USACO Stock Market】的更多相关文章

洛谷 P2938 [USACO09FEB]股票市场Stock Market 洛谷传送门 JDOJ 2625: USACO 2009 Feb Gold 2.Stock Market JDOJ传送门 题目描述 Despite their innate prudence, the cows took a beating in the home mortgage market and now are trying their hand at stocks. Happily, Bessie is pres…
USACO 2009 Feb 股票市场 Stock Market Description 尽管奶牛们天生谨慎,她们仍然在住房抵押信贷市场中大受打击,现在她们准备在股市 上碰碰运气.贝西开挂了,她知道S只股票在今后D天内的价格. 假设她一开始有M元钱,怎么操作才能在D天后赚到最多的钱?股票在市场上的供应量 可以看成是无限的,但买卖股票必须以整数为最小交易单位. 举一个牛市的例子.假设贝西有10元本金,股票价格如下: 股票 今天的单价 明天的单价 后天的单价 A 10 15 15 B 13 11 2…
我们假设每天买完第二天就卖掉( 不卖出也可以看作是卖出后再买入 ), 这样就是变成了一个完全背包问题了, 股票价格为体积, 第二天的股票价格 - 今天股票价格为价值.... 然后就一天一天dp... --------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm> #include<iostre…
1578: [Usaco2009 Feb]Stock Market 股票市场 Time Limit: 10 Sec  Memory Limit: 64 MBSubmit: 414  Solved: 199[Submit][Status][Discuss] Description 尽管奶牛们天生谨慎,她们仍然在住房抵押信贷市场中受到打击,现在她们开始着手于股市. Bessie很有先见之明,她不仅知道今天S (2 <= S <= 50)只股票的价格,还知道接下来一共D(2 <= D <…
Around September of 2016 I wrote two articles on using Python for accessing, visualizing, and evaluating trading strategies (see part 1 and part 2). These have been my most popular posts, up until I published my article on learning programming langua…
Using the latest advancements in AI to predict stock market movements 2019-01-13 21:31:18 This blog is copied from: https://github.com/borisbanushev/stockpredictionai In this notebook I will create a complete process for predicting stock price moveme…
Stock Market 股票市场 bzoj-1578 Usaco-2009 Feb 题目大意:给定一个$S\times D$的大矩阵$T$,其中$T[i][j]$表示第i支股票第j天的价格.给定初始资金$M$,求最后的最大收益. 注释:$1\le S\le 50$,$1\le D\le 10$,$1\le M\le 2\cdot 10^5$,$1\le val_i\le 10^4$. 想法: 我们如果前几天买股票然后过几天卖掉等价于第一天买第二天卖掉然后持续到今天. 也就是持续的买卖到今天.…
Stock Market Indices USA Africa Asia and Pacific Canada Europe Middle East South America International BBC Global 30 - world stock market index of 30 of the largest companies by stock market value in Europe, Asia and the Americas. iShares MSCI EAFE I…
Question: Let us suppose we have an array whose ith element gives the price of a share on the day i.If you were only permitted to buy one share of the stock and sell one share of the stock, design an algorithm to find the best times to buy and sell.…
[题意]给定s个股票和d天,给出价格矩阵s*d,每天可以买入或卖出整数倍股票,初始资金m,求最大利益.m<=200000,s<=50,d<=10. [算法]完全背包 [题解]关键在于转化:第一天买入-第三天卖出,相当于,第一天买入-第二天卖出-第二天买入-第三天卖出.那么买卖股票就变成相邻两天的事情了. 对于每一天,就是完全背包,总重量为资金,重量为当天价格,价值为第二天价格-当天价格. f[i][j]表示前i个股票使用资金j能获得的最大收益. f[i][j]=f[i-1][j-A[i]…
传送门:http://www.lydsy.com/JudgeOnline/problem.php?id=1578 [题解] 由于连续买相当于每天买,第二天卖,然后再买.所以每天最后钱尽量多一定是最优的. 所以对于m天,每天做一次O(n*70w)的完全背包dp即可. # include <stdio.h> # include <string.h> # include <iostream> # include <algorithm> // # include &…
传送门 可以看出 第一天买,第三天卖 == 第一天买,第二天卖完再买,第三天卖 所以我们只考虑前一天买,后一天卖即可 那么有按天数来划分 f[i][j]表示前i天,共有j元,最大的盈利 第一维可以省去 那么有两种选择,不买 或者 前一天买,后一天卖 #include <cstdio> #include <cstring> #include <iostream> #define N 500001 #define max(x, y) ((x) > (y) ? (x)…
参考:https://blog.csdn.net/mars_ch/article/details/53011234 我背包真是好不熟练啊-- 第一天买了第三天卖相当于第一天买了第二天卖第二天再买第三天再卖.所以问题转化成完全背包,每天转移即可 #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> using namespace std; const int N=55…
Code: #include<cstdio> #include<algorithm> #include<iostream> #include<cstring> #include<stack> #include<string> using namespace std; void setIO(string a){ freopen((a+".in").c_str(),"r",stdin),freope…
题意简述: 给定⼀个DDD天的SSS只股票价格矩阵,以及初始资⾦ MMM:每次买股票只能买某个股票价格的整数倍,可以不花钱,约定获利不超过500000500000500000.最⼤化你的 总获利. 题目分析: 首先我们要知道此题的详细意图:每天都可以用你手中有的钱买入股票,数量不限,也可以卖出你自己的股票,所得的收益或价值已经在D∗SD*SD∗S的矩阵中给出.要求在最后一天结束后得到的钱最多. 题解: 其实我们可以发现:对于每一天只要最大化你的收益就可以达成目的.然后问题就转换为求每一天的股票交…
第n天不卖,视为卖了又原价买回 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define R(a,b,c) for(register int a = (b); a <= (c); ++ a) #define nR(a,b,c) for(register int a = (b); a >=…
UPD:我真不是想骗访问量TAT..一开始没注意总长度写着写着网页崩了王仓(其实中午的时候就时常开始卡了= =)....损失了2h(幸好长一点的都单独开了一篇)....吓得赶紧分成两坨....TAT.............. —————————————————————————————————————————————————————————————————————————————— 写(被虐)了整整一个月b站上usaco的金组题...然而到现在总共只写了100道上下TAT(当然是按AC人数降序排…
#include<bits/stdc++.h> using namespace std; #define ll long long #define pi (4*atan(1.0)) #define eps 1e-14 ,M=4e6+,inf=1e9+,mod=1e9+; ; struct is { int x; int pos; }a[N]; int cmp1(is a,is b) { if(a.x!=b.x) return a.x<b.x; return a.pos<b.pos;…
Stock market volatility continues unabated. It may be too early to tell, but I’m marking the top of this current market correction at July 20, with the bottom still to be determined (though I’d say it’s still a few weeks off). Since July 20, investor…
Stock Chase Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 455   Accepted: 131 Description I have to admit, the solution I proposed last year for solving the bank cash crisis didn’t solve the whole economic crisis. As it turns out, comp…
第一眼看到题目,感觉水水的,不就是最长下降子序列嘛!然后写……就呵呵了..要判重,还要高精度……判重我是在计算中加入各种判断.这道题比看上去麻烦一点,但其实还好吧.. #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #define rep(i,l,r) for(int i=l;i<r;i++) #define clr(x,c) memset(x,c,si…
Asia Stock Exchanges July 7, 2009 This article is to summarise the trading rules of some Asia stockexchanges. Those rules are very important to know if we need to developany trading system against those exchanges. 1. Hong Kong Stock Exchange 1.1 Orde…
Buy Low, Buy Lower The advice to "buy low" is half the formula to success in the stock market. But to be considered a great investor you must also follow this problems' advice: "Buy low, buy lower" That is, each time you buy a stock, y…
Stock Prices Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 987    Accepted Submission(s): 397 Problem Description Buy low, sell high. That is what one should do to make profit in the stock ma…
Optiver sponsored problem. After years of hard work Optiver has developed a mathematical model that allows them to predict wether or not a company will be succesful. This obviously gives them a great advantage on the stock market. In the past, Optive…
orz xhk 5/50 1597: [Usaco2008 Mar]土地购买 $ f[i]=min(f[j]+x[i]*y[j+1]) $ 然后斜率优化 1699: [Usaco2007 Jan]Balanced Lineup排队 silver里好像做过? 静态RMQ直接上st表 1578: [Usaco2009 Feb]Stock Market 股票市场 看成完全背包.对于每天都搞一下完全背包 1574: [Usaco2009 Jan]地震损坏Damage 语文题QwQ.大力搜索,代码: #i…
听说KPM初二暑假就补完了啊%%% 先刷Gold再刷Silver(因为目测没那么多时间刷Silver,方便以后TJ2333(雾 按AC数降序刷 ------------------------------------------------------------------------------------------------------- bzoj1597: [Usaco2008 Mar]土地购买  斜率优化DP h升序,w降序. f[i]=min(f[j]+h[i]*w[j+1])…
Stock Chase Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1201    Accepted Submission(s): 363 Problem Description I have to admit, the solution I proposed last year for solving the bank cash c…
bzoj 1606: [Usaco2008 Dec]Hay For Sale 购买干草——背包 #include<cstdio> #include<cstring> #include<algorithm> using namespace std; int read(){ ,f=,c=getchar(); ; c=getchar();} +(c-'); c=getchar();} return ans*f; } ],k; int main() { h=read(); n=…
POJ2279 Mr. Young's Picture Permutations 题意 Language:Default Mr. Young's Picture Permutations Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 2513 Accepted: 960 Description Mr. Young wishes to take a picture of his class. The students will…