Spoj-BITDIFF Bit Difference
Given an integer array of N integers, find the sum of bit differences in all the pairs that can be formed from array elements. Bit difference of a pair (x, y) is the count of different bits at the same positions in binary representations of x and y. For example, bit difference for 2 and 7 is 2. Binary representation of 2 is 010 and 7 is 111 (first and last bits differ in two numbers).
Input
Input begins with a line containing an integer T(1<=T<=100), denoting the number of test cases. Then T test cases follow. Each test case begins with a line containing an integer N(1<=N<=10000), denoting the number of integers in the array, followed by a line containing N space separated 32-bit integers.
Output
For each test case, output a single line in the format Case X: Y, where X denotes the test case number and Y denotes the sum of bit differences in all the pairs that can be formed from array elements modulo 10000007.
Example
Input:
1
4
3 2 1 4 Output:
Case 1: 22
求和:对任意一对数(a,b)二进制展开,这两个数有多少位是01不同的
把每一位拆开来,假设第i位是1的有bit[i]个,答案就是Σ2*bit[i]*(n-bit[i])
#include<cstdio>
#include<iostream>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<cmath>
#include<queue>
#include<deque>
#include<set>
#include<map>
#include<ctime>
#define LL long long
#define inf 0x7ffffff
#define pa pair<int,int>
#define mkp(a,b) make_pair(a,b)
#define pi 3.1415926535897932384626433832795028841971
#define mod 10000007
using namespace std;
inline LL read()
{
LL x=,f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
int n;
LL ans;
int a[];
int bit[];
inline void work(int cur)
{
n=read();
for (int i=;i<=n;i++)a[i]=read();
ans=;
memset(bit,,sizeof(bit));
for (int i=;i<=n;i++)
for (int j=;j<=;j++)
if (a[i] & (<<j))bit[j]++;
for (int j=;j<=;j++)
ans+=(LL)bit[j]*(n-bit[j])*;
printf("Case %d: %lld\n",cur,ans%mod);
}
int main()
{
int T=read(),tt=;
while (T--)work(++tt);
}
Spoj BITDIFF
Spoj-BITDIFF Bit Difference的更多相关文章
- SPOJ - BITDIFF: Bit Difference [神妙の预处理]
tags:[数学][预处理]题解:我们用一种巧妙的预处理姿势:记录下每一个数位上分别出现了多少个1.如果第i个数位上出现了cnt[i]个1,那么,在这个数位上产生的"差异值"为:2 ...
- POJ 1511 Invitation Cards / UVA 721 Invitation Cards / SPOJ Invitation / UVAlive Invitation Cards / SCU 1132 Invitation Cards / ZOJ 2008 Invitation Cards / HDU 1535 (图论,最短路径)
POJ 1511 Invitation Cards / UVA 721 Invitation Cards / SPOJ Invitation / UVAlive Invitation Cards / ...
- Java 堆内存与栈内存异同(Java Heap Memory vs Stack Memory Difference)
--reference Java Heap Memory vs Stack Memory Difference 在数据结构中,堆和栈可以说是两种最基础的数据结构,而Java中的栈内存空间和堆内存空间有 ...
- BZOJ 2588: Spoj 10628. Count on a tree [树上主席树]
2588: Spoj 10628. Count on a tree Time Limit: 12 Sec Memory Limit: 128 MBSubmit: 5217 Solved: 1233 ...
- SPOJ DQUERY D-query(主席树)
题目 Source http://www.spoj.com/problems/DQUERY/en/ Description Given a sequence of n numbers a1, a2, ...
- What's the difference between a stub and mock?
I believe the biggest distinction is that a stub you have already written with predetermined behavio ...
- SPOJ GSS3 Can you answer these queries III[线段树]
SPOJ - GSS3 Can you answer these queries III Description You are given a sequence A of N (N <= 50 ...
- 【填坑向】spoj COT/bzoj2588 Count on a tree
这题是学主席树的时候就想写的,,, 但是当时没写(懒) 现在来填坑 = =日常调半天lca(考虑以后背板) 主席树还是蛮好写的,但是代码出现重复,不太好,导致调试的时候心里没底(虽然事实证明主席树部分 ...
- [转载]Difference between <context:annotation-config> vs <context:component-scan>
在国外看到详细的说明一篇,非常浅显透彻.转给国内的筒子们:-) 原文标题: Spring中的<context:annotation-config>与<context:componen ...
随机推荐
- HDU 5418 Victor and World (可重复走的TSP问题,状压dp)
题意: 每个点都可以走多次的TSP问题:有n个点(n<=16),从点1出发,经过其他所有点至少1次,并回到原点1,使得路程最短. 思路: 给了很多重边,选最小的留下即可.任意点可能无法直接到达, ...
- Linux OpenGL 实践篇-13-geometryshader
几何着色器 几何着色器是位于图元装配和片元着色器之前的一个着色器阶段,是一个可选阶段.它的输入是一个图元的完整的顶点信息,通常来自于顶点着色器,但如果细分计算着色器启用的话,那输入则是细分计算着色器的 ...
- CPP-基础:C++拷贝构造函数详解
一. 什么是拷贝构造函数 首先对于普通类型的对象来说,它们之间的复制是很简单的,例如: ; int b = a; 而类对象与普通对象不同,类对象内部结构一般较为复杂,存在各种成员变量.下面看一个类对象 ...
- k8s framework
reference 1. k8s master framework master master 是k8s cluster运行着daemon服务:kube-apiserver, kube-schedul ...
- Bootstrap 静态控件
当您需要在一个水平表单内表单标签后放置纯文本时,请在 <p> 上使用 class .form-control-static. 实例: <!DOCTYPE html><ht ...
- VUE +element el-table运用sortable 拖拽table排序,实现行排序,列排序
Sortable.js是一款轻量级的拖放排序列表的js插件(虽然体积小,但是功能很强大) 项目需求是要求能对element中 的table进行拖拽行排序 这里用到了sorttable Sortable ...
- break、continue、exit、return的区别和对比
break.continue.exit.return的区别和对比 一:说明 break.continue在条件循环语句及循环语句(for.while.if等)中用于控制程序的走向:而exit则用于种植 ...
- 如何用纯 CSS 创作牛奶文字变换效果
效果预览 在线演示 按下右侧的"点击预览"按钮可以在当前页面预览,点击链接可以全屏预览. https://codepen.io/comehope/pen/MGNWOm 可交互视频教 ...
- CSS3中制作倒影box-reflect
目前仅在Chrome.Safari和Opera浏览器下支持 box-reflect:none | <direction> <offset>? <mask-box-imag ...
- PHPMailer中文乱码问题的解决方法
之前用PHPMailer帮人家开发了用于发邮件的网站,由于是英文客户,所以中文没怎么测试,最近反馈说 中文乱码! 其实,之前是有发现标题中会出现中文了乱码,已经通过相应的代码解决. 收到反馈之后,查看 ...