PAT Advanced 1050 String Subtraction (20 分)
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do it fast.
Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
Output Specification:
For each test case, print S1−S2 in one line.
Sample Input:
They are students.
aeiou
Sample Output:
Thy r stdnts.
#include <iostream>
using namespace std; int main(){
string s1,s2,res="";
getline(cin,s1);
getline(cin,s2);
for(int i=;i<s1.length();i++){
if(s2.find(s1[i])==s2.npos) res+=s1[i];
}
cout<<res;
system("pause");
return ;
}
PAT Advanced 1050 String Subtraction (20 分)的更多相关文章
- PAT 甲级 1050 String Subtraction (20 分) (简单送分,getline(cin,s)的使用)
1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be t ...
- PAT Advanced 1050 String Subtraction (20) [Hash散列]
题目 Given two strings S1 and S2, S = S1 – S2 is defined to be the remaining string afer taking all th ...
- PAT练习--1050 String Subtraction (20 分)
题⽬⼤意:给出两个字符串,在第⼀个字符串中删除第⼆个字符串中出现过的所有字符并输出. 这道题的思路:将哈希表里关于字符串s2的所有字符都置为true,再对s1的每个字符进行判断,若Hash[s1[i] ...
- 【PAT甲级】1050 String Subtraction (20 分)
题意: 输入两个串,长度小于10000,输出第一个串去掉第二个串含有的字符的余串. trick: ascii码为0的是NULL,减去'0','a','A',均会导致可能减成负数. AAAAAccept ...
- 1050 String Subtraction (20分)
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking ...
- PAT 解题报告 1050. String Subtraction (20)
1050. String Subtraction (20) Given two strings S1 and S2, S = S1 - S2 is defined to be the remainin ...
- PAT甲级——1050 String Subtraction
1050 String Subtraction Given two strings S1 and S2, S=S1−S2 is defined to be the remain ...
- PAT (Advanced Level) 1050. String Subtraction (20)
简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> ...
- PAT Advanced 1042 Shuffling Machine (20 分)(知识点:利用sstream进行转换int和string)
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...
随机推荐
- 如何消除 com.netflix.discovery.shared.transport.TransportException: Cannot execute request on any known server
在application.properties中添加以下两句话: eureka.client.register-with-eureka=falseeureka.client.fetch-registr ...
- 手动清空微信PC客户端数据
微信PC客户端,用久了之后,会产生大量数据,包括聊天记录.聊天图片.视频等等,非常占存储空间,除非很重要的聊天记录或文件,建议额外保存,其他的可以手动删掉就好,可以节省存储空间. 1.找到[C:\Us ...
- OpenStack 2018 年终盘点
目录 文章目录 目录 前言 OpenStack 一年来的成长 Nova Cinder Neutron Ironic Cyborg Octavia Kolla Magnum Zun Kuryr 从 Op ...
- loadrunner 场景设计-手工场景方案(Schedule)设计 Part 2
loadrunner 场景设计-手工场景方案(Schedule)设计 Part 2 ---------------------------接Part 1------------------------ ...
- 【HTML5】页面点击按钮添加一行 删除一行 全选 反选 全不选
页面点击按钮添加一行 删除一行 全选 反选 全不选 页面效果图如下 html页面代码 <!DOCTYPE html> <html> <head> & ...
- UniEAP Platform V5.0 Unable to compile class for JSP
流程设计器报错: http://127.0.0.1:8080/framework/workflow/webdesign/procmodify/procmodifydetail.jsp?isLoadDa ...
- Java锁机制ReentrantLock
ReentrantLock 锁常用于保证程序的人为顺序执行. 写一个类模拟ReentrantLock类的功能 class MyLock{ private boolean lock = false; p ...
- MTU,MRU,MSS
MTU是以太网数据链路层概念,默认是1500,当在PPPOE环境的时候,是1492和1480,两者有何区别,暂不清楚 MRU是PPP链路数据链路层的概念,都是最大传输单元的意思 MSS是最大报文段长度 ...
- firewalld防火墙简介
1.防火墙 防火墙,其实就是一个隔离工具:工作于主机或者网络的边缘 对于进出本主机或者网络的报文根据事先定义好的网络规则做匹配检测, 对于能够被规则所匹配的报文做出相应处理的组件(这个组件可以是硬件, ...
- 【机器学习入门笔记】第 2 课:SVM
Support Vector machines 为什么人们称一种算法为机器,我也不知道(俄罗斯人发明) 粗略的来说,支持向量机所做的就是去寻找分割线(separating) 或者通常称之为超平面,介于 ...