问题 给出一个元素以递增序列排序的单链表,将其转换为一棵高度平衡的二叉搜索树. 初始思路 二叉搜索树高度平衡,意味着左右子树的高度要平衡.根据二叉树左子树节点小于根节点,右子树节点大于根节点的性质:我们在待选节点中选择值为中位数的节点作为根节点,所有小于中位数的节点作为左子树,所有大于中位数的节点作为右子树,即可满足高度平衡的要求.由于题目给出的已经是排好序的单链表,我们只要每次选择中间的节点即可.然后通过递归处理左右子树,最终完成高度平衡二叉搜索树的构建. 最终完成代码如下: class So…

108. 将有序数组转换为二叉搜索树 108. Convert Sorted Array to Binary Search Tree 题目描述 将一个按照升序排列的有序数组,转换为一棵高度平衡二叉搜索树. 本题中,一个高度平衡二叉树是指一个二叉树每个节点的左右两个子树的高度差的绝对值不超过 1. 每日一算法2019/5/17Day 14LeetCode108. Convert Sorted Array to Binary Search Tree 示例: 给定有序数组: [-10,-3,0,5,9…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…

[题目] 给出的升序排序的数组,个数必为奇数,要求形成二叉搜索(平衡)树. [思路] 辅助函数fun,[0,len]=>[0,mid-1]+[mid+1,len]. 当left>right,返回null. public TreeNode fun(int[] nums,int left,int right) { int mid=(right+left)/2; TreeNode tmp=new TreeNode(nums[mid]); if(right<left) return null;…

Medium! 题目描述: 给定一个单链表,其中的元素按升序排序,将其转换为高度平衡的二叉搜索树. 本题中,一个高度平衡二叉树是指一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过 1. 示例: 给定的有序链表: [-10, -3, 0, 5, 9], 一个可能的答案是:[0, -3, 9, -10, null, 5], 它可以表示下面这个高度平衡二叉搜索树: 0 / \ -3 9 / / -10 5 解题思路: 这道题是要求把有序链表转为二叉搜索树,和之前那道Convert Sorted…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要求把有序链表转为二叉搜索树,和之前那道Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树思路完全一样,只不过是操作的数据类型有所差别,一个是数组,一个是链表.数组方便就方便在可以通过index直接访问任意一个元…

Convert Sorted List to Binary Search Tree Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 为了满足平衡要求,容易想到提出中间节点作为树根,因为已排序,所以左右两侧天然满足BST的要求. 左右子串分别递归下去,上层根节点连接下层根节点即可完成. 递归找中点,然后断开前后两段链表,并继续找…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…