Description

Given a string s and a string t, check if s is subsequence of t.

You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).

A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, “ace” is a subsequence of “abcde” while “aec” is not).

Example 1:

s = “abc”, t = “ahbgdc”

Return true.

Example 2:

s = “axc”, t = “ahbgdc”

Return false.

My program:

从s和t的首端开始遍历比较字符是否相等即可,如果不等,则增加在t中的下标j位置;如果相等,则同时增加s中下标i和t中下标j。如果t中的指标位置增长到了t的末尾,而s中的指标还没有增长的末尾,则返回false。如果s中的指标先增长到了末尾,则返回true。

class Solution {
public:
bool isSubsequence(string s, string t) {
int i = 0, j = 0;
if (s.empty()) return true;
while(i<s.size() && j<t.size())
{
if(s[i] == t[j])
{
++i;
++j;
}
else
++j;
}
if (i<s.size()) return false;
else return true;
}
};

Simple C++ code:

bool isSubsequence(string s, string t) {
int si= 0;
for(int ti = 0; ti < t.size() && si < s.size(); ti++) {
if(t[ti] == s[si]) si++;
}
return si == s.size();
}

Leetcode392. Is Subsequence的更多相关文章

  1. [Swift]LeetCode392. 判断子序列 | Is Subsequence

    Given a string s and a string t, check if s is subsequence of t. You may assume that there is only l ...

  2. [LeetCode] Arithmetic Slices II - Subsequence 算数切片之二 - 子序列

    A sequence of numbers is called arithmetic if it consists of at least three elements and if the diff ...

  3. [LeetCode] Is Subsequence 是子序列

    Given a string s and a string t, check if s is subsequence of t. You may assume that there is only l ...

  4. [LeetCode] Wiggle Subsequence 摆动子序列

    A sequence of numbers is called a wiggle sequence if the differences between successive numbers stri ...

  5. [LeetCode] Increasing Triplet Subsequence 递增的三元子序列

    Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the ar ...

  6. [LeetCode] Longest Increasing Subsequence 最长递增子序列

    Given an unsorted array of integers, find the length of longest increasing subsequence. For example, ...

  7. 动态规划求最长公共子序列(Longest Common Subsequence, LCS)

    1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与 ...

  8. 【LeetCode】Increasing Triplet Subsequence(334)

    1. Description Given an unsorted array return whether an increasing subsequence of length 3 exists o ...

  9. CF724D. Dense Subsequence[贪心 字典序!]

    D. Dense Subsequence time limit per test 2 seconds memory limit per test 256 megabytes input standar ...

随机推荐

  1. 【记录一下】phpMyAdmin 4.5.0-beta1 发布,要求 PHP 5.5

    详情点击: [开源中国]http://www.oschina.net/news/65696/phpmyadmin-4-5-0-beta1 [phpMyAdmin]https://www.phpmyad ...

  2. spring融合activitymq-all启动报错的解决办法

    报错信息: nested exception is java.lang.NoSuchMethodError: org.springframework.core.annotation.Annotated ...

  3. 基于CentOS与VmwareStation10搭建Oracle11G RAC 64集群环境:3.安装Oracle RAC-3.6.集群管理命令

    3.6. 集群管理命令 3.6.1. RAC的启动与关闭 oracle rac默认会开机自启动,如需维护时可使用以下命令: 关闭: crsctl stop cluster 停止本节点集群服务 crsc ...

  4. nfs mount 故障 mount.nfs: access denied by server while mounting 10.0.100.208:/backup_usb

    生产环境: 服务端centos7.2,客户端:ubuntu16.04 挂载出现的故障: root@HDCtrl100:/mnt# mount -t nfs 10.0.100.208:/backup_u ...

  5. js同比例缩放图片

    function DrawImage(ImgD, FitWidth, FitHeight) { var image = new Image(); image.src = ImgD.src; if (i ...

  6. C# 操作mongodb 简单实例

    本实例主要简单的查询,新增,修改和删除操作,完整代码如下: using System; using System.Collections.Generic; using System.Text; usi ...

  7. Kinect 1.8 体感开发,手势,姿态(Pose) 捕捉判断方法以及一些辅方法

    using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.T ...

  8. C 实现strcmp,strcpy,strcat函数

    基于C语言的strcmp,strcpy,strcat函数的实现.C语言是一个程序猿的基础,一定要重视. char* strcat ( char * dst , const char * src ) { ...

  9. 编程算法 - 推断二叉树是不是平衡树 代码(C)

    推断二叉树是不平衡树 代码(C) 本文地址: http://blog.csdn.net/caroline_wendy 题目: 输入一颗二叉树的根结点, 推断该树是不是平衡二叉树. 二叉平衡树: 随意结 ...

  10. DEB方式在UBUNTU安装ODOO 8.0

    odoo在ubuntu最简单最快速安装方式是deb方式,基本无需再去改数据库配置文件,全自动化了,odoo中文网推荐新手采用此方法 1 安装数据库:sudo apt-get install postg ...