java.util.ConcurrentModificationException is a very common exception when working with java collection classes. Java Collection classes are fail-fast, which means if the Collection will be changed while some thread is traversing over it using iterator, the iterator.next() will throw ConcurrentModificationException. Concurrent modification exception can come in case of multithreaded as well as single threaded java programming environment.

java.util.ConcurrentModificationException

Let’s see the concurrent modification exception scenario with an example.


Copy
package com.journaldev.ConcurrentModificationException; import java.util.ArrayList;

import java.util.HashMap;

import java.util.Iterator;

import java.util.List;

import java.util.Map; public class ConcurrentModificationExceptionExample {
<span class="hljs-function"><span class="hljs-keyword">public</span> <span class="hljs-keyword">static</span> <span class="hljs-keyword">void</span> <span class="hljs-title">main</span>(<span class="hljs-params">String args[]</span>) </span>{
List&lt;String&gt; myList = <span class="hljs-keyword">new</span> ArrayList&lt;String&gt;(); myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"1"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"2"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"3"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"4"</span>);
myList.<span class="hljs-keyword">add</span>(<span class="hljs-string">"5"</span>); Iterator&lt;String&gt; it = myList.iterator();
<span class="hljs-keyword">while</span> (it.hasNext()) {
String <span class="hljs-keyword">value</span> = it.next();
System.<span class="hljs-keyword">out</span>.println(<span class="hljs-string">"List Value:"</span> + <span class="hljs-keyword">value</span>);
<span class="hljs-keyword">if</span> (<span class="hljs-keyword">value</span>.<span class="hljs-keyword">equals</span>(<span class="hljs-string">"3"</span>))
myList.<span class="hljs-keyword">remove</span>(<span class="hljs-keyword">value</span>);
} Map&lt;String, String&gt; myMap = <span class="hljs-keyword">new</span> HashMap&lt;String, String&gt;();
myMap.put(<span class="hljs-string">"1"</span>, <span class="hljs-string">"1"</span>);
myMap.put(<span class="hljs-string">"2"</span>, <span class="hljs-string">"2"</span>);
myMap.put(<span class="hljs-string">"3"</span>, <span class="hljs-string">"3"</span>); Iterator&lt;String&gt; it1 = myMap.keySet().iterator();
<span class="hljs-keyword">while</span> (it1.hasNext()) {
String key = it1.next();
System.<span class="hljs-keyword">out</span>.println(<span class="hljs-string">"Map Value:"</span> + myMap.<span class="hljs-keyword">get</span>(key));
<span class="hljs-keyword">if</span> (key.<span class="hljs-keyword">equals</span>(<span class="hljs-string">"2"</span>)) {
myMap.put(<span class="hljs-string">"1"</span>, <span class="hljs-string">"4"</span>);
<span class="hljs-comment">// myMap.put("4", "4");</span>
}
} }

}

Above program will throw java.util.ConcurrentModificationException when executed, as shown in below console logs.


Copy
List Value:1
List Value:2
List Value:3
Exception in thread "main" java.util.ConcurrentModificationException
at java.base/java.util.ArrayList$Itr.checkForComodification(ArrayList.java:937)
at java.base/java.util.ArrayList$Itr.next(ArrayList.java:891)
at com.journaldev.ConcurrentModificationException.ConcurrentModificationExceptionExample.main(ConcurrentModificationExceptionExample.java:22)

From the output stack trace, its clear that the concurrent modification exception is coming when we call iterator next() function. If you are wondering how Iterator checks for the modification, its implementation is present in AbstractList class where an int variable modCount is defined. modCount provides the number of times list size has been changed. modCount value is used in every next() call to check for any modifications in a function checkForComodification().

Now comment the list part and run the program again. You will see that there is no ConcurrentModificationException being thrown now.

Output will be:


Copy
Map Value:3
Map Value:2
Map Value:4

Since we are updating the existing key value in the myMap, its size has not been changed and we are not getting ConcurrentModificationException. Note that the output may differ in your system because HashMap keyset is not ordered like list. If you will uncomment the statement where I am adding a new key-value in the HashMap, it will cause ConcurrentModificationException.

To Avoid ConcurrentModificationException in multi-threaded environment

  1. You can convert the list to an array and then iterate on the array. This approach works well for small or medium size list but if the list is large then it will affect the performance a lot.
  2. You can lock the list while iterating by putting it in a synchronized block. This approach is not recommended because it will cease the benefits of multithreading.
  3. If you are using JDK1.5 or higher then you can use ConcurrentHashMap and CopyOnWriteArrayList classes. This is the recommended approach to avoid concurrent modification exception.

To Avoid ConcurrentModificationException in single-threaded environment

You can use the iterator remove() function to remove the object from underlying collection object. But in this case you can remove the same object and not any other object from the list.

Let us run an example using Concurrent Collection classes:


Copy
package com.journaldev.ConcurrentModificationException; import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.concurrent.ConcurrentHashMap;
import java.util.concurrent.CopyOnWriteArrayList; public class AvoidConcurrentModificationException { public static void main(String[] args) { List<String> myList = new CopyOnWriteArrayList<String>(); myList.add("1");
myList.add("2");
myList.add("3");
myList.add("4");
myList.add("5"); Iterator<String> it = myList.iterator();
while (it.hasNext()) {
String value = it.next();
System.out.println("List Value:" + value);
if (value.equals("3")) {
myList.remove("4");
myList.add("6");
myList.add("7");
}
}
System.out.println("List Size:" + myList.size()); Map<String, String> myMap = new ConcurrentHashMap<String, String>();
myMap.put("1", "1");
myMap.put("2", "2");
myMap.put("3", "3"); Iterator<String> it1 = myMap.keySet().iterator();
while (it1.hasNext()) {
String key = it1.next();
System.out.println("Map Value:" + myMap.get(key));
if (key.equals("1")) {
myMap.remove("3");
myMap.put("4", "4");
myMap.put("5", "5");
}
} System.out.println("Map Size:" + myMap.size());
} }

Output of above program is shown below. You can see that there is no ConcurrentModificationException being thrown by the program.



Copy
List Value:1
List Value:2
List Value:3
List Value:4
List Value:5
List Size:6
Map Value:1
Map Value:2
Map Value:4
Map Value:5
Map Size:4

From the above example its clear that:

  1. Concurrent Collection classes can be modified safely, they will not throw ConcurrentModificationException.
  2. In case of CopyOnWriteArrayList, iterator doesn’t accommodate the changes in the list and works on the original list.
  3. In case of ConcurrentHashMap, the behaviour is not always the same.

    For condition:

    
    
    Copy
    if(key.equals("1")){
    myMap.remove("3");}

    Output is:

    
    
    Copy
    Map Value:1
    Map Value:null
    Map Value:4
    Map Value:2
    Map Size:4

    It is taking the new object added with key “4” but not the next added object with key “5”.

    Now if I change the condition to below.

    
    
    Copy
    if(key.equals("3")){
    myMap.remove("2");}

    Output is:

    
    
    Copy
    Map Value:1
    Map Value:3
    Map Value:null
    Map Size:4

    In this case its not considering the new added objects.

    So if you are using ConcurrentHashMap then avoid adding new objects as it can be processed depending on the keyset. Note that the same program can print different values in your system because HashMap keyset is not ordered.

Use for loop to avoid java.util.ConcurrentModificationException

If you are working on single-threaded environment and want your code to take care of the extra added objects in the list then you can do so using for loop rather than iterator.


Copy
for(int i = 0; i<myList.size(); i++){
System.out.println(myList.get(i));
if(myList.get(i).equals("3")){
myList.remove(i);
i--;
myList.add("6");
}
}

Note that I am decreasing the counter because I am removing the same object, if you have to remove the next or further far object then you don’t need to decrease the counter. Try it yourself.

java.util.ConcurrentModificationException(如何避免ConcurrentModificationException)的更多相关文章

  1. java.util.ConcurrentModificationException 解决办法(转载)

    今天在项目的中有一个需求,需要在一个Set类型的集合中删除满足条件的对象,这时想当然地想到直接调用Set的remove(Object o)方法将指定的对象删除即可,测试代码:   public cla ...

  2. java.util.ConcurrentModificationException --map

    key:3-key key:/v1.02-key Exception in thread "main" java.util.ConcurrentModificationExcept ...

  3. 偶遇到 java.util.ConcurrentModificationException 的异常

    今天在调试程序 遇到了如此问题 贴上代码来看看稍后分析 List<String> list = null;boolean isUpdate = false;try { list = JSO ...

  4. 对ArrayList操作时报错java.util.ConcurrentModificationException null

    用iterator遍历集合时要注意的地方:不可以对iterator相关的地方做添加或删除操作.否则会报java.util.ConcurrentModificationException 例如如下代码: ...

  5. LinkedList - java.util.ConcurrentModificationException

    package com.test.io; import java.io.BufferedReader; import java.io.FileNotFoundException; import jav ...

  6. java.util.ConcurrentModificationException 解决办法

    在使用iterator.hasNext()操作迭代器的时候,如果此时迭代的对象发生改变,比如插入了新数据,或者有数据被删除. 则使用会报以下异常:Java.util.ConcurrentModific ...

  7. Iterator之java.util.ConcurrentModificationException

    在运行以下代码时,会报java.util.ConcurrentModificationException异常, public class Demo { public static void main( ...

  8. java.util.ConcurrentModificationException 解决办法(转)

    今天在项目的中有一个需求,需要在一个Set类型的集合中删除满足条件的对象,这时想当然地想到直接调用Set的remove(Object o)方法将指定的对象删除即可,测试代码:   public cla ...

  9. java集合--java.util.ConcurrentModificationException异常

    ConcurrentModificationException 异常:并发修改异常,当方法检测到对象的并发修改,但不允许这种修改时,抛出此异常.一个线程对collection集合迭代,另一个线程对Co ...

  10. list删除操作 java.util.ConcurrentModificationException

    首先大家先看一段代码: public static void main(String[] args) { List<String> listStr = new ArrayList<S ...

随机推荐

  1. JavaScript数组的某些操作(二)

    7.颠倒数组中元素的顺序(注意:不是为数组排序)--reverse方法 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitiona ...

  2. CHROME开发者工具的小技巧

    我猜不能转载,但是必须分享. http://coolshell.cn/articles/17634.html

  3. 5.cocos2d锚点

    创建一个层T1LayerAnchorPoint AppDelegate.cpp bool AppDelegate::applicationDidFinishLaunching() { // initi ...

  4. mv---移动文件或目录

    mv命令用来对文件或目录重新命名,或者将文件从一个目录移到另一个目录中.source表示源文件或目录,target表示目标文件或目录.如果将一个文件移到一个已经存在的目标文件中,则目标文件的内容将被覆 ...

  5. 负载均衡之lvs

    集群(cluster):将一组计算机软/硬件连接起来,高度紧密的协作完成计算工作,其中的单个计算机通常称为节点.负载均衡集群(Load Balancing):通过负载均衡器,将负载尽可能平均分摊处理. ...

  6. 理性分析 C++(-O2) 和 JS 的性能差距

    laptop: Intel(R) Core(TM) i7-8550U CPU @ 1.80GHz.. Test1: 最后一行:时间(ms) #pragma GCC optimize("O2& ...

  7. Spring源码分析专题 —— IOC容器启动过程(上篇)

    声明 1.建议先阅读<Spring源码分析专题 -- 阅读指引> 2.强烈建议阅读过程中要参照调用过程图,每篇都有其对应的调用过程图 3.写文不易,转载请标明出处 前言 关于 IOC 容器 ...

  8. jQ-多选按钮实现单选按钮的功能以及input按钮的优化

    css: .displayN{display: none;} label {font-size:12px;cursor:pointer;} label i {font-size:12px;font-s ...

  9. 将vue-cli 2.x的项目升级到3.x

    尝试将vue-cli 2.x的项目升级到3.x,记录一下升级过程,和遇到的坑 1. 直接复制替换src文件夹 2. 安装项目需要的依赖 (可以将原来package.json dependencies下 ...

  10. 网站新建移动站,做了link rel="canonical" 等于主站URL后,全站被百度K了。

    移动站所有页面的权重都指向主站的首页,估计就是被K的原因.毕竟那么多网页一下权重那么多,当然被K了.不知道啥时候能好.