[LeetCode] Line Reflection 直线对称
Given n points on a 2D plane, find if there is such a line parallel to y-axis that reflect the given points.
Example 1:
Input: [[1,1],[-1,1]]
Output: true
Example 2:
Input: [[1,1],[-1,-1]]
Output: false
Follow up:
Could you do better than O(n2) ?
Hint:
- Find the smallest and largest x-value for all points.
- If there is a line then it should be at y = (minX + maxX) / 2.
- For each point, make sure that it has a reflected point in the opposite side.
Credits:
Special thanks to @memoryless for adding this problem and creating all test cases.
这道题给了我们一堆点,问我们存不存在一条平行于y轴的直线,使得所有的点关于该直线对称。题目中的提示给的相当充分,我们只要按照提示的步骤来做就可以解题了。首先我们找到所有点的横坐标的最大值和最小值,那么二者的平均值就是中间直线的横坐标,然后我们遍历每个点,如果都能找到直线对称的另一个点,则返回true,反之返回false,参见代码如下:
解法一:
class Solution {
public:
bool isReflected(vector<pair<int, int>>& points) {
unordered_map<int, set<int>> m;
int mx = INT_MIN, mn = INT_MAX;
for (auto a : points) {
mx = max(mx, a.first);
mn = min(mn, a.first);
m[a.first].insert(a.second);
}
double y = (double)(mx + mn) / ;
for (auto a : points) {
int t = * y - a.first;
if (!m.count(t) || !m[t].count(a.second)) {
return false;
}
}
return true;
}
};
下面这种解法没有求最大值和最小值,而是把所有的横坐标累加起来,然后求平均数,基本思路都相同,参见代码如下:
解法二:
class Solution {
public:
bool isReflected(vector<pair<int, int>>& points) {
if (points.empty()) return true;
set<pair<int, int>> pts;
double y = ;
for (auto a : points) {
pts.insert(a);
y += a.first;
}
y /= points.size();
for (auto a : pts) {
if (!pts.count({y * - a.first, a.second})) {
return false;
}
}
return true;
}
};
类似题目:
参考资料:
https://leetcode.com/problems/line-reflection/description/
https://leetcode.com/discuss/107661/48-ms-short-c-solution
https://leetcode.com/discuss/107761/group-by-y-then-sort-by-x-17ms
LeetCode All in One 题目讲解汇总(持续更新中...)
[LeetCode] Line Reflection 直线对称的更多相关文章
- Leetcode: Line Reflection
Given n points on a 2D plane, find if there is such a line parallel to y-axis that reflect the given ...
- HDU 2671 Can't be easier(数学题,点关于直线对称)
题目 //数学题//直线 y = k * x + b//直线 ax+by+c=0; 点 (x0,y0); 点到直线距离 d = (ax0+by0+c)/sqrt(a^2+b^2) /********* ...
- LeetCode 5 最长对称串
LeetCode 5 最长对称串 最早时候做这道题的时候还是用Java写的,用的是字符串匹配的思路,一直Time Limit Exceeded.甚至还想过用KMP开优化子串查找. public cla ...
- Leetcode:面试题28. 对称的二叉树
Leetcode:面试题28. 对称的二叉树 Leetcode:面试题28. 对称的二叉树 Talk is cheap . Show me the code . /** * Definition fo ...
- [Swift]LeetCode356. 直线对称 $ Line Reflection
Given n points on a 2D plane, find if there is such a line parallel to y-axis that reflect the given ...
- Line Reflection -- LeetCode
Given n points on a 2D plane, find if there is such a line parallel to y-axis that reflect the given ...
- [LeetCode] Strobogrammatic Number III 对称数之三
A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside ...
- [LeetCode] Strobogrammatic Number II 对称数之二
A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside ...
- [CareerCup] 7.3 Line Intersection 直线相交
7.3 Given two lines on a Cartesian plane, determine whether the two lines would intersect. 这道题说是在笛卡尔 ...
随机推荐
- External Configuration Store Pattern 外部配置存储模式
Move configuration information out of the application deployment package to a centralized location. ...
- Javascript本地存储小结
前言 总括:详细讲述Cookie,LocalStorge,SesstionStorge的区别和用法. 人生如画,岁月如歌. 原文博客地址:Javascript本地存储小结 知乎专栏&& ...
- scikit-learn一般实例之六:构建评估器之前进行缺失值填充
本例将会展示对确实值进行填充能比简单的对样例中缺失值进行简单的丢弃能获得更好的结果.填充不一定能提升预测精度,所以请通过交叉验证进行检验.有时删除有缺失值的记录或使用标记符号会更有效. 缺失值可以被替 ...
- Win10 UWP系列:关于错误 0x80073CF9及一个小bug的解决
最近一直在开发XX的uwp版本,也是边摸索边做,最近遇到几个比较奇怪的问题,记录于此. 1.项目可用部署到PC,但无法部署到手机,提示以下错误: 错误 : DEP0001 : 意外错误: Instal ...
- c#面向对象基础技能——学习笔记(三)基于OOP思想研究对象的【方法】
实例方法:(解决问题的步骤)完成某功能的各种语句的组合 编写方法要考虑的内容: 1.通过项目需求,确定各方法的任务.功能: 2.方法的可访问性(默认是private):(字段private 属性int ...
- MahApps.Metro使用
# MahApps.Metro使用 # ## 下载MahApps.Metro ## PM> Install-Package MahApps.Metro ## MainWindow.xaml中添加 ...
- axis2+spring集成
转载自:http://www.cnblogs.com/linjiqin/archive/2011/07/05/2098316.html 1.新建一个web project项目,最终工程目录如下: 注意 ...
- CString转换为LPSTR和LPSTR转化为CString
一.CString转换为LPSTR 方法一: CString strFileName LPSTR lpstr - strFileName.GetBuffer(); strFileName.Releas ...
- linux之cp/scp命令+scp命令详解
名称:cp 使用权限:所有使用者 使用方式: cp [options] source dest cp [options] source... directory 说明:将一个档案拷贝至另一档案,或将数 ...
- Struts2入门(七)——Struts2的文件上传和下载
一.前言 在之前的随笔之中,我们已经了解Java通过上传组件来实现上传和下载,这次我们来了解Struts2的上传和下载. 注意:文件上传时,我们需要将表单提交方式设置为"POST" ...