Be the Winner

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 2718    Accepted Submission(s): 1487

Problem Description
Let's consider m apples divided into n groups. Each group contains no more than 100 apples, arranged in a line. You can take any number of consecutive apples at one time.

For example "@@@" can be turned into "@@" or "@" or "@ @"(two piles). two people get apples one after another and the one who takes the last is


the loser. Fra wants to know in which situations he can win by playing strategies (that is, no matter what action the rival takes, fra will win).
 
Input
You will be given several cases. Each test case begins with a single number n (1 <= n <= 100), followed by a line with n numbers, the number of apples in each pile. There is a blank line between cases.
 
Output
If a winning strategies can be found, print a single line with "Yes", otherwise print "No".
 
Sample Input
2
2 2
1
3
 
Sample Output
No
Yes
#include <stdio.h>
#include <string.h>
using namespace std;
#define M 50
int num[M];
int main()
{
int i,ans,re,n;
while(scanf("%d",&n)!=EOF)
{
ans=0,re=0;
for(i=0;i<n;i++)
{
scanf("%d",&num[i]);
if(num[i]>1)
ans++;
re^=num[i];
}
if(ans)
{
if(re)
printf("Yes\n");
else
printf("No\n");
}
else
{
if(re)
printf("No\n");
else
printf("Yes\n");
}
}
return 0;
}

hdoj--2509--Be the Winner(尼姆博弈)的更多相关文章

  1. hdu-------(1848)Fibonacci again and again(sg函数版的尼姆博弈)

    Fibonacci again and again Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Jav ...

  2. hdu 1907 (尼姆博弈)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1907 Problem Description Little John is playing very ...

  3. POJ 2234 Matches Game (尼姆博弈)

    题目链接: https://cn.vjudge.net/problem/POJ-2234 题目描述: Here is a simple game. In this game, there are se ...

  4. HDU1907(尼姆博弈)

    John Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submis ...

  5. POJ 3480 &amp; HDU 1907 John(尼姆博弈变形)

    题目链接: PKU:http://poj.org/problem? id=3480 HDU:http://acm.hdu.edu.cn/showproblem.php? pid=1907 Descri ...

  6. hdu 1907 尼姆博弈

    John Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submis ...

  7. hdu----(1849)Rabbit and Grass(简单的尼姆博弈)

    Rabbit and Grass Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) ...

  8. hdu 1849(Rabbit and Grass) 尼姆博弈

    Rabbit and Grass Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) ...

  9. Being a Good Boy in Spring Festival 尼姆博弈

    Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Descr ...

  10. HDU 4315 Climbing the Hill (阶梯博弈转尼姆博弈)

    Climbing the Hill Time Limit: 1000MS   Memory Limit: 32768KB   64bit IO Format: %I64d & %I64u Su ...

随机推荐

  1. veket智能机器人

    官方网站:http://www.lucky8k.com/forum.php veket儿童操作系统 希望工具超过小puppy linux系统 一个还在发展中的linux系统: Slax Linux : ...

  2. 面试回答问题要防范hr的陷阱

    面试技巧是大众化的,比较实在.在经历的各种面试中,最不容易防范的面试就是“拉呱”(山东方言,聊天的意思),这样子自己容易放松警惕. 看看下面的,就知道应该怎么应对这些“滑头”的HR! 1.我们为什么要 ...

  3. [Intermediate Algorithm] - Binary Agents

    题目 传入二进制字符串,翻译成英语句子并返回. 二进制字符串是以空格分隔的. 提示 String.charCodeAt() String.fromCharCode() 测试用例 binaryAgent ...

  4. 来源页面地址 上一页面url

    Uri uri = Request.UrlReferrer;

  5. (转)Bootstrap 之 Metronic 模板的学习之路 - (1)总览

    https://segmentfault.com/a/1190000006673582#articleHeader0 写在前面 bootstrap 的模板非常多,Envato 上有着各种各样的免费及付 ...

  6. webpack学习(六)—webpack+react+es6(第2篇)

    接上篇        webpack学习(五)—webpack+react+es6(第1篇) 本文做个简单的图片加文字的页面.其中,配置文件跟上篇一致.项目结构: index.html <!DO ...

  7. 01 DOS常用命令

    有时候没有可视化窗口,命令行对文件进行操作更方便快捷 cmd 命令弹出 dir 查看当前所在目录下的文件 ctrl+c 退出 \a 显示隐藏文件 cd /改变到根目录 dir /a 显示隐藏文件 di ...

  8. 【转载】深入理解Java的接口和抽象类

    深入理解Java的接口和抽象类 对于面向对象编程来说,抽象是它的一大特征之一.在Java中,可以通过两种形式来体现OOP的抽象:接口和抽象类.这两者有太多相似的地方,又有太多不同的地方.很多人在初学的 ...

  9. jsp 多条件组合查询

    web层: public String query(HttpServletRequest request, HttpServletResponse response) throws ServletEx ...

  10. ADB 命令和monkey

    一.概要 1.什么是adb? adb全称为Android Debug Bridge,就是起到调试桥的作用.顾名思义,adb就是一个debug工具. 2.adb工作原理 不是很理解?那就来看看它的工作原 ...