01 | Jewels and Stones
Question
You're given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
are letters. Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example:
Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:
Input: J = "z", S = "ZZ"
Output: 0
Note:
S
andJ
will consist of letters and have length at most 50.- The characters in
J
are distinct.
Answer One
class Solution { /**
* @param String $J
* @param String $S
* @return Integer
*/
function numJewelsInStones($J, $S) {
$Js = str_split($J);
$sum = 0;
foreach($Js as $v) {
$sum += substr_count($S, $v);
}
return $sum;
}
}
Answer Two
class Solution { /**
* @param String $J
* @param String $S
* @return Integer
*/
function numJewelsInStones($J, $S) {
// $Js = str_split($J);
$Ss = str_split($S);
$sum = 0;
$res = array_count_values($Ss);
foreach($res as $k => $v) {
if(strpos($J, $k) !== false) {
$sum += $v;
}
}
return $sum;
}
}
PHP 原生函数大法好...
01 | Jewels and Stones的更多相关文章
- LeetCode --> 771. Jewels and Stones
Jewels and Stones You're given strings J representing the types of stones that are jewels, and S rep ...
- Leetcode#771.Jewels and Stones(宝石与石头)
题目描述 给定字符串J 代表石头中宝石的类型,和字符串 S代表你拥有的石头. S 中每个字符代表了一种你拥有的石头的类型,你想知道你拥有的石头中有多少是宝石. J 中的字母不重复,J 和 S中的所有字 ...
- 【Leetcode】Jewels and Stones
Jewels and Stones Description You're given strings J representing the types of stones that are jewel ...
- 【Leetcode_easy】771. Jewels and Stones
problem 771. Jewels and Stones solution1: class Solution { public: int numJewelsInStones(string J, s ...
- 771. Jewels and Stones - LeetCode
Question 771. Jewels and Stones Solution 题目大意:两个字符串J和S,其中J中每个字符不同,求S中包含有J中字符的个数,重复的也算 思路:Set记录字符串J中的 ...
- codechef Jewels and Stones 题解
Soma is a fashionable girl. She absolutely loves shiny stones that she can put on as jewellery acces ...
- 771. Jewels and Stones
You're given strings J representing the types of stones that are jewels, and S representing the ston ...
- [Swift]LeetCode771. 宝石与石头 | Jewels and Stones
You're given strings J representing the types of stones that are jewels, and S representing the ston ...
- [LeetCode] Jewels and Stones 珠宝和石头
You're given strings J representing the types of stones that are jewels, and S representing the ston ...
随机推荐
- Red Black Tree 红黑树 AVL trees 2-3 trees 2-3-4 trees B-trees Red-black trees Balanced search tree 平衡搜索树
小结: 1.红黑树:典型的用途是实现关联数组 2.旋转 当我们在对红黑树进行插入和删除等操作时,对树做了修改,那么可能会违背红黑树的性质.为了保持红黑树的性质,我们可以通过对树进行旋转,即修改树中某些 ...
- Python 参数校验的进化
Python 函数参数魔法 事情的起因是感觉目前项目中的参数校验方法写的太简单了,很多时候需要在server层再if else处理,于是就动手准备写一个好用一点的,可以自定义校验参数规则的参数校验器, ...
- eclipse配置SVN
1.设置 maven 工程svn忽略target 最新maven写法忽略的文件,还需忽略target.*/logs. Windows -> Preferences -> Team -> ...
- 解决访问google的问题
我用的是360安全浏览器. 1.点击扩展,搜索goole 2.可以看到第一个就是谷歌访问助手 3.下载安装 4.点击永久激活之后它会提示你怎么做 5.大概是让你修改主页,修改主页是在选项里,第一个基本 ...
- Codeforces Round #383 (Div. 2) C. Arpa's loud Owf and Mehrdad's evil plan —— DFS找环
题目链接:http://codeforces.com/contest/742/problem/C C. Arpa's loud Owf and Mehrdad's evil plan time lim ...
- oracle查看锁表进程,杀掉锁表进程
查看锁表进程SQL语句1: select sess.sid, sess.serial#, lo.oracle_username, lo.os_user_name, ao ...
- 编译Thrift
按照 https://syslint.com/blog/tutorial/how-to-install-apache-thrift-on-ubuntu-14-04/ 进行, 编译时出现错误 make[ ...
- tcpdump 探测器分析
注:默认情况下,tcpdump临听它遇见的第一个网络接口,如果它选择了错误的接口,可以-i标志强行指定接口,如果DNS不能用,或者只是不希望tcpdump进行名字查找,请使用-n选项,这个选项(-n) ...
- c++再探string之eager-copy、COW和SSO方案
在牛客网上看到一题字符串拷贝相关的题目,深入挖掘了下才发现原来C++中string的实现还是有好几种优化方法的. 原始题目是这样的: 关于代码输出正确的结果是()(Linux g++ 环境下编译运行) ...
- 使用Axis2创建Web Service
Axis2是新一代Web Service开发工具,目前最新版本是1.5.本文主要介绍如何用Axis2创建Web Service. 首先下载二进制包和war包,将war包复制到Tomcat的webapp ...