Pleasant sheep and big big wolf HDU - 3046（最小割）

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Pleasant sheep and big big wolf HDU - 3046（最小割）

Pleasant sheep and big big wolf Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3316 Accepted Submission(s): 1360 Problem Description In ZJNU, there is a well-known prairie. And it attracts p…

hdu 3046 最小割

每个栅栏其实就是一条边,修一些栅栏,使得狼不能抓到羊,其实就是求一个割,使得羊全在S中,狼全在T中. #include <cstdio> #include <cstring> #include <vector> #include <queue> #define maxn 40010 #define oo 0x3f3f3f3f #define clr(arr,n) memset(&arr,0,sizeof(arr[0])*(n+1)) using na…

HDU 3046Pleasant sheep and big big wolf（切最小网络流）

职务地址:HDU 3046 最小割第一发!事实上也没什么发不发的. ..最小割==最大流.. 入门题,可是第一次入手最小割连入门题都全然没思路... sad..对最小割的本质还是了解的不太清楚.. 这题就是对每两个相邻的格子的边界都要进行加边,然后求最大流就OK了. RE了好长时间,注意遍历加边的时候要从1開始,而不是0開始,由于0是源点的.. .(或许仅仅有我才犯这样的错误吧. . .)建图不多说了..仅仅要了解了最小割,建图还是非常easy想的. 代码例如以下: #include <iost…

HDU 3046 Pleasant sheep and big big wolf（最小割）

HDU 3046 Pleasant sheep and big big wolf 题目链接题意:一个n * m平面上,1是羊.2是狼,问最少要多少围墙才干把狼所有围住,每有到达羊的路径思路:有羊和狼.要分成两个集合互不可达.显然的最小割.建图源点连狼,容量无穷,羊连汇点,容量无穷.然后相邻格子连边.容量为1 代码: #include <cstdio> #include <cstring> #include <queue> #include <algorithm…

HDU 3046 Pleasant sheep and big big wolf

Pleasant sheep and big big wolf Time Limit: 1000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 304664-bit integer IO format: %I64d Java class name: Main In ZJNU, there is a well-known prairie. And it attracts pleas…

hdu 3046 Pleasant sheep and big big wolf 最小割

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3046 In ZJNU, there is a well-known prairie. And it attracts pleasant sheep and his companions to have a holiday. Big big wolf and his families know about this, and quietly hid in the big lawn. As ZJNU A…