Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a…

Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.The input string does not contain leading or trailing spaces and the words are always separated by a single space.For example,Given s = "t…

Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…

题目描述 给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序. 示例 1: 输入: "Let's take LeetCode contest" 输出: "s'teL ekat edoCteeL tsetnoc" 注意:在字符串中,每个单词由单个空格分隔,并且字符串中不会有任何额外的空格. 思路 分割字符串,再逆序,拼接到字符串 代码实现 package String; /** * 557. Reverse Words in a St…

一年没有管理博客园了,说来实在惭愧.. 最近开始刷LeetCode,之前没刷过,说来也实在惭愧... 刚开始按 AC Rates 从简单到难刷,觉得略无聊,就决定按 Add Date 刷,以后也可能看心情随便选题…(⊙o⊙)…今天做了14年 Add 的三个题,其中 Maximum Product Subarray 着实把我折腾了好一会儿,所以想想还是跟大家分享一下我的解法,也或许有更好的方法,期待大家的分享.就把三个题按 Add Date 的先后顺序分享一下吧. Add Date 2014-03…

557. Reverse Words in a String III 最简单的把空白之间的词反转 class Solution { public: string reverseWords(string s) { vector<int> blank; ;i < s.size();i++){ if(s[i] == ' ') blank.push_back(i); } ; int end; ;i < blank.size();i++){ end = blank[i] - ; revers…

Question: Reverse Words in a String Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Clarification: What constitutes a word?A sequence of non-space characters con…

Write a function that takes a string as input and reverse only the vowels(元音字母) of a string. Example 1:Given s = "hello", return "holle". Example 2:Given s = "leetcode", return "leotcede". Note:The vowels does not i…

今天第一次在leetcode上提交了一个题目,据说这个网站基本上都是名企面试笔试题,今天无意一进去就看到第一题居然就是昨天的腾讯实习生笔试题,赶紧注册了个账号做题. 题目描述: Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the".   很简单的英文就不翻译了.题目不难但是做这个题…

题目描述: Write a function that takes a string as input and reverse only the vowels of a string. Example 1:Given s = "hello", return "holle". Example 2:Given s = "leetcode", return "leotcede". Note:The vowels does not i…

Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…

1.题目描述 Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc…

1. 题目:https://leetcode.com/problems/reverse-words-in-a-string-iii/discuss/ 反转字符串中的所有单词. 2. 思路: 这题主要是要注意空格的影响.比方说,string首尾和单词之间可能有一或多个空格.看到有人逐个对空格判断,但是我觉得逐个判断其实稍微容易出错(当然如果非常熟悉的话就完全无所谓啦),我的一个简单想法是用stringstream. PS:不熟悉stringstream的朋友可以看看链接的文档. 3. 代码 cla…

Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…

问题描述: Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". 解题思路: 先利用split()方法将句子按空格分为几个单词的列表, 然后reverse()函数使列表逆序, 最后join函数以空格为间隔拼成字符串返回结果. Python代码: class Solution:  …

Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example,Given s =…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a word?A sequence of n…

Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 解题思路: 本题方法多多,最简单的方式直接按“ ” spilt即可,JAVA实现如下: public String reverseWords(String s) { if (s == null || s.length()…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. 倒序字符串. 注意使用BufferString,因为如果使用Stri…

1.(原文)问题描述 Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". click to show clarification. Clarification: What constitutes a word? A sequence of non-space charact…

题目: Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example,Given…

题目要求 Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. 题目分析及思路 题目给出一个字符串,要求将每个词中的字母顺序颠倒,但仍旧保留空格和原先的词序.可以用.split()方法将词分开并遍历,最后倒序并组成新的字符串. python代码 class…

Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc" 解:输入一堆字符串,每一个空格之前的字符串都要反转,拆成一个数组反转之后拼成一个字符串 let array = s.split(' '); let newArr = []; for(let i = 0; i < array.length; i++){ let str = array[i].split("…

Given an input string, reverse the string word by word. Example: Input: "the sky is blue",Output: "blue is sky the".Note: A word is defined as a sequence of non-space characters.Input string may contain leading or trailing spaces. Howe…

Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". Update (2015-02-12): For C programmers: Try to solve it in-place in O(1) space. 这题遇到的困难主要是细节地方处理的不好:(1)空格的处理,(2…

题目: Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". 代码:oj在线测试通过 Runtime: 172 ms class Solution: # @param s, a string # @return a string def reverseWords(self, s)…

题意:给定一个字符串,反转字符串中的元音字母. 例如: Input: "leetcode" Output: "leotcede" 法一:双指针 class Solution { public: string reverseVowels(string s) { if(s == "") return ""; set <char> st ={'a','e','i','o','u','A','E','I','O','U'}…

题意:倒置字符串中的元音字母. 用两个下标分别指向前后两个相对的元音字母,然后交换. 注意:元音字母是aeiouAEIOU. class Solution { public: bool isVowels(char c){ string Vowels = "aeiouAEIOU"; ; i < Vowels.size(); ++i){ if(c == Vowels[i]) return true; } return false; } string reverseVowels(str…

原题地址 将单词按空格分词,然后倒序拼接即可 代码: void reverseWords(string &s) { vector<string> words; ; ; ; i < s.length(); i++) { if (s[i] == ' ') { ) words.push_back(s.substr(start, len)); len = ; } else { ) { start = i; len = ; } else len++; } } ) words.push_ba…

两个for 第一个for将每一个元音依次存放进一个char数组 第二个for,每检测到元音,就从char数尾部开始,依次赋值 如何检测元音呢?当然写一个冗长的if(),不过我们有更好的选择 hashset的contains, 或者String自带的contains, 或者建一个int[128],因为元音有5个,算上大小写,一共10个,他们的ascii值都在128以内,然后将元音对应的int[]值设为1,其它设为0,只要检测int[strs[i]] ?= 0即可判断是否为元音 class Solu…