思路:

维护一个unordered_map,key是每个连续区间的端点,value是该区间的长度。

实现:

 class Solution
{
public:
int longestConsecutive(vector<int>& nums)
{
unordered_map<int, int> mp;
int ans = ;
for (auto it: nums)
{
if (mp.count(it)) continue;
int l = mp.count(it - ) ? mp[it - ] : ;
int r = mp.count(it + ) ? mp[it + ] : ;
int sum = l + r + ;
ans = max(ans, sum);
mp[it] = sum;
mp[it - l] = sum;
mp[it + r] = sum;
}
return ans;
}
};

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