POJ 1052 Plato's Blocks】的更多相关文章

  Plato's Blocks Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 734   Accepted: 296 Description Plato believed what we perceive is but a shadow of reality. Recent archaeological excavations have uncovered evidence that this belief may h…
题目来源:http://poj.org/problem?id=1052 题目大意: 把1*1*1的小立方体通过粘接相邻面组成大的立方体的形状.如下图所示: 一层一层地堆叠,立方体从三个方向的投影会分别形成三个字母的形状:"E" "G" "B" 科学家们想知道哪些投影形状的组合是可能出现的.写一个程序判断给定的投影图形组合是否可能出现. 输入:由一系列数据集组成.每个用例第一行为一个整数n(1<=n<=20),表示大立方体的边长.接下来…
Tiling Up Blocks Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4675   Accepted: 1824 Description Michael The Kid receives an interesting game set from his grandparent as his birthday gift. Inside the game set box, there are n tiling bl…
MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5547   Accepted: 3458 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…
POJ 排序的思想就是根据选取范围的题目的totalSubmittedNumber和totalAcceptedNumber计算一个avgAcceptRate. 每一道题都有一个value,value = acceptedNumber / avgAcceptRate + submittedNumber. 这里用到avgAcceptedRate的原因是考虑到通过的数量站的权重可能比提交的数量占更大的权重,所以给acceptedNumber乘上了一个因子. 当然计算value还有别的方法,比如POJ上…
acm之pku题目分类 对ACM有兴趣的同学们可以看看 DP:  1011   NTA                 简单题  1013   Great Equipment     简单题  1024   Calendar Game       简单题  1027   Human Gene Functions   简单题  1037   Gridland            简单题  1052   Algernon s Noxious Emissions 简单题  1409   Commun…
以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…
A POJ 1018 Communication System B POJ 1050 To the Max C POJ 1083 Moving Tables D POJ 1125 Stockbroker Grapevine E POJ 1143 Number Game F POJ 1157 LITTLE SHOP OF FLOWERS G POJ 1163 The Triangle H POJ 1178 Camelot I POJ 1179 Polygon J POJ 1189 钉子和小球 K…
poj 1390 Blocks 题意 一排带有颜色的砖块,每一个可以消除相同颜色的砖块,,每一次可以到块数k的平方分数.问怎么消能使分数最大.. 题解 此题在徐源盛<对一类动态规划问题的研究>以及刘汝佳的黑书<算法艺术与信息学竞赛>中都有提及. 首先我们要将相同颜色块进行合并.定义状态\(dp[i][j][k]\)表示第\(i\)到第\(j\)个颜色块后面接了\(k\)个颜色为\(color[j]\)的砖块. 不难得出转移方程为\(dp[i][j][k]=max \{ dp[i][…
Blocks Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 3997   Accepted: 1775 Description Panda has received an assignment of painting a line of blocks. Since Panda is such an intelligent boy, he starts to think of a math problem of paint…