PAT甲级——1041 Be Unique
Being unique is so important to people on Mars that even their lottery is designed in a unique way. The rule of winning is simple: one bets on a number chosen from [1,104]. The first one who bets on a unique number wins. For example, if there are 7 people betting on { 5 31 5 88 67 88 17 }, then the second one who bets on 31 wins.
Input Specification:
Each input file contains one test case. Each case contains a line which begins with a positive integer N (≤105) and then followed by N bets. The numbers are separated by a space.
Output Specification:
For each test case, print the winning number in a line. If there is no winner, print None instead.
Sample Input 1:
7 5 31 5 88 67 88 17
Sample Output 1:
31
Sample Input 2:
5 888 666 666 888 888
Sample Output 2:
None
#include <iostream>
#include <string>
using namespace std;
int main(void)
{
int a[100001] = {0};
int b[100001] = {0};//用来区别该数字是否重复出现
int n,flag=0;
cin >> n;
for (int i = 0; i < n; i++)
{
cin >> a[i];
b[a[i]]++;
}
for (int i = 0; i < n; i++)
{
if (b[a[i]] == 1)
{
cout << a[i] << endl;
return 0;
}
}
if (flag == 0)
cout << "None" << endl;
return 0;
}
PAT甲级——1041 Be Unique的更多相关文章
- PAT 甲级 1041 Be Unique (20 分)
1041 Be Unique (20 分) Being unique is so important to people on Mars that even their lottery is desi ...
- PAT 甲级 1041 Be Unique (20 分)(简单,一遍过)
1041 Be Unique (20 分) Being unique is so important to people on Mars that even their lottery is de ...
- PAT 甲级 1041 Be Unique
https://pintia.cn/problem-sets/994805342720868352/problems/994805444361437184 Being unique is so imp ...
- PAT 甲级 1041. Be Unique (20) 【STL】
题目链接 https://www.patest.cn/contests/pat-a-practise/1041 思路 可以用 map 标记 每个数字的出现次数 然后最后再 遍历一遍 找到那个 第一个 ...
- PAT甲 1041. Be Unique (20) 2016-09-09 23:14 33人阅读 评论(0) 收藏
1041. Be Unique (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Being uniqu ...
- 【PAT】1041. Be Unique (20)
题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1041 题目描述: Being unique is so important to people ...
- PAT Advanced 1041 Be Unique (20 分)
Being unique is so important to people on Mars that even their lottery is designed in a unique way. ...
- PAT甲级——A1041 Be Unique
Being unique is so important to people on Mars that even their lottery is designed in a unique way. ...
- PAT Advanced 1041 Be Unique (20) [Hash散列]
题目 Being unique is so important to people on Mars that even their lottery is designed in a unique wa ...
随机推荐
- 使用util包里自带的接口和类实现观察者模式
之前的关于观察者模式的文章,是用自己写的Observable接口和Observer接口,然后进行实现.其实官方的util包下自带有实现观察者模式对应的接口和类,可以简化我们的代码结构. 比如我们可以直 ...
- git登录账号密码错误remote: Incorrect username or password (access token)
git提交时弹框让输入用户和密码,不小心输入错误了 再次提交 一直就提示 remote: Incorrect username or password 错误了,也不弹框要重新输入 解决方法 win1 ...
- 关于Vue element-ui中诡异问题的解决思路
最近在做Element-ui项目时总是会出现些异步及其一些诡异问题,关于vue 的异步原理就不多说了,感觉大部分的问题都可以用Vue.nextTick来解决,Vue.nextTick是等DOM二次加载 ...
- SpringCloud学习之Config分布式配置中心(八)
统一配置中心概述 如果微服务架构中没有使用统一配置中心时,所存在的问题: 配置文件分散在各个项目里,不方便维护 配置内容安全与权限,实际开发中,开发人员是不知道线上环境的配置的 更新配置后,项目需要重 ...
- 13. react 基础 redux 的基本介绍 及 用 antd 编写 TodoList 的样式
1. redux 简述 当 store 内的 数据进行变更的时候 多个组件感知到 store 内的数据变化 将会被自动更新 2. redux 工作流 Store 代表数据存储 (例如: 图书馆管理 ...
- 78.objects对象所属类原理分析
def index3(request): # 查找文章题目中包含中国的文章分类 category = Category.objects.filter(article__title__contains= ...
- IP欺骗(XFF头等)
很多时候需要伪造一些http头来绕过WAF 1.X-Forwarded-For: 简称XFF头,它代表客户端,也就是HTTP的请求端真实的IP,只有在通过了HTTP 代理或者负载均衡服务器时才会添加该 ...
- Leetcode第1题:两数之和
给定一个整数数组 nums 和一个目标值 target,请你在该数组中找出和为目标值的 两个 整数.你可以假设每种输入只会对应一个答案.但是,你不能重复利用这个数组中同样的元素.示例:给定 nums ...
- MySQL--通过.frm和.ibd对mysql数据恢复
转载:http://bbs.csdn.net/topics/392114182 例如说 现在要恢复user表1.先建立和之前user表一样的表结构.就是执行create table user .... ...
- Java面向对象(概述,构造函数,类与对象的关系,this关键字,成员、局部),匿名对象的调用,构造代码块(5)
Java面向对象(概述,构造函数,类与对象的关系,this关键字,成员.局部),匿名对象的帝爱用,构造代码块(5)