# -*- coding: utf-8 -*-
"""
Created on Wed Aug 10 08:10:35 2016 @author: Administrator
"""
'''
关于:cross_validation.scores
此处cross_validation.scores并不是cross_validation的scores,
而是分类函数(本文是clf,svm)的scores
分成K部分
K-1是训练
1次是测试
共K个scores
''' import time
import numpy as np
from sklearn import cross_validation
from sklearn import datasets
from sklearn import svm start = time.time()
iris = datasets.load_iris()
print iris.data.shape, iris.target.shape
#(150L, 4L) (150L,) X_train, X_test, y_train, y_test = cross_validation.train_test_split(iris.data, iris.target, test_size=0.4, random_state=0)
print X_train.shape, y_train.shape
print X_test.shape, y_test.shape
#(90L, 4L) (90L,)
#(60L, 4L) (60L,) clf = svm.SVC(kernel='linear', C=1).fit(X_train, y_train)
print clf.score(X_test, y_test)
#0.966666666667 #模块2
clf = svm.SVC(kernel='linear', C=1)
scores = cross_validation.cross_val_score(clf, iris.data, iris.target, cv=5)
print scores
#[ 0.96666667 1. 0.96666667 0.96666667 1. ]
print("Accuracy: %0.2f (+/- %0.2f)" % (scores.mean(), scores.std() * 2))
#Accuracy: 0.98 (+/- 0.03) #模块3
from sklearn import metrics
scores = cross_validation.cross_val_score(clf, iris.data, iris.target,cv=5, scoring='f1_weighted')
print scores
#[ 0.96658312 1. 0.96658312 0.96658312 1. ] print("Took %.2f seconds for" % ((time.time() - start)))

关于:cross_validation.scores的更多相关文章

  1. [LeetCode] Rank Scores 分数排行

    Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ra ...

  2. Codeforces Round #370 (Div. 2) D. Memory and Scores DP

    D. Memory and Scores   Memory and his friend Lexa are competing to get higher score in one popular c ...

  3. Faster RCNN 运行自己的数据,刚开始正常,后来就报错: Index exceeds matrix dimensions. Error in ori_demo (line 114) boxes_cell{i} = [boxes(:, (1+(i-1)*4):(i*4)), scores(:, i)];

    function script_faster_rcnn_demo() close all; clc; clear mex; clear is_valid_handle; % to clear init ...

  4. LeetCode Database: Rank Scores

    Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ra ...

  5. LeetCode:Rank Scores

    做到这题时卡了不少时间,参考了别人的解法,觉得挺不错的,还挺巧妙. SELECT s2.Score,s1.Rank From ( SELECT S1.Score, COUNT(*) as Rank F ...

  6. (Problem 22)Names scores

    Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over five-tho ...

  7. Memory and Scores

    Memory and Scores 题目链接:http://codeforces.com/contest/712/problem/D dp 因为每轮Memory和Lexa能取的都在[-k,k],也就是 ...

  8. anacoda报错No module named 'sklearn.cross_validation'

    在目前的snacoda里集成的sklearn已经不存在cross_validation模块了 使用以下模块 from  sklearn.model_selection  import train_te ...

  9. [SQL]LeetCode178. 分数排名 | Rank Scores

    Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ra ...

随机推荐

  1. Rem是什么,牛逼的Vue,Epub竟然可以实现阅读器功能。太牛了。

    rem 相当于根元素font-size值的倍数. 1rem=根元素font-size 2rem=根元素font-size * 2 // 1rem = fontSize px // 1px = (1/f ...

  2. SSIS的控制流之Foreach循环容器和序列容器

    上一篇介绍了For循环容器的使用.本篇将介绍Foreach循环容器和序列容器的使用. Foreach循环容器 Foreach循环容器定义包中的控制流.其循环的实现类似于编程语言中的Foreach循环结 ...

  3. java:OutputStream和InputStream 输出输入流,FileOutputStream,FileInputStream写入读取流

    1.在java中stream代表一种数据流(源),javaio的底层数据元,---(想像成水龙头)2.任何有能力产生数据流(源)的javaio对象就可以看作是一个InputStream对象既然它能产生 ...

  4. java:正则匹配Pattern,Matcher

    一.正则匹配Pattern,Mather String s = "aa424fsfsd92lfjw2755097"; Pattern p = Pattern.compile(&qu ...

  5. 【疯了C#】神奇的换肤(一)

    之前看网上有换肤控件IrisSkin2的介绍,感觉很神奇,今天亲自做下试验,C#越来越有趣了,是Labview无法比拟的. 前期准备工作如下:下载后IrisSkin2.dll及匹配的皮肤. 其中ssk ...

  6. LightOJ - 1027 数学期望

    题意:有n扇门,每扇门有一个值x,大于0代表x分钟后出去,小于0代表x分钟后回到原地,求出去的时间的期望 题解:假设出去的总时间为sum1,回来的总时间为sum2,出去的门个数为out,进来的门的个数 ...

  7. Get UTI (uniform type identifier) and ContentType

    #import <Foundation/Foundation.h> int main(int argc, const char * argv[]) { @autoreleasepool { ...

  8. java中如何将string 转化成long

    1.Java中如何将string 转化成long long l = Long.parseLong([String]); 或 long l = Long.parseLong([String],[int ...

  9. 1.mysql优化---优化入门之MySQL的优化介绍及执行步骤

    优化到底优化什么?      优化,一直是面试最常问的一个问题.因为从优化的角度,优化的思路,完全可以看出一个人的技术积累.那么,关于系统优化,假设这么个场景,用户反映系统太卡(其实就是高并发),那么 ...

  10. 九、python沉淀之路--递归、全局变量、局部变量、作用域

    一.递归 1.递归函数,同时使用嵌套,并且是将别的函数作用于调用函数里面 例1 num = [1,2,3,4,5] def add_one(i): return i+1 def reduce(i): ...