leetcode 968. Binary Tree Cameras

968. Binary Tree Cameras

思路：如果子节点只能覆盖到父节点、当前节点，但是父节点可以覆盖到他的父节点、子节点、当前节点，所以从叶子节点往上考虑

0代表子节点没有被覆盖

1代表子节点被覆盖，但是子节点没有camera

2代表子节点被覆盖，子节点有camera

https://www.cnblogs.com/ethanhong/p/10200550.html

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int minCameraCover(TreeNode* root) {
        int sum = ;
        if(minCameraCover(root,sum) == )
            sum++;
        return sum;
    }
    int minCameraCover(TreeNode* root,int& sum){
        if(!root)
            return ;
        int left = minCameraCover(root->left,sum);
        int right = minCameraCover(root->right,sum);
        if(left ==  || right == ){
            sum++;
            return ;
        }
        else if(left ==  || right == )
            return ;
        else
            return ;
    }
};