前言

 

【LeetCode 题解】系列传送门:  http://www.cnblogs.com/double-win/category/573499.html

 

1.题目描述

There are N gas stations along a circular route, where the amount of gas at station i is gas[i].

You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.

Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.

Note:
The solution is guaranteed to be unique.

2. 思路

题解: 与经典的最大字段和问题类似,采用贪心策略。

3. 解法

 1 class Solution {
2 public:
3 int canCompleteCircuit(vector<int> &gas, vector<int> &cost) {
4 int station = gas.size();
5 int i,sum=0,start=0,total=0;
6
7 for(i=0;i<station;i++)
8 gas[i]-=cost[i];
9
10 for(i=0;i<station;i++) total+=gas[i];
11 if(total<0) return -1;
12
13 // 与求最大子段和类似,使用贪心策略
14 for(i=0;i<station;i++)
15 {
16 sum+= gas[i];
17 if(sum<0)
18 {
19 start=i+1; // 如果当前和为负数,选择下一个元素作为起点
20 sum=0;
21 }
22 }
23 return start;
24 }
25 };

4. 相关题目

Maximum Subarray : http://www.cnblogs.com/double-win/p/3746672.html

作者:Double_Win

出处:   http://www.cnblogs.com/double-win/p/3746637.html

声明: 由于本人水平有限,文章在表述和代码方面如有不妥之处,欢迎批评指正~

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