LintCode: Binary Tree Postorder Traversal
C++,递归
/**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
/**
* @param root: The root of binary tree.
* @return: Postorder in vector which contains node values.
*/
public:
vector<int> postorderTraversal(TreeNode *root) {
// write your code here
vector<int> result;
if (root == NULL) {
return result;
}
if (root->left != NULL) {
vector<int> left = postorderTraversal(root->left);
result.reserve(result.size() + left.size());
result.insert(result.end(), left.begin(), left.end());
}
if (root->right != NULL) {
vector<int> right = postorderTraversal(root->right);
result.reserve(result.size() + right.size());
result.insert(result.end(), right.begin(), right.end());
}
result.push_back(root->val);
return result;
}
};
C++,递归,辅助函数
/**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
/**
* @param root: The root of binary tree.
* @return: Postorder in vector which contains node values.
*/
public:
vector<int> postorderTraversal(TreeNode *root) {
// write your code here
vector<int> result;
if (root == NULL) {
return result;
} else {
postorderCore(root, result);
}
return result;
}
void postorderCore(TreeNode *root, vector<int> &result) {
if (root == NULL) {
return;
}
if (root->left != NULL) {
postorderCore(root->left, result);
}
if (root->right != NULL) {
postorderCore(root->right, result);
}
result.push_back(root->val);
return;
}
};
C++,非递归
[一个stack]
[一个cur指针]
[一个pre指针]
/**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
/**
* @param root: The root of binary tree.
* @return: Postorder in vector which contains node values.
*/
public:
vector<int> postorderTraversal(TreeNode *root) {
// write your code here
vector<int> result;
if (root == NULL) {
return result;
} TreeNode *cur = root, *pre = NULL;
stack<TreeNode *> sta; while (cur != NULL || !sta.empty()) {
while (cur != NULL) {
sta.push(cur);
cur = cur->left;
}
cur = sta.top();
if (cur->right == NULL || cur->right == pre) {
sta.pop();
result.push_back(cur->val);
pre = cur;
cur = NULL;
} else {
cur = cur->right;
}
}
return result;
}
};
LintCode: Binary Tree Postorder Traversal的更多相关文章
- 12. Binary Tree Postorder Traversal && Binary Tree Preorder Traversal
详见:剑指 Offer 题目汇总索引:第6题 Binary Tree Postorder Traversal Given a binary tree, return the po ...
- Binary Tree Preorder Traversal and Binary Tree Postorder Traversal
Binary Tree Preorder Traversal Given a binary tree, return the preorder traversal of its nodes' valu ...
- C++版 - LeetCode 145: Binary Tree Postorder Traversal(二叉树的后序遍历,迭代法)
145. Binary Tree Postorder Traversal Total Submissions: 271797 Difficulty: Hard 提交网址: https://leetco ...
- LeetCode: Binary Tree Postorder Traversal 解题报告
Binary Tree Postorder Traversal Given a binary tree, return the postorder traversal of its nodes' va ...
- 【LeetCode】145. Binary Tree Postorder Traversal (3 solutions)
Binary Tree Postorder Traversal Given a binary tree, return the postorder traversal of its nodes' va ...
- 二叉树前序、中序、后序非递归遍历 144. Binary Tree Preorder Traversal 、 94. Binary Tree Inorder Traversal 、145. Binary Tree Postorder Traversal 、173. Binary Search Tree Iterator
144. Binary Tree Preorder Traversal 前序的非递归遍历:用堆来实现 如果把这个代码改成先向堆存储左节点再存储右节点,就变成了每一行从右向左打印 如果用队列替代堆,并且 ...
- LeetCode 145. 二叉树的后序遍历(Binary Tree Postorder Traversal)
145. 二叉树的后序遍历 145. Binary Tree Postorder Traversal 题目描述 给定一个二叉树,返回它的 后序 遍历. LeetCode145. Binary Tree ...
- [LeetCode] Binary Tree Postorder Traversal 二叉树的后序遍历
Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary ...
- 145. Binary Tree Postorder Traversal
题目: Given a binary tree, return the postorder traversal of its nodes' values. For example:Given bina ...
随机推荐
- JavaScript进阶系列04,函数参数个数不确定情况下的解决方案
本篇主要体验函数参数个数不确定情况下的一个解决方案.先来看一段使用函数作为参数进行计算的实例. var calculate = function(x, y, fn) { return fn(x, y) ...
- C#编程(二十)----------静态类
如果类只包含静态的方法和属性,该类就是静态的.静态类在功能上与使用私有静态构造函数创建的类相同.不能创建静态类的实例.使用关键字static关键字,编译器可以检查用户是否不经意间给类添加了实例成员.如 ...
- 点击cell动态修改高度动画
点击cell动态修改高度动画 效果 源码 https://github.com/YouXianMing/Animations // // TapCellAnimationController.m // ...
- 绝命毒师第五季/全集Breaking Bad迅雷下载
本季Breaking Bad Season 5(2012)看点:故事紧接着上一季,通过一场精心策划的大爆炸,沃尔特(布莱恩·科兰斯顿 Bryan Cranston 饰)终于除掉了长久以来的威胁古斯塔沃 ...
- Java并发编程的艺术(十)——线程池(1)
线程池的作用 减少资源的开销 减少了每次创建线程.销毁线程的开销. 提高响应速度 每次请求到来时,由于线程的创建已经完成,故可以直接执行任务,因此提高了响应速度. 提高线程的可管理性 线程是一种稀缺资 ...
- MECE分析法(Mutually Exclusive Collectively Exhaustive)
什么是MECE分析法? MECE,是Mutually Exclusive Collectively Exhaustive,中文意思是“相互独立,完全穷尽”. 也就是对于一个重大的议题,能够做到不重叠. ...
- asp.net为什么会产生app_offline.htm 这个文件,为什么删除后运行浏览器就不会报应用程序脱机
一般是发布的时候自动生成的.VS2008在发布程序的时候,会首先在网站目录中生成这个文件,并把该虚拟目录的首页设成这个文件. 这样你在发布程序的时候如果有人访问网站就会看到这个页面. 不影响发布.ap ...
- Linux Shell脚本入门--wget 命令用法详解
Linux Shell脚本入门--wget 命令用法详解 wget是在Linux下开发的开放源代码的软件,作者是Hrvoje Niksic,后来被移植到包括Windows在内的各个平台上.它有以下功能 ...
- [数学] 将长为L的木棒随机折成3段,则3段构成三角形的概率
1.题目 如题,将长为L的木棒随机折成3段,则3段构成三角形的概率是多少? 2.解析 这个与其说是编程题目,倒不如说是个数学题目.可能是你没有见过,或者没有过这种解题思想.(还是那句,一回生两回熟,类 ...
- Reverse Words in a String leetcode java
题目: Given an input string, reverse the string word by word. For example, Given s = "the sky is ...