Given a collection of numbers, return all possible permutations.

For example,
[1,2,3] have the following permutations:
[1,2,3][1,3,2][2,1,3][2,3,1][3,1,2], and [3,2,1].

使用递归解决

class Solution {
public:
vector<bool> visit;
vector<int> num;
vector<vector<int> > res;
void dfs(int index , vector<int>& sub){
if(index == num.size()){
res.push_back(sub);
return;
} for(int i = ; i < num.size(); ++ i){
if(!visit[i]){
visit[i] = true;
sub[index] = num[i];
dfs(index+, sub);
visit[i] = false;
}
}
} vector<vector<int> > permute(vector<int> &num) {
this->num = num;
visit.resize(num.size(),false);
vector<int> sub(num.size(),);
dfs(,sub);
return res;
}
};

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