Problem description

Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence ai. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.

Help Kefa cope with this task!

Input

The first line contains integer n (1 ≤ n ≤ 105).

The second line contains n integers a1,  a2,  ...,  an (1 ≤ ai ≤ 109).

Output

Print a single integer — the length of the maximum non-decreasing subsegment of sequence a.

Examples

Input

6
2 2 1 3 4 1

Output

3

Input

3
2 2 9

Output

3

Note

In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.

In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one.

解题思路:求最大非递减序列的长度,注意maxlen初始值为1,水过!

AC代码:

 #include<bits/stdc++.h>
using namespace std;
int n,len=,maxlen=,a[];
int main(){
cin>>n;
for(int i=;i<n;++i)cin>>a[i];
for(int i=;i<n;++i){
if(a[i]>=a[i-])len++;
else len=;
maxlen=max(maxlen,len);
}
cout<<maxlen<<endl;
return ;
}

A - Kefa and First Steps的更多相关文章

  1. Codeforces Round #321 (Div. 2) A. Kefa and First Steps 水题

    A. Kefa and First Steps Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/58 ...

  2. Codeforces 580A - Kefa and First Steps

    580A - Kefa and First Steps 思路:dp dp[i]表示包括前i个元素中a[i]在内的最大增序列. 代码: #include<bits/stdc++.h> usi ...

  3. Codeforces Round #321 (Div. 2) A. Kefa and First Steps【暴力/dp/最长不递减子序列】

    A. Kefa and First Steps time limit per test 2 seconds memory limit per test 256 megabytes input stan ...

  4. Codeforces Round #321 (Div. 2)-A. Kefa and First Steps,暴力水过~~

    A. Kefa and First Steps time limit per test 2 seconds memory limit per test 256 megabytes input stan ...

  5. codeforces水题100道 第十四题 Codeforces Round #321 (Div. 2) A. Kefa and First Steps (brute force)

    题目链接:http://www.codeforces.com/problemset/problem/580/A题意:求最长连续非降子序列的长度.C++代码: #include <iostream ...

  6. Codeforces Round #321 (Div. 2) Kefa and First Steps 模拟

    原题连接:http://codeforces.com/contest/580/problem/A 题意: 给你一个序列,问你最长不降子串是多长? 题解: 直接模拟就好了 代码: #include< ...

  7. Codeforces Round #321 (Div. 2) A, B, C, D, E

    580A. Kefa and First Steps 题目链接: A. Kefa and First Steps 题意描述: 给出一个序列,求最长不降连续子序列多长? 解题思路: 水题,签到 代码: ...

  8. Codeforces Round #321 (Div. 2)

    水 A - Kefa and First Steps /************************************************ * Author :Running_Time ...

  9. animation-timing-function: steps() 详解

    在应用 CSS3 渐变/动画时,有个控制时间的属性 <animation-timing-function> .它的取值中除了常用到的 贝萨尔曲线以外,还有个让人比较困惑的 steps()  ...

随机推荐

  1. 使用脚本卸载.net framework for mac

    官方只提供了安装包,没提供卸载

  2. Shell 环境变量也是变量

    跟定义普通变量一样,语法是 变量名=值,只不过这个名字叫 PATH,值是路径 shell PATH=/usr/local/python-2.7.6/bin 导入的话使用export命令 shell e ...

  3. Linux 之WinSCP连接FTP

    1.安装vsftpd 2.ftp命令 /sbin/service vsftpd start /sbin/service vsftpd restart /sbin/service vsftpd stop ...

  4. Can't find variable: SockJS vue项目

    用的vue-cli(webpack-simple模板),在开发环境运行(npm run dev),一直都没有问题,突然在ios的safari中调试,出现报错:Can't find variable: ...

  5. 【转】上拉下拉电阻、I/O输出(开漏、推挽等)

    作者:BakerZhang 链接:https://www.jianshu.com/p/3ac3a29b0f58来源:简书 感谢! ——————————————————————————————————— ...

  6. 后台导出大量数据超时报 nginx404错误

    使用nginx服务器如果遇到timeou情况时可以如下设置参数,使用fastcgi:    fastcgi_connect_timeout 75;  链接          fastcgi_read_ ...

  7. 深度遍历DFS

    目录: https://zhipianxuan.github.io/ 一.树的DFS 二.二维矩阵的DFS 三.图的DFS 一.题目一:二维矩阵(输出所有路径数) 思路:从起点开始,DFS,直到走到终 ...

  8. 虚拟机pycharm

    一.进入虚拟机Ubuntu软件查找pycharm专业版进行安装 二.进入https://www.jetbrains.com/pycharm/download/#section=linux 下载Linu ...

  9. Emacs学习笔记之主模式笔记

    % 模式相关—————————————————————————— 这里经常用的也就各种语言相对应的模式,有些就没再写进去,比如f90等模式 Fundamental mode 基本模式         ...

  10. phpstorm zhuce ma

    username :cf96PiPYt271u1TC License Key : 97807-12042010 00001GctOKh8f206hliugiW6iAS5bh 8AAXfEtfpdDSr ...