现在,这里有一个功能:
  F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100) 
当x在0到100之间时,你能找到最小值吗?

输入

第一行包含一个整数T(1 < = T < = 100),这意味着测试用例的数量。然后T行,每一行只有一个实数Y。(0 < Y < 1e10)当x在0到100之间时,输出值为最小值(精确到小数点后4位)。

Sample Input

2
100
200

Sample Output

-74.4291
-178.8534
 #include<bits/stdc++.h>
using namespace std;
double del(double mid) /*求导*/
{
double temp = *pow(mid,)+*pow(mid,)+*mid*mid+*mid; return temp;
} double cacu(double mid ,double y)
{
double ans;
ans = *pow(mid,)+*pow(mid,)+*pow(mid,)+*mid*mid-y*mid;
return ans;
}
int main()
{
int t;
double y;
while(cin>>t)
{
while(t--)
{
scanf("%lf",&y);
double left = ,right = ,mid;
while( right-left >1e-)
{
mid =(left+right) /;
if(del(mid) - y > )
right = mid;
else
left = mid;
}
printf("%.4lf\n",cacu(mid,y));
} }
return ;
}

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