You are my brother
问题 : You are my brother
时间限制: 1 Sec 内存限制: 128 MB
题目描述
Little A gets to know a new friend, Little B, recently. One day, they realize that they are family 500 years ago. Now, Little A wants to know whether Little B is his elder, younger or brother.
输入
There are multiple test cases.
For each test case, the first line has a single integer, n (n<=1000). The next n lines have two integers a and b (1<=a,b<=2000) each, indicating b is the father of a. One person has exactly one father, of course. Little A is numbered 1 and Little B is numbered 2.
Proceed to the end of file.
输出
For each test case, if Little B is Little A’s younger, print “You are my younger”. Otherwise, if Little B is Little A’s elder, print “You are my elder”. Otherwise, print “You are my brother”. The output for each test case occupied exactly one line.
样例输入
5 1 3 2 4 3 5 4 6 5 6 6 1 3 2 4 3 5 4 6 5 7 6 7
样例输出
You are my elder You are my brother
解题思路
根据所给的数对,判断1,2分别组成的链的长短。
#include <stdio.h>
#include <string.h>
int main()
{
int n, a, b;
int s[2010];
while (~scanf("%d", &n))
{
memset(s, 0, sizeof(s));
for (int i = 0; i < n; i++)
{
scanf("%d%d", &a, &b);
s[a] = b;
}
a = 1;
b = 2;
while (s[a] && s[b])
{
a = s[a];
b = s[b];
}
if (!s[a] && s[b])
puts("You are my younger");
else if (!s[a] && !s[b])
puts("You are my brother");
else puts("You are my elder");
}
return 0;
}You are my brother的更多相关文章
- fzoj1314 You are my brother
题目描述 Little A gets to know a new friend, Little B, recently. One day, they realize that they are fam ...
- 远程监控显示brother数控机床数据
最近几个月公司太忙了,到现在已经连续出差两个多月了. 这个项目这要做mes系统,涉及到产品在机床的加工过程监控,然后led看板显示产品进度. 这里的主角是日本的brother数控机床,服务器按照一定频 ...
- Ubuntu 安装 Brother MFC7470D 驱动
Ubuntu 安装 Brother MFC7470D 驱动 办公室的打印机是 Brother MFC7470D ,在 Ubuntu 中安装打印机驱动时,发现没有这个型号的驱动.只有 MFC7450 的 ...
- FJNU 1154 Fat Brother And His Love(胖哥与女神)
FJNU 1154 Fat Brother And His Love(胖哥与女神) Time Limit: 2000MS Memory Limit: 257792K [Description] [ ...
- FJNU 1153 Fat Brother And XOR(胖哥与异或)
FJNU 1153 Fat Brother And XOR(胖哥与异或) Time Limit: 1000MS Memory Limit: 257792K [Description] [题目描述] ...
- FJNU 1155 Fat Brother’s prediction(胖哥的预言)
FJNU 1155 Fat Brother’s prediction(胖哥的预言) Time Limit: 1000MS Memory Limit: 257792K [Description] [ ...
- FJNU 1152 Fat Brother And Integer(胖哥与整数)
FJNU 1152 Fat Brother And Integer(胖哥与整数) Time Limit: 1000MS Memory Limit: 257792K [Description] [题 ...
- FJNU 1156 Fat Brother’s Gorehowl(胖哥的血吼)
FJNU 1156 Fat Brother’s Gorehowl(胖哥的血吼) Time Limit: 1000MS Memory Limit: 257792K [Description] [题目 ...
- FJNU 1151 Fat Brother And Geometry(胖哥与几何)
FJNU 1151 Fat Brother And Geometry(胖哥与几何) Time Limit: 1000MS Memory Limit: 257792K [Description] [ ...
- FJNU 1157 Fat Brother’s ruozhi magic(胖哥的弱智术)
FJNU 1157 Fat Brother’s ruozhi magic(胖哥的弱智术) Time Limit: 1000MS Memory Limit: 257792K [Description ...
随机推荐
- box-shadow阴影覆盖问题
“商品库”栏下方阴影被覆盖,解决方法:给“商品库”盒子加“position:relative”
- 1Mybatis入门--1.1单独使用jdbc编程问题总结
1.1.1 jdbc程序 Public static void main(String[] args) { Connection connection = null; PreparedStatemen ...
- Light oj 1281 - New Traffic System 多状态最短路
题目大意:有向图,新计划的地铁,有k个计划新路,利用现有的铁路.k条新路和限定只能用d条新路,找出从0到n-1的最短路径 题目思路:用dist[u][use],储存使用use条新路,到达节点u的最短路 ...
- .net中的设计模式---单例模式
.net设计模式: Net设计模式实例之单例模式( Singleton Pattern) 一 : 单例模式的简介:(Brief Introduction) 单例模式(Singleton Patter ...
- python3+selenium入门13-操作cookie
可以把cookie理解为自己账户的身份证.因为http协议是无状态的,上一个请求和下一个请求没有关系.但是有时需要有关联.比如登录之后,才能进行操作这样的设置.这个就是cookie在起作用.登录成功时 ...
- genPanel.py
#!/usr/bin/python # -*- coding: UTF-8 -*- import os import sys import re import shutil import glob ' ...
- 词向量之Word2vector原理浅析
原文地址:https://www.jianshu.com/p/b2da4d94a122 一.概述 本文主要是从deep learning for nlp课程的讲义中学习.总结google word2v ...
- 使用tomcat发布含有shtml文件的web程序
平常都是使用html或jsp,当导入含有shtml的一个web项目时,向平常一样使用Jetty运行,访问到shtml文件时,直接在浏览器上显示出了源码. 查询,使用tomcat发布,修改tomcat的 ...
- fiddler 抓取 安卓模拟器 https包
2017-12-12 16:47:45 星期二 需要材料: 1. fiddler 2. 逍遥模拟器 步骤: 1. fiddler->tool->Optiions...->connec ...
- scrapy-redis(调度器Scheduler源码分析)
settings里面的配置:'''当下面配置了这个(scrapy-redis)时候,下面的调度器已经配置在scrapy-redis里面了'''##########连接配置######## REDIS_ ...