ba ...
- “字符串替换” 和 “模板设置” (application/config.php)
//视图输出字符串内容替换'view_replace_str' => [ '__PUBLIC__' => '/public/', '__ROOT__' => '/',], 模板设置: ...
- 吴恩达深度学习笔记(deeplearning.ai)之卷积神经网络(一)
Padding 在卷积操作中,过滤器(又称核)的大小通常为奇数,如3x3,5x5.这样的好处有两点: 在特征图(二维卷积)中就会存在一个中心像素点.有一个中心像素点会十分方便,便于指出过滤器的位置. ...