C. Vanya and Scales
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Vanya has a scales for weighing loads and weights of masses w0, w1, w2, ..., w100 grams where w is some integer not less than 2(exactly one weight of each nominal value). Vanya wonders whether he can weight an item with mass m using the given weights, if the weights can be put on both pans of the scales. Formally speaking, your task is to determine whether it is possible to place an item of mass m and some weights on the left pan of the scales, and some weights on the right pan of the scales so that the pans of the scales were in balance.
InputThe first line contains two integers w, m (2 ≤ w ≤ 109, 1 ≤ m ≤ 109) — the number defining the masses of the weights and the mass of the item.
OutputPrint word 'YES' if the item can be weighted and 'NO' if it cannot.
Examplesinput3 7outputYESinput100 99outputYESinput100 50outputNONoteNote to the first sample test. One pan can have an item of mass 7 and a weight of mass 3, and the second pan can have two weights of masses 9 and 1, correspondingly. Then 7 + 3 = 9 + 1.
Note to the second sample test. One pan of the scales can have an item of mass 99 and the weight of mass 1, and the second pan can have the weight of mass 100.
Note to the third sample test. It is impossible to measure the weight of the item in the manner described in the input.
#include<bits/stdc++.h>
using namespace std; int main()
{
int a,b,c;
scanf("%d%d",&a,&b);
while(b)
{
c=b%a;
if(!c)b/=a;
else if(c==){b=(b-)/a;}
else if(c==a-){b=(b+)/a;}
else{puts("NO");return ;}
}
puts("YES");
}
C. Vanya and Scales的更多相关文章
- codeforces C. Vanya and Scales
C. Vanya and Scales Vanya has a scales for weighing loads and weights of masses w0, w1, w2, ..., w10 ...
- CodeForces 552C Vanya and Scales
Vanya and Scales Time Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u S ...
- Codeforces Round #308 (Div. 2)----C. Vanya and Scales
C. Vanya and Scales time limit per test 1 second memory limit per test 256 megabytes input standard ...
- Codeforces Round #308 (Div. 2) C. Vanya and Scales dfs
C. Vanya and Scales Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/552/p ...
- Vanya and Scales(思维)
Vanya and Scales time limit per test 1 second memory limit per test 256 megabytes input standard inp ...
- 暴力/进制转换 Codeforces Round #308 (Div. 2) C. Vanya and Scales
题目传送门 /* 题意:问是否能用质量为w^0,w^1,...,w^100的砝码各1个称出重量m,砝码放左边或在右边 暴力/进制转换:假设可以称出,用w进制表示,每一位是0,1,w-1.w-1表示砝码 ...
- codeforces 552 C Vanya and Scales
这个题的意思就是给出一个数m.以及一个以1为首元素.w为比例常数的等比数列,数列长度为101,数列中每一个数字最多仅仅能用一次.问是否存在xa+wb+--=wc+wd+--+we+m. 非常显然,换句 ...
- 【30.23%】【codeforces 552C】Vanya and Scales
time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...
- Codeforces 552C Vanya and Scales(思路)
题目大概说有101个质量w0.w1.w2.....w100的砝码,和一个质量m的物品,问能否在天平两边放物品和砝码使其平衡. 哎,怎么没想到..注意到w0.w1.w2.....w100—— 把m转化成 ...
随机推荐
- redis集群设置密码详解
原文:http://lookingdream.blog.51cto.com/5177800/1827851 注意事项: 1.如果是使用redis-trib.rb工具构建集群,集群构建完成前不要配置密码 ...
- Building a Radio Listening Station to Decode Digital Audio & Police Dispatches
On April 7, 2017, residents in Dallas, Texas, woke to the sound of emergency sirens blaring all over ...
- [转]通俗易懂的php多线程解决方案
原文: https://www.w3cschool.cn/php/php-thread.html --------------------------------------------------- ...
- nginx配置初步
nginx配置初步 1,切换至nginx目录,找到配置文件目录 cd /etc/nginx/conf.d 2,拷贝一份conf文件 sudo cp default.conf head.conf 3,进 ...
- C语言使用以及其它语言经常出的错误
1. 计算优先级 i/*pi/(*p) //默认即用“()”花括号分隔即可 2.分号结束 ; ; if(i<j);{ //code } //分号结束必须看清楚 3.声明变量 ; ; //声明变量 ...
- 卸载 linux http
当我们想卸载httpd 的时候,使用rpm -qa httpd 的时候,我们发现有很多的依赖包.我们耐心的想一个一个的卸载的时候(使用rpm -e httpd-*),还会进入死循环.解决的办法是:使用 ...
- JS基础——构造函数VS原型
JS是一种基于对象的语言.在使用过程中不免遇到复制对象的问题.但通常我们採用的直接赋值'obj1=obj2'这样的做法会出现数据覆盖问题. 也就是对象引用过程中引用地址一致.导致对象数据被改动的问题. ...
- HDU 3305 Ice-sugar Gourd
Ice-sugar Gourd Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)T ...
- python 字符串前缀
普通字符串 一般字符串都是已unicode编码,且和C类似,可以使用\来转义,比如 a = "test\ntest" print(a) 输出 test test 前面加r 在字符串 ...
- 创建一个zookeeper的会话(实现watcher)
在先前的章节中,我们利用zkCli去了解了一下主要的zookeeper的操作.在接下来的章节中,我们将会学习一下在应用中是怎样利用zookeeper的api的.接下来我们将利用一个程序展示一下,怎样来 ...