zoj 1109 Language of FatMouse(字典树)

Language of FatMouse

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Time Limit: 10 Seconds     
Memory Limit: 32768 KB

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We all know that FatMouse doesn't speak English. But now he has to beprepared since our nation will join WTO soon. Thanks to Turing we havecomputers to help him.

Input Specification

Input consists of up to 100,005 dictionary entries, followed by a blankline, followed by a message of up to 100,005 words. Each dictionaryentry is a line containing an English word, followed by a space and a FatMouse word.No FatMouse word appears more than
once in thedictionary. The message is a sequence of words in the language of FatMouse,one word on each line. Each word in the input is a sequence of at most 10lowercase letters.

Output Specification

Output is the message translated to English, one word per line. FatMouse words not in the dictionary should be translated as "eh".

Sample Input

dog ogday
cat atcay
pig igpay
froot ootfray
loops oopslay

atcay
ittenkay
oopslay

Output for Sample Input

cat
eh

loops

题解：建科字典树，单词插入的结尾记录该单词相应的单词的下标，查询就可以。


#include<cstring>
#include<algorithm>
#include<cstdio>
#include<iostream>
#include<cstdlib>

#define N 100020

using namespace std;

char s[12];
char ans[N][12];

struct Trie {
    int id;
    struct Trie *nxt[26];
    Trie() {
        id=0;
        for(int i=0; i<26; i++) {
            nxt[i]=NULL;
        }
    }
};

void Trie_Inser(Trie *p,char s[],int id) {
    int i=0;
    Trie *q=p;
    while(s[i]) {
        int nx=s[i]-'a';
        if(q->nxt[nx]==NULL) {
            q->nxt[nx]=new Trie;
        }
        i++;
        q=q->nxt[nx];
    }
    q->id=id;
}

int Trie_Serch(Trie *p,char s[]) {
    Trie *q=p;
    int i=0;
    while(s[i]) {
        int nx=s[i]-'a';
        if(q->nxt[nx]==NULL)return 0;
        q=q->nxt[nx];
        i++;
    }
    return q->id;
}

int main() {
    //freopen("test.in","r",stdin);
    Trie *p=new Trie;
    int id=1;
    char a[40];
    while(1) {
        gets(a);
        if(a[0]=='\0')break;
        int l=0;
        int len=strlen(a);
        int i;
        for(i=0; i<len; i++) {
            if(a[i]==' ')break;
            ans[id][l++]=a[i];
        }
        ans[id][l]='\0';
        l=0;
        i++;
        for(; i<len; i++) {
            s[l++]=a[i];
        }
        s[l]='\0';
        //printf("%s %s\n",ans[id],s);
        Trie_Inser(p,s,id);
        id++;
    }
    while(~scanf("%s",s)) {
        id=Trie_Serch(p,s);
        if(id==0) {
            printf("eh\n");
        } else {
            printf("%s\n",ans[id]);
        }
    }
    return 0;
}