Java Word Break(单词拆解)

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Java Word Break(单词拆解)

给定一个字符串 String s = "leetcode" dict = ["leet", "code"]. 查看一下是够是字典中的词语组成.假设是返回true,否则返回false. 下边提供3种思路 1.动态算法 import java.util.HashSet; import java.util.Set; public class WordBreak1 { public static void main(String[] args) { //…

[LeetCode] 139. Word Break 单词拆分

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Note: The same word in the dictionary may be reused multiple t…

139 Word Break 单词拆分

给定一个非空字符串 s 和一个包含非空单词列表的字典 wordDict,确定 s 是否可以被空格分割为一个或多个在字典里出现的单词.你可以假设字典中无重复的单词.例如,给出s = "leetcode",dict = ["leet", "code"].返回 true 因为 "leetcode" 可以被切分成 "leet code". 详见:https://leetcode.com/problems/word-…

LeetCode 139. Word Break单词拆分 (C++)

题目: Given a non-empty string s and a dictionary wordDict containing a list of non-emptywords, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Note: The same word in the dictionary may be reused multipl…

[leetcode]139. Word Break单词能否拆分

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words. Note: The same word in the dictionary may be reused multiple t…

Leetcode139. Word Break单词拆分

给定一个非空字符串 s 和一个包含非空单词列表的字典 wordDict,判定 s 是否可以被空格拆分为一个或多个在字典中出现的单词. 说明: 拆分时可以重复使用字典中的单词. 你可以假设字典中没有重复的单词. 示例 1: 输入: s = "leetcode", wordDict = ["leet", "code"] 输出: true 解释: 返回 true 因为 "leetcode" 可以被拆分成 "leet cod…

[LeetCode] 140. Word Break II 单词拆分II

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. Note: The same word in the dictionary m…