1. Find Minimum in Rotated Sorted Array

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).

Find the minimum element.

You may assume no duplicate exists in the array.

Example 1:

Input: [3,4,5,1,2]
Output: 1

Example 2:

Input: [4,5,6,7,0,1,2]
Output: 0

二分查找

class Solution {
public:
int findMin(vector<int>& nums) {
// 特殊情况
if(nums.size() == 1)return nums[0];
int l = 0, r = nums.size()-1, mid;
if(nums[r] > nums[l])return nums[l];
//查找
while(l <= r){
mid = (l+r)/2;
//两种情况对应着断点
if(nums[mid] > nums[mid+1])return nums[mid+1];
if(nums[mid-1] > nums[mid])return nums[mid];
//调整两侧的范围
if(nums[mid] > nums[0]){
l = mid + 1;
}else{
r = mid - 1;
}
}
return -1;
}
};

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