PS:http://stackoverflow.com/questions/16557677/difference-between-data-section-and-the-bss-section-in-c

The .bss section is guaranteed to be all zeros when the program is loaded into memory. So any global data that is uninitialized, or initialized to zero is placed in the .bss section. For example:

static int g_myGlobal = 0;     // <--- in .bss section

The nice part about this is, the .bss section data doesn't have to be included in the ELF file on disk (ie. there isn't a whole region of zeros in the file for the .bss section). Instead, the loader knows from the section headers how much to allocate for the .bss section, and simply zero it out before handing control over to your program.

Notice the readelf output:

[ 3] .data PROGBITS 00000000 000110 000000 00 WA 0 0 4
[ 4] .bss NOBITS 00000000 000110 000000 00 WA 0 0 4

.data is marked as PROGBITS. That means there are "bits" of program data in the ELF file that the loader needs to read out into memory for you. .bss on the other hand is marked NOBITS, meaning there's nothing in the file that needs to be read into memory as part of the load.


Example:

// bss.c
static int g_myGlobal = 0; int main(int argc, char** argv)
{
return 0;
}

Compile it with $ gcc -m32 -Xlinker -Map=bss.map -o bss bss.c

Look at the section headers with $ readelf -S bss

Section Headers:
[Nr] Name Type Addr Off Size ES Flg Lk Inf Al
[ 0] NULL 00000000 000000 000000 00 0 0 0
:
[13] .text PROGBITS 080482d0 0002d0 000174 00 AX 0 0 16
:
[24] .data PROGBITS 0804964c 00064c 000004 00 WA 0 0 4
[25] .bss NOBITS 08049650 000650 000008 00 WA 0 0 4
:

Now we look for our variable in the symbol table: $ readelf -s bss | grep g_myGlobal

37: 08049654     4 OBJECT  LOCAL  DEFAULT   25 g_myGlobal

Note that g_myGlobal is shown to be a part of section 25. If we look back in the section headers, we see that 25 is .bss.


To answer your real question:

Here in the above program I dont have any un-intialised data but the BSS has occupied 8 bytes. Why does it occupy 8 bytes ?

Continuing with my example, we look for any symbol in section 25:

$ readelf -s bss | grep 25
9: 0804825c 0 SECTION LOCAL DEFAULT 9
25: 08049650 0 SECTION LOCAL DEFAULT 25
32: 08049650 1 OBJECT LOCAL DEFAULT 25 completed.5745
37: 08049654 4 OBJECT LOCAL DEFAULT 25 g_myGlobal

The third column is the size. We see our expected 4-byte g_myGlobal, and this 1-byte completed.5745. This is probably a function-static variable from somewhere in the C runtime initialization - remember, a lot of "stuff" happens before main() is ever called.

4+1=5 bytes. However, if we look back at the .bss section header, we see the last column Al is 4. That is the section alignment, meaning this section, when loaded, will always be a multiple of 4 bytes. The next multiple up from 5 is 8, and that's why the .bss section is 8 bytes.


Additionally We can look at the map file generated by the linker to see what object files got placed where in the final output.

.bss            0x0000000008049650        0x8
*(.dynbss)
.dynbss 0x0000000000000000 0x0 /usr/lib/gcc/x86_64-redhat-linux/4.7.2/../../../../lib/crt1.o
*(.bss .bss.* .gnu.linkonce.b.*)
.bss 0x0000000008049650 0x0 /usr/lib/gcc/x86_64-redhat-linux/4.7.2/../../../../lib/crt1.o
.bss 0x0000000008049650 0x0 /usr/lib/gcc/x86_64-redhat-linux/4.7.2/../../../../lib/crti.o
.bss 0x0000000008049650 0x1 /usr/lib/gcc/x86_64-redhat-linux/4.7.2/32/crtbegin.o
.bss 0x0000000008049654 0x4 /tmp/ccKF6q1g.o
.bss 0x0000000008049658 0x0 /usr/lib/libc_nonshared.a(elf-init.oS)
.bss 0x0000000008049658 0x0 /usr/lib/gcc/x86_64-redhat-linux/4.7.2/32/crtend.o
.bss 0x0000000008049658 0x0 /usr/lib/gcc/x86_64-redhat-linux/4.7.2/../../../../lib/crtn.o

Again, the third column is the size.

We see 4 bytes of .bss came from /tmp/ccKF6q1g.o. In this trivial example, we know that is the temporary object file from the compilation of our bss.c file. The other 1 byte came from crtbegin.o, which is part of the C runtime.


Finally, since we know that this 1 byte mystery bss variable is from crtbegin.o, and it's named completed.xxxx, it's real name is completed and it's probably a static inside some function. Looking at crtstuff.c line 362 we find the culprit: a static _Bool completed inside of __do_global_dtors_aux().

[转] .bss段和.data段的区别的更多相关文章

  1. bss段和data段的区别

    一般情况下,一个程序本质上都是由 bss段.data段.text段三个组成的——本概念是当前的计算机程序设计中是很重要的一个基本概念.而且在嵌入式系统的设计中也非常重要,牵涉到嵌入式系统运行时的内存大 ...

  2. [转帖]浅谈程序中的text段、data段和bss段

    作者:百问科技链接:https://zhuanlan.zhihu.com/p/28659560来源:知乎著作权归作者所有.商业转载请联系作者获得授权,非商业转载请注明出处. 一般情况,一个程序本质上都 ...

  3. (深入理解计算机系统) bss段,data段、text段、堆(heap)和栈(stack)

    bss段: bss段(bss segment)通常是指用来存放程序中未初始化的全局变量的一块内存区域. bss是英文Block Started by Symbol的简称. bss段属于静态内存分配. ...

  4. 【转】(深入理解计算机系统) bss段,data段、text段、堆(heap)和栈(stack)

    bss段: bss段(bss segment)通常是指用来存放程序中未初始化的全局变量的一块内存区域. bss是英文Block Started by Symbol的简称. bss段属于静态内存分配. ...

  5. Linux中的段管理,bss段,data段,

    Linux 的段管理, BSS段(bss segment)通常是指用来存放程序中未初始化的全局变量的一块内存区域.BSS是英文Block Started by Symbol的简称.BSS段属于静态内存 ...

  6. [转] bss段、data段、text段

    1.前言 一个程序本质上都是由 BSS 段.DATA段.TEXT段三个组成的. 本文主要分编译时和运行时分别对 对data段 bss段 text段 堆 栈作一简要说明 2. 程序编译时概念说明 程序与 ...

  7. Text段、Data段和BSS段

    不同的compiler在编译的过程中对于存储的分配可能略有不同,但基本结构大致相同. 大体上可分为三段:Text段.Data段和BSS段. text段用于存放代码,通常情况下在内存中被映射为只读,但d ...

  8. 代码中函数、变量、常量 / bss段、data段、text段 /sct文件、.map文件的关系[实例分析arm代码(mdk)]

    函数代码://demo.c #include<stdio.h> #include<stdlib.h> , global2 = , global3 = ; void functi ...

  9. Linux段管理,BSS段,data段,.rodata段,text段

    近期在解决一个编译问题时,一直在考虑一个问题,那就是Linux下可执行程序执行时内存是什么状态,是依照什么方式分配内存并执行的.查看了一下资料.就此总结一下,众所周知.linux下内存管理是通过虚存管 ...

随机推荐

  1. Swift进阶

    概述 访问控制 Swift命名空间 Swift和ObjC互相调用 Swift和ObjC映射关系 Swift调用ObjC ObjC调用Swift 扩展—Swift调用C 反射 扩展—KVO 内存管理 循 ...

  2. Web学习资源及手册查询整理

    入门了解html.css.js.jQuery:http://www.w3school.com.cn/, bootstrap.nodejs.php.jQuery入门:http://www.runoob. ...

  3. 0.0C语言重点问题回顾

    左值和右值得区别:左值是用来表明变量的身份的,右值更加侧重于值本身: void*是个例外,它只有基地址没有类型信息,所以无法解引用. int *p = malloc(100); char *s = m ...

  4. 将CSS CLIP属性应用在:扩展覆盖效果

    我们想要展示如何利用CSS3 clip属性制作一种简单而整洁的扩展效果,当点击一个box元素时实现平稳过渡.这个想法是为了实现某种叠加效果,好像它实际上在各个元素的下面.点击其中一个元素将创建一个切断 ...

  5. underscorejs-pluck学习

    2.14 pluck 2.14.1 语法: _.pluck(list, key) 2.14.2 说明: pluck方法根据key对list数组中的每个对象进行检索,返回检索成功的属性值,否则返回und ...

  6. sql server 利用首字母拼音排序和笔画排序的语句

    --按笔画排序 select * from Student order by Sname COLLATE Chinese_PRC_Stroke_CS_AS_KS_WS --按字母拼音排序 select ...

  7. 关于自定义Adapter实现ListView的使用

    以下为使用BaseAdapter作扩展,自定义Adapter来使用ListView控件: 需要注意以下的几点: 1.自定义Adapter时,需要特别注意Adapter类中getView()方法覆盖,注 ...

  8. UVA1152 4Values whose Sum is 0

    Description The SUM problem can be formulated as follows: given four lists A, B, C, D of integer val ...

  9. C# 代码中 计算某个函数 或WebService 请求花费时间

    /// 计算请求所花费的时间 System.Diagnostics.Stopwatch watch = new System.Diagnostics.Stopwatch(); watch.Start( ...

  10. es6整理

    1.const和let let类似于var,不同的是let只在所在的代码段有效 for循环的计数器,就很合适使用let命令. let和var的区别: //变量i是var声明的,在全局范围内都有效.所以 ...