Hardwood Species
Time Limit: 10000MS   Memory Limit: 65536K
Total Submissions: 16056   Accepted: 6418

Description

Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter. 
America's temperate climates produce forests with hundreds of hardwood species -- trees that share certain biological characteristics. Although oak, maple and cherry all are types of hardwood trees, for example, they are different species. Together, all the hardwood species represent 40 percent of the trees in the United States.

On the other hand, softwoods, or conifers, from the Latin word meaning "cone-bearing," have needles. Widely available US softwoods include cedar, fir, hemlock, pine, redwood, spruce and cypress. In a home, the softwoods are used primarily as structural lumber such as 2x4s and 2x6s, with some limited decorative applications.

Using satellite imaging technology, the Department of Natural Resources has compiled an inventory of every tree standing on a particular day. You are to compute the total fraction of the tree population represented by each species.

Input

Input to your program consists of a list of the species of every tree observed by the satellite; one tree per line. No species name exceeds 30 characters. There are no more than 10,000 species and no more than 1,000,000 trees.

Output

Print the name of each species represented in the population, in alphabetical order, followed by the percentage of the population it represents, to 4 decimal places.

Sample Input

Red Alder
Ash
Aspen
Basswood
Ash
Beech
Yellow Birch
Ash
Cherry
Cottonwood
Ash
Cypress
Red Elm
Gum
Hackberry
White Oak
Hickory
Pecan
Hard Maple
White Oak
Soft Maple
Red Oak
Red Oak
White Oak
Poplan
Sassafras
Sycamore
Black Walnut
Willow

Sample Output

Ash 13.7931
Aspen 3.4483
Basswood 3.4483
Beech 3.4483
Black Walnut 3.4483
Cherry 3.4483
Cottonwood 3.4483
Cypress 3.4483
Gum 3.4483
Hackberry 3.4483
Hard Maple 3.4483
Hickory 3.4483
Pecan 3.4483
Poplan 3.4483
Red Alder 3.4483
Red Elm 3.4483
Red Oak 6.8966
Sassafras 3.4483
Soft Maple 3.4483
Sycamore 3.4483
White Oak 10.3448
Willow 3.4483
Yellow Birch 3.4483

Hint

This problem has huge input, use scanf instead of cin to avoid time limit exceeded.

Source

map水。。。。

#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <map>

using namespace std;

int main()
{
    char name[40];
    map<string,int> mSI;
    while(gets(name))
    {
        string s(name);
        if(mSI.count(s))
        {
            mSI[s]++;
        }
        else
        {
            mSI.insert( pair<string,int>(s,1) );
        }
    }

map<string,int>::iterator beg=mSI.begin(),end=mSI.end(),i=beg;
    double sum=0;
    for(;i!=end;i++)
    {
        sum+=(*i).second;
    }
    for(i=beg;i!=end;i++)
    {
        printf("%s %.4lf\n",(i->first).c_str(),(i->second)*100/sum);
    }

return 0;
}

* This source code was highlighted by YcdoiT. ( style: Codeblocks )

POJ 2418 Hardwood Species的更多相关文章

  1. [字典树] poj 2418 Hardwood Species

    题目链接: id=2418">http://poj.org/problem?id=2418 Hardwood Species Time Limit: 10000MS   Memory ...

  2. POJ 2418 Hardwood Species(STL在map应用)

    职务地址:id=2418">POJ 2418 通过这个题查了大量资料..知道了非常多曾经不知道的东西. . .. 在代码中凝视说明吧. 代码例如以下: #include <ios ...

  3. [ACM] POJ 2418 Hardwood Species (Trie树或map)

    Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 17986   Accepted: 713 ...

  4. poj 2418 Hardwood Species (map)

    题目:http://poj.org/problem?id=2418 在poj 上交题总是有各种错误,再次感叹各个编译器. c++ AC代码,G++为超时,上代码: #include<cstdio ...

  5. POJ - 2418 Hardwood Species(map,trie,BST)

    1.输入若干行树名,输入结束后,按字典序输出树名及其所占百分比. 2.多种方法:map,trie,BST 3. map: #include<iostream> #include<st ...

  6. 二叉搜索树 POJ 2418 Hardwood Species

    题目传送门 题意:输入一大堆字符串,问字典序输出每个字符串占的百分比 分析:二叉搜索树插入,然后中序遍历就是字典序,这里root 被new出来后要指向NULL,RE好几次.这题暴力sort也是可以过的 ...

  7. POJ 2418 Hardwood Species( AVL-Tree )

    #include <stdio.h> #include <stdlib.h> #include <math.h> #include <string.h> ...

  8. POJ 2418 Hardwood Species (哈希,%f 和 %lf)

    我的错因: 本来改用%f输出,我用了%lf,结果编译器直接判定为错误(一部分编译器认为lf是没有错的).当时我还以为是hash出错了.. 方法不止一种: 方法 时间   空间 Hash 891ms 5 ...

  9. POJ 2418 Hardwood Species 【Trie树】

    <题目链接> 题目大意: 给你一堆字符串,让你按字典序输出他们出现的频率. 解题分析: 首先,这是Trie数词频统计的题目,以Trie树的边储存字母,节点存储以该节点结尾的链所代表的字符串 ...

随机推荐

  1. Android四大布局及其主要属性

    布局: <LinearLayout></LinearLayout> <RelativeLayout></RelativeLayout> <Fram ...

  2. Mediator Pattern --中介者模式原理及实现(C++)

    主要参考<大话设计模式>和<设计模式:可复用面向对象软件的基础>两本书.本文介绍中介者模式的实现. 中介者模式:What it is:Define an object that ...

  3. Unity3D 游戏计时功能实现

    最近工作实在是太忙了,没办法认真写博客,但是还是要好好记录下日常的学习. 需求 各类游戏中都大量运用到计时功能,不管是直接显示的在前端UI,还是后台运行. 思路 Unity中提供了Time类可以方便的 ...

  4. Git.Framework 框架随手记--ORM查询数据集合 一

    本文记录Git.Framework之ORM中最为浓墨重彩的一篇,查询集合.根据自己做的项目统计这个是使用频率最高的一个. 一. 查询集合方法简介 (1)List<T> GetList(); ...

  5. css的6中居中的方式

    请先看blog:http://blog.csdn.net/wolinxuebin/article/details/7615098

  6. [C#]Main(String[] args)参数输入问题

    Main函数是程序的入口点,它是入口点,那它的参数,又是怎样来的呢?首先写个简单的测试程序看看args到底是什么? class Program { static void Main(string[] ...

  7. js获取url查询参数

    function getURLParamInfo(key) { if (location.search == "") { return undefined; } var a = l ...

  8. Android Launcher分析和修改9——Launcher启动APP流程

    本来想分析AppsCustomizePagedView类,不过今天突然接到一个临时任务.客户反馈说机器界面的图标很难点击启动程序,经常点击了没有反应,Boss说要优先解决这问题.没办法,只能看看是怎么 ...

  9. 18.Android之SharedPreferences数据存储学习

    SharedPreferences是Android中最容易理解的数据存储技术,实际上SharedPreferences处理的就是一个key-value(键值对)SharedPreferences常用来 ...

  10. opencv笔记2:图像ROI

    time:2015年 10月 03日 星期六 12:03:45 CST # opencv笔记2:图像ROI ROI ROI意思是Region Of Interests,感兴趣区域,是一个图中的一个子区 ...