$n \leq 200$个数,$ \leq 500$,$K \leq 1000$代价内的数字分组有多少?一个分组的代价是分成的每个小组的总代价:一个小组的代价是极差. 问的极差那就从极入手嘛.一个小组只有最大和最小值是有用滴!那就来分这些最大最小值. 由于考虑大小,不如先把数列排个序.这样的话,可以表示出那种“有几个小组分不满”的形似插头DP的状态,在移动到下一个数时代价加上当前数和下一个数的差乘上还没分配满的小组数即可.具体,$f(i,j,k)$表示前$i$个数$j$个小组还没满,当前代价$k…

Group Projects Description There are n students in a class working on group projects. The students will divide into groups (some students may be in groups alone), work on their independent pieces, and then discuss the results together. It takes the i…

F - Group Projects 题目大意:给你n个物品, 每个物品有个权值ai, 把它们分成若干组, 总消耗为每组里的最大值减最小值之和. 问你一共有多少种分组方法. 思路:感觉刚看到的时候的想法是先排好序, dp[ i ][ j ][ k ]表示已经划分了 i 个, 并且分成了 j 组, 目前为止的总消耗为k的方案总数. 但是这个状态没有办法转移, 题解提供了一种将贡献分段的方法, 比如说原数组为1 2 3 6 7 8 10, 其中一组里面有 1 3 7 8 那么我们不是 直接计算出(8…

F. Group Projects time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output There are n students in a class working on group projects. The students will divide into groups (some students may be in g…

F. Group Projects 题目连接: http://www.codeforces.com/contest/626/problem/F Description There are n students in a class working on group projects. The students will divide into groups (some students may be in groups alone), work on their independent piec…

F. Group Projects   There are n students in a class working on group projects. The students will divide into groups (some students may be in groups alone), work on their independent pieces, and then discuss the results together. It takes the i-th stu…

[题目]#6395. 「THUPC2018」城市地铁规划 / City [题意]给定n个点要求构造一棵树,每个点的价值是一个关于点度的k次多项式,系数均为给定的\(a_0,...a_k\),求最大价值.\(n \leq 3000,k \leq 10\). [算法]背包DP+Prufer序 首先每个点度x的价值g(x)可以暴力预处理.将每个点的度-1后,就不再有树形态这个限制了,只要n个点的度加起来是n-2即可,因为此时只要让所有还原后度不为1的点连通,度为1的叶子节点直接分配. 问题转化为n-2…

[题目]F. Group Projects [题意]给定k和n个数字ai,要求分成若干集合使得每个集合内部极差的总和不超过k的方案数.n<=200,m<=1000,1<=ai<=500. [算法]动态规划 [题解]每个集合的最小值和最大值非常重要,将序列从小到大排序后,每个集合可以视为最小值到最大值的一条线段. 设$f[i][j][k]$表示前i个数,当前有j条线段没有结束,总和为k的方案数. 转移的关键在于集合权值的拆分,转化为算每个数的贡献.数字a[i+1]的贡献就是覆盖的线段…

[CF626F]Group Projects 题目大意: 有一个长度为\(n(n\le200)\)的数列\(\{A_i\}\),将其划分成若干个子集,每个子集贡献为子集\(\max-\min\).求子集贡献和\(\le m(m\le1000)\)的划分方案数. 思路: 将每个数看成数轴上的点,原题中的子集贡献和就是在这些点中,每个点作为至多一个线段的端点,所有线段长度之和(同一线段的两个端点可以相同). 考虑动态规划,将\(\{A_i\}\)排序,用\(f[i][j][k]\)表示用了前\(i\…

Annoying problem 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5293 Description Coco has a tree, whose vertices are conveniently labeled by 1,2,-,n. There are m chain on the tree, Each chain has a certain weight. Coco would like to pick out some ch…