Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.

The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.

One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.

The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."

Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!

Input Specification:

The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.

The last test case is followed by a line containing:

0 0

Output Specification:

For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:

Loowater is doomed!

Sample Input:

2 3
5
4
7
8
4
2 1
5
5
10
0 0

Output for Sample Input:

11
Loowater is doomed! 题目大意:输入n,m表示有n个头和m个勇士,接下来n个头的战斗力,m歌骑士的战斗力。规定一个骑士只能杀掉一个战斗力不大于其自身战斗力的头,同时要支付给他与战斗力等值的金币,问花费最少为多少,不能杀掉就显示样例2的输出。 解题思路:贪心,头和骑士能力从小到大排序,一个一个砍,不能砍掉当前头的骑士就不要。
 #include<iostream>
#include<algorithm>
using namespace std;
int main(){
int n,m;
int heard[],power[];
while(cin>>n>>m){
if(n== && m==)return ;
for(int i=;i<n;i++)cin>>heard[i];
for(int j=;j<m;j++)cin>>power[j];
sort(heard,heard+n);
sort(power,power+m);
int cur=;
int cost=;
for(int i=;i<m;i++){//从小到大一个一个来砍,不能砍下当前的就不砍
if(power[i]>=heard[cur]){
cost+=power[i];
if(++cur == n)break;
}
}
if(cur<n)cout<<"Loowater is doomed!\n";
else cout<<cost<<'\n';
}return ;
}
												

[ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]的更多相关文章

  1. UVA 11292 Dragon of Loowater(简单贪心)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  2. uva 11292 Dragon of Loowater (勇者斗恶龙)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  3. [ACM_水题] UVA 12502 Three Families [2人干3人的活后分钱,水]

      Three Families  Three families share a garden. They usually clean the garden together at the end o ...

  4. UVa 11292 Dragon of Loowater (水题,排序)

    题意:有n个条龙,在雇佣勇士去杀,每个勇士能力值为x,只能杀死头的直径y小于或等于自己能力值的龙,只能被雇佣一次,并且你要给x赏金,求最少的赏金. 析:很简单么,很明显,能力值高的杀直径大的,低的杀直 ...

  5. UVa 11292 - Dragon of Loowater(排序贪心)

    Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shore ...

  6. UVa 11292 Dragon of Loowater

    简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> ...

  7. UVA - 11292 Dragon of Loowater 贪心

    贪心策略:一个直径为X的头颅,应该让雇佣费用满足大于等于X且最小的骑士来砍掉,这样才能使得花费最少. AC代码 #include <cstdio> #include <cmath&g ...

  8. [ACM_水题] UVA 11729 Commando War [不可同时交代任务 可同时执行 最短完成全部时间 贪心]

    There is a war and it doesn't look very promising for your country. Now it's time to act. You have a ...

  9. UVA它11292 - Dragon of Loowater

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

随机推荐

  1. phpunit.xml

    <phpunit bootstrap="vendor/autoload.php"> <testsuites> <testsuite name=&quo ...

  2. 一个很酷的加载loading效果--IT蓝豹

    一个很酷的加载loading效果,自定义LeafLoadingView实现,LeafLoadingView继承view, 本例子主要由以下几点构成 (1):RotateAnimation实现叶子旋转 ...

  3. C++中 容易忽视的const 修饰符

    C++可以用const定义常量,也可以用#define定义常量,但是前者比后者有更多的有点: (1)const常量有数据类型,而宏常量没有数据类型.编译器可以对const进行类型安全检查,而后者只进行 ...

  4. MongoDB中的连接池

    参见 http://www.cnblogs.com/huangfox/archive/2012/04/01/2428947.html

  5. SCI写作经验交流,别人的经验借鉴下,很有用的!

    http://www.dxy.cn/bbs/topic/27127771 语言是非英语国家论文的最大障碍.首先是时态和语态:在前言和讨论里,描述该研究的过去历史和现状时,要使用相应的时态:过去就使用过 ...

  6. 重置mysql数据库密码相关方法

    方法一: 在my.ini的[mysqld]字段加入:skip-grant-tables重启mysql服务,这时的mysql不需要密码即可登录数据库 然后进入mysqlmysql>use mysq ...

  7. Unity(三)依赖注入

    Unity具体实现依赖注入包含.属性注入.方法注入. 构造函数注入 public void ConStructorCodeTest1() { //默认注册(无命名),如果后面还有默认注册会覆盖前面的 ...

  8. 在ASP.NET中引用自定义提示框

    在html网页中自定义提示框 正文: 在一般的B/S架构中项目,与用户的交互信息是非常重要的.在一般的情况下,设计人员都在把用户信息呈现在html中,用div和span去弹出相关信息.对于一般的情况而 ...

  9. 在updatepanel使用colorbox无效

    今天在给一个使用colorbox的页面加了一个updatepanel后,colorbox无效了,原因是以前的页面初始化colorbox是用 $(document).ready(function(){ ...

  10. js 页面值变动监听

    1.初始化值map对象 var compareMap = {}:// 定义全局变量 function initCompareMap(context){//context 为指定要初始化的区域,即上下文 ...