String M[] = {"", "M", "MM", "MMM”};//1000~3000
String C[] = {"", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM”};//100~900
String X[] = {"", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC”};//10~90
String I[] = {"", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX”};//1~9
 
按照上述对应规则可以进行选择合适的罗马数字。
 
参考代码:
 
package leetcode_50;

/***
*
* @author pengfei_zheng
* 整数转为罗马数字
*/
public class Solution12 {
public static String intToRoman(int num) {
/***
* 对应规则如下所示:
*/
String M[] = {"", "M", "MM", "MMM"};
String C[] = {"", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM"};
String X[] = {"", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC"};
String I[] = {"", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX"};
return M[num/1000] + C[(num%1000)/100] + X[(num%100)/10] + I[num%10];
}
}

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