PAT Advanced 1050 String Subtraction (20 分)
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do it fast.
Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
Output Specification:
For each test case, print S1−S2 in one line.
Sample Input:
They are students.
aeiou
Sample Output:
Thy r stdnts.
#include <iostream>
using namespace std; int main(){
string s1,s2,res="";
getline(cin,s1);
getline(cin,s2);
for(int i=;i<s1.length();i++){
if(s2.find(s1[i])==s2.npos) res+=s1[i];
}
cout<<res;
system("pause");
return ;
}
PAT Advanced 1050 String Subtraction (20 分)的更多相关文章
- PAT 甲级 1050 String Subtraction (20 分) (简单送分,getline(cin,s)的使用)
1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be t ...
- PAT Advanced 1050 String Subtraction (20) [Hash散列]
题目 Given two strings S1 and S2, S = S1 – S2 is defined to be the remaining string afer taking all th ...
- PAT练习--1050 String Subtraction (20 分)
题⽬⼤意:给出两个字符串,在第⼀个字符串中删除第⼆个字符串中出现过的所有字符并输出. 这道题的思路:将哈希表里关于字符串s2的所有字符都置为true,再对s1的每个字符进行判断,若Hash[s1[i] ...
- 【PAT甲级】1050 String Subtraction (20 分)
题意: 输入两个串,长度小于10000,输出第一个串去掉第二个串含有的字符的余串. trick: ascii码为0的是NULL,减去'0','a','A',均会导致可能减成负数. AAAAAccept ...
- 1050 String Subtraction (20分)
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking ...
- PAT 解题报告 1050. String Subtraction (20)
1050. String Subtraction (20) Given two strings S1 and S2, S = S1 - S2 is defined to be the remainin ...
- PAT甲级——1050 String Subtraction
1050 String Subtraction Given two strings S1 and S2, S=S1−S2 is defined to be the remain ...
- PAT (Advanced Level) 1050. String Subtraction (20)
简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> ...
- PAT Advanced 1042 Shuffling Machine (20 分)(知识点:利用sstream进行转换int和string)
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...
随机推荐
- Parcelable和Serializable
本文主要介绍Parcelable和Serializable的作用.效率.区别及选择,关于Serializable的介绍见Java 序列化的高级认识. 1.作用 Serializable的作用是为了保存 ...
- web基础知识汇总
HTML&XML 1.JavaWeb的概述 A: 什么是Web----->就是网页或者网站 B: 什么是JavaWeb----->就是使用java语言做web C: 浏览器访问网站 ...
- 解决ssh链接慢问题
1,ssh -v root@ip 2,查看哪里卡住了 一般情况就是卡在debug1: SSH2_MSG_SERVICE_ACCEPT received 3,如果是上面卡住了 修改/etc/ssh/ss ...
- 转载 STM32 使用Cubemx 建一个USB(HID)设备下位机,实现数据收发
STM32 使用Cubemx 建一个USB(HID)设备下位机,实现数据收发 本文转载自 https://www.cnblogs.com/xingboy/p/9913963.html 这里我主要说一 ...
- Activity启动场景Task分析(二)
场景分析 下面通过启动Activity的代码来分析一下: 1.桌面 首先,我们看下处于桌面时的状态,运行命令: adb shell dumpsys activity 结果如下 ACTIVITY MAN ...
- ibatis使用iterate实现批量插入insert正确写法
由于想批量入库提升效率,最近实现了ibatis的批量插入,结果一直报错 :StringIndexOutOfBoundsException ,原来是value中的格式不正确. 本人邮箱:techqu@1 ...
- Kubernetes网络隔离NetworkPolicy
Kubernetes要求集群中所有pod,无论是节点内还是跨节点,都可以直接通信,或者说所有pod工作在同一跨节点网络,此网络一般是二层虚拟网络,称为pod网络.在安装引导kubernetes时,由选 ...
- 深入理解java:4.2. 框架编程之Spring框架的设计理念
什么是Spring呢? Spring是为了解决企业应用开发的复杂性而创建的一个轻量级的控制反转(IoC)和面向切面(AOP)的容器框架. Spring优点 简单了解Spring之后,我们看一下Spri ...
- poj1284(欧拉函数+原根)
题目链接:https://vjudge.net/problem/POJ-1284 题意:给定奇素数p,求x的个数,x为满足{(xi mod p)|1<=i<=p-1}={1,2,...,p ...
- Windown Server 2008配置tomcat9虚拟路径
一.用途 用于保存项目运产生的文件 二.步骤 1.修改conf\下的web.xml <!-- 找到listings将false改为true --> <init-para ...