Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.

The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.

One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.

The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."

Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!

Input Specification:

The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.

The last test case is followed by a line containing:

0 0

Output Specification:

For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:

Loowater is doomed!

Sample Input:

2 3
5
4
7
8
4
2 1
5
5
10
0 0

Output for Sample Input:

11
Loowater is doomed! 题目大意:输入n,m表示有n个头和m个勇士,接下来n个头的战斗力,m歌骑士的战斗力。规定一个骑士只能杀掉一个战斗力不大于其自身战斗力的头,同时要支付给他与战斗力等值的金币,问花费最少为多少,不能杀掉就显示样例2的输出。 解题思路:贪心,头和骑士能力从小到大排序,一个一个砍,不能砍掉当前头的骑士就不要。
 #include<iostream>
#include<algorithm>
using namespace std;
int main(){
int n,m;
int heard[],power[];
while(cin>>n>>m){
if(n== && m==)return ;
for(int i=;i<n;i++)cin>>heard[i];
for(int j=;j<m;j++)cin>>power[j];
sort(heard,heard+n);
sort(power,power+m);
int cur=;
int cost=;
for(int i=;i<m;i++){//从小到大一个一个来砍,不能砍下当前的就不砍
if(power[i]>=heard[cur]){
cost+=power[i];
if(++cur == n)break;
}
}
if(cur<n)cout<<"Loowater is doomed!\n";
else cout<<cost<<'\n';
}return ;
}
												

[ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]的更多相关文章

  1. UVA 11292 Dragon of Loowater(简单贪心)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  2. uva 11292 Dragon of Loowater (勇者斗恶龙)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  3. [ACM_水题] UVA 12502 Three Families [2人干3人的活后分钱,水]

      Three Families  Three families share a garden. They usually clean the garden together at the end o ...

  4. UVa 11292 Dragon of Loowater (水题,排序)

    题意:有n个条龙,在雇佣勇士去杀,每个勇士能力值为x,只能杀死头的直径y小于或等于自己能力值的龙,只能被雇佣一次,并且你要给x赏金,求最少的赏金. 析:很简单么,很明显,能力值高的杀直径大的,低的杀直 ...

  5. UVa 11292 - Dragon of Loowater(排序贪心)

    Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shore ...

  6. UVa 11292 Dragon of Loowater

    简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> ...

  7. UVA - 11292 Dragon of Loowater 贪心

    贪心策略:一个直径为X的头颅,应该让雇佣费用满足大于等于X且最小的骑士来砍掉,这样才能使得花费最少. AC代码 #include <cstdio> #include <cmath&g ...

  8. [ACM_水题] UVA 11729 Commando War [不可同时交代任务 可同时执行 最短完成全部时间 贪心]

    There is a war and it doesn't look very promising for your country. Now it's time to act. You have a ...

  9. UVA它11292 - Dragon of Loowater

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

随机推荐

  1. DHCP服务器的开始方式

    方法一:采用DHCP服务器接口开启的方式 [Huawei]dhcp enable [Huawei]int g0/0/0[Huawei-GigabitEthernet0/0/0]ip add 192.1 ...

  2. [2015hdu多校联赛补题]hdu5297 Y sequence

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5297 题意:给你一个所有正整数的序列,然后去掉满足x^(2~r)的所有数(x为所有正整数,r>= ...

  3. decimalFormat("#","##0.00") java

    importjava.text.DecimalFormat; publicclassTestNumberFormat{ publicstaticvoidmain(String[]args){ doub ...

  4. javascript 按ctrl和enter键提交表单

    <!DOCTYPE html><html lang="en"><head>    <meta charset="UTF-8&qu ...

  5. JS控制鼠标点击事件

    鼠标点击事件就是当鼠标点击元素时,就会出现另一个窗口,类似于百度首页中右上角的“登录”这个按钮,当鼠标点击 登录时,就会出现登录窗口.大体的意思就是这样,直接上代码了,简单易懂. <!DOCTY ...

  6. 【golang】go语言,进行并发请求的wrap变参封装

    package main import ( "fmt" "sync" "time" ) type WaitGroupWrapper stru ...

  7. db2 进程

    DB2 通用数据库进程全接触 Dwaine Snow, DB2 UDB 和 Informix IDS 产品经理, IBM 多伦多实验室 Dwaine Snow 是 DB2 UDB 分区数据库以及查询巡 ...

  8. POJ2309 -- BST

    找找规律,实际上是二分查找的过程,只要找到了mid与输入的n相同的话,直接输出left和right就可以了. 代码如下: #include <iostream> using namespa ...

  9. 一个自己用的代码备份工具,支持delphi,android,java,可以自己添加配置,灵活支持大部分编程语言

    下面就是这个软件的下载地址 http://files.cnblogs.com/files/stevenlaz/release.zip 绿色软件 MConfig.exe 进行安装,或者卸载 MBacku ...

  10. PyMongo下载及安装

    PyMongo最新版本下载地址: http://pypi.python.org/pypi/pymongo/#downloads PyMongo旧版本下载地址: http://pypi.python.o ...