static int wing=[]()
{
std::ios::sync_with_stdio(false);
cin.tie(NULL);
return ;
}(); class Solution
{
public:
int findLengthOfLCIS(vector<int>& nums)
{
int sz=nums.size();
if(sz<)
return sz;
int count=;
int res=INT_MIN;
for(int i=;i<sz;i++)
{
if(nums[i]>nums[i-])
count++;
else
{
res=max(res,count);
count=;
}
}
return max(res,count);
}
};

扫描一遍,问题不大

674. Longest Continuous Increasing Subsequence的更多相关文章

  1. leetcode300. Longest Increasing Subsequence 最长递增子序列 、674. Longest Continuous Increasing Subsequence

    Longest Increasing Subsequence 最长递增子序列 子序列不是数组中连续的数. dp表达的意思是以i结尾的最长子序列,而不是前i个数字的最长子序列. 初始化是dp所有的都为1 ...

  2. 【Leetcode_easy】674. Longest Continuous Increasing Subsequence

    problem 674. Longest Continuous Increasing Subsequence solution class Solution { public: int findLen ...

  3. [LeetCode] 674. Longest Continuous Increasing Subsequence 最长连续递增序列

    Given an unsorted array of integers, find the length of longest continuous increasing subsequence. E ...

  4. LeetCode 674. Longest Continuous Increasing Subsequence (最长连续递增序列)

    Given an unsorted array of integers, find the length of longest continuous increasing subsequence. E ...

  5. [Leetcode]674. Longest Continuous Increasing Subsequence

    Given an unsorted array of integers, find the length of longest continuous increasing subsequence. E ...

  6. [LeetCode&Python] Problem 674. Longest Continuous Increasing Subsequence

    Given an unsorted array of integers, find the length of longest continuousincreasing subsequence (su ...

  7. 674. Longest Continuous Increasing Subsequence最长连续递增子数组

    [抄题]: Given an unsorted array of integers, find the length of longest continuous increasing subseque ...

  8. 674. Longest Continuous Increasing Subsequence@python

    Given an unsorted array of integers, find the length of longest continuous increasing subsequence (s ...

  9. LeetCode 674. Longest Continuous Increasing Subsequence最长连续递增序列 (C++/Java)

    题目: Given an unsorted array of integers, find the length of longest continuous increasing subsequenc ...

  10. [LC] 674. Longest Continuous Increasing Subsequence

    Given an unsorted array of integers, find the length of longest continuous increasing subsequence (s ...

随机推荐

  1. C++中的构造函数

    C++中的构造函数可以分为4类: (1)默认构造函数.以Student类为例,默认构造函数的原型为 Student()://没有参数 (2)初始化构造函数 Student(int num,int ag ...

  2. 二次注入的学习--Buy Flag(http://10.112.68.215:10002)

    这次有做一个二次注入的天枢CTF题目,算是完整地理解了一遍注入的知识.来,启航.   1.判断注入点     经过对题目的实践分析,知道注册时需要输入年龄大于18岁,但在登录后界面,年龄因为太大不能接 ...

  3. Codeforces Beta Round #27 (Codeforces format, Div. 2)

    Codeforces Beta Round #27 (Codeforces format, Div. 2) http://codeforces.com/contest/27 A #include< ...

  4. Django import相关

    from django.shortcuts import render,redirect from django.contrib.auth import authenticate,logout,log ...

  5. 【php 之根据函数名称动态调用该函数】

    解释函数:call_user_func()以及函数call_user_func_array() 对于PHP程序员而言,函数是再熟悉不过的事物了,毕竟我们整天都在和PHP内置函数以及我们自定义的函数打交 ...

  6. redis集群 与spring-data-redis 集成

    所遇到的坑:必须使用如下的jedis 版本与spring-data-redis 版本,才能够达到集群效果 .1.7版本以前是不支持集群的 <dependency> <groupId& ...

  7. python学习-名字管理

    记录代码片段 print("="*50) print(" 名片管理系统 v0.01") print("1. 添加一个新的名片") print ...

  8. Vue 局部组件和全局组件的使用

    <template> <div id="app"> <!--<img alt="Vue logo" src="./ ...

  9. python 面向对象编程 之 析构方法

    析构方法:当对象在内存中被释放的时候,自动触发执行 如果产生的对象仅仅只是用户级别的, 那么无需定义__del__,如果对象还会向操作系统发生系统调用, 即一个对象有用户级别与内核级两种资源, 比如打 ...

  10. react-router4 第一篇

    无奈,英语4级没过,只能靠猜了.. 首先就是安装了 npm install --save-dev react npm install --save-dev react-dom npm install ...