Codeforces Beta Round #52 (Div. 2)
Codeforces Beta Round #52 (Div. 2)
http://codeforces.com/contest/56
A
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define eb emplace_back
#define maxn 1000005
#define rep(k,i,j) for(int k=i;k<j;k++)
typedef long long ll;
typedef unsigned long long ull; int n; int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
cin>>n;
map<string,int>mp;
mp["ABSINTH"]++;
mp["BEER"]++;
mp["BRANDY"]++;
mp["CHAMPAGNE"]++;
mp["GIN"]++;
mp["RUM"]++;
mp["SAKE"]++;
mp["TEQUILA"]++;
mp["VODKA"]++;
mp["WHISKEY"]++;
mp["WINE"]++;
string str;
int ans=;
for(int i=;i<=n;i++){
cin>>str;
int tmp=;
if(str[]>=''&&str[]<=''){
for(int j=;j<str.length();j++){
tmp=tmp*+str[j]-'';
}
if(tmp<) ans++;
}
else{
if(mp[str]) ans++;
}
}
cout<<ans<<endl;
}
B
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define eb emplace_back
#define maxn 1000005
#define rep(k,i,j) for(int k=i;k<j;k++)
typedef long long ll;
typedef unsigned long long ull; int n;
int a[];
int book[]; int main(){
#ifndef ONLINE_JUDGE
// freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
cin>>n;
int L=,R=;
int co=;
int cc=;
for(int i=;i<=n;i++) {
cin>>a[i];
if(a[i]!=i){
book[i]=;
if(L!=) R=i;
if(L==) L=i;
}
}
int pre=0x3f3f3f3f;
int flag=;
for(int i=;i<=n;i++){
if(book[i]){
if(pre<a[i]){
flag=;
}
pre=a[i];
}
}
if(flag) cout<<"0 0"<<endl;
else{
cout<<L<<" "<<R<<endl;
}
}
C
模拟
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define eb emplace_back
#define maxn 1000005
#define rep(k,i,j) for(int k=i;k<j;k++)
typedef long long ll;
typedef unsigned long long ull;
char S;
int n,ans;
string s[]; int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
while(cin>>S)
{
if(S=='.')
{
for(int i=;i<n;i++)
if(s[i]==s[n])
ans++;
s[n]="";
n--;
}
else
if(S==':' || S==',')
n++;
else
s[n]+=S;
}
cout<<ans<<endl;
}
D
DP +路径搜索,基础DP, 类似一道名为编辑距离的题目
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define eb emplace_back
#define maxn 1000005
#define rep(k,i,j) for(int k=i;k<j;k++)
typedef long long ll;
typedef unsigned long long ull; string s1,s2;
int dp[][]; void dfs(int i,int j){
if(i==&&j==) return;
if(i&&dp[i-][j]+==dp[i][j]){
dfs(i-,j);
cout<<"DELETE"<<" "<<j+<<endl;
}
else if(j&&dp[i][j-]+==dp[i][j]){
dfs(i,j-);
cout<<"INSERT"<<" "<<j<<" "<<s2[j-]<<endl;
}
else{
dfs(i-,j-);
if(s1[i-]!=s2[j-])
cout<<"REPLACE"<<" "<<j<<" "<<s2[j-]<<endl;
}
} int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
cin>>s1>>s2;
int len1=s1.length();
int len2=s2.length();
rep(i,,len1+) dp[i][]=i;
rep(i,,len2+) dp[][i]=i;
dp[][]=;
rep(i,,len1+){
rep(j,,len2+){
dp[i][j]=min(min(dp[i-][j],dp[i][j-])+,dp[i-][j-]+(s1[i-]!=s2[j-]));
}
}
cout<<dp[len1][len2]<<endl;
dfs(len1,len2);
}
E
DP 从后往前推,找出符合的距离 。想到逆向思路就很简单了
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define eb emplace_back
#define maxn 1000005
#define rep(k,i,j) for(int k=i;k<j;k++)
typedef long long ll;
typedef unsigned long long ull; int n;
struct sair{
int x,h,pos,num;
}a[]; bool cmp(sair a,sair b){
return a.x<b.x;
} bool cmp1(sair a,sair b){
return a.pos<b.pos;
} int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
cin>>n;
for(int i=;i<=n;i++){
cin>>a[i].x>>a[i].h;
a[i].pos=i;
a[i].num=;
}
sort(a+,a+n+,cmp);
for(int i=n-;i>=;i--){
int j=i+;
while(j<=n&&a[i].x+a[i].h>a[j].x){
a[i].num+=a[j].num;
j=a[j].num+j;
}
}
sort(a+,a+n+,cmp1);
for(int i=;i<=n;i++){
cout<<a[i].num<<" ";
} }
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