-->Raising Modulo Numbers Descriptions: 题目一大堆,真没什么用,大致题意 Z M H A1  B1 A2  B2 A3  B3 ......... AH  BH 有Z组数据   求(A1B1+A2B2+ ... +AHBH)mod M. Sample Input 3 16 4 2 3 3 4 4 5 5 6 36123 1 2374859 3029382 17 1 3 18132 Sample Output 2 13195 13 题目链接https://v…

[题目链接] http://poj.org/problem?id=1995 [算法] 快速幂 [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #includ…

Raising Modulo Numbers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5532   Accepted: 3210 Description People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, oth…

Raising Modulo Numbers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5477   Accepted: 3173 Description People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, oth…

Raising Modulo Numbers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5934   Accepted: 3461 Description People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, oth…

Raising Modulo Numbers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 6347   Accepted: 3740 Description People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, oth…

Raising Modulo Numbers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5500   Accepted: 3185 Description People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, oth…

id=3140">[POJ 3140] Contestants Division(树型dp) Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9121   Accepted: 2623 Description In the new ACM-ICPC Regional Contest, a special monitoring and submitting system will be set up, and stud…

[POJ 1275] Cashier Employment(差分约束系统的建立和求解) Cashier Employment Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7569   Accepted: 2856 Description A supermarket in Tehran is open 24 hours a day every day and needs a number of cashiers to f…

[POJ 2486] Apple Tree(树型dp) Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8981   Accepted: 2990 Description Wshxzt is a lovely girl. She likes apple very much. One day HX takes her to an apple tree. There are N nodes in the tree. Each…

[POJ 2942]Knights of the Round Table(双联通分量+染色判奇环) Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 11661   Accepted: 3824 Description Being a knight is a very attractive career: searching for the Holy Grail, saving damsels in distress, an…

[POJ 2750] Potted Flower(线段树套dp) Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 4566   Accepted: 1739 Description The little cat takes over the management of a new park. There is a large circular statue in the center of the park, surrou…

2295: [POJ Challenge]我爱你啊 Time Limit: 1 Sec  Memory Limit: 128 MB Description ftiasch是个十分受女生欢迎的同学,所以她总是收到许多情书.虽然她十分有魅力,然而她却是个低调的人.因此她从来不会告诉别人她到底收到了多少情书. ftiasch的好朋友1tthinking想知道她到底收到了多少情书.1tthinking知道,ftiasch每次收到一封情书,就会在日记最后写下一个包含"luvletter"子序列的…

Raising Modulo Numbers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 6373   Accepted: 3760 Description People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, oth…

2288: [POJ Challenge]生日礼物 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 382  Solved: 111[Submit][Status][Discuss] Description ftiasch 18岁生日的时候,lqp18_31给她看了一个神奇的序列 A1, A2, ..., AN. 她被允许选择不超过 M 个连续的部分作为自己的生日礼物. 自然地,ftiasch想要知道选择元素之和的最大值.你能帮助她吗?   Inp…

2288: [POJ Challenge]生日礼物 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 284  Solved: 82[Submit][Status] Description ftiasch 18岁生日的时候,lqp18_31给她看了一个神奇的序列 A1, A2, ..., AN. 她被允许选择不超过 M 个连续的部分作为自己的生日礼物. 自然地,ftiasch想要知道选择元素之和的最大值.你能帮助她吗? Input 第1行,两个整数…

2293: [POJ Challenge]吉他英雄 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 80  Solved: 59[Submit][Status] Description 1tthinking 特别喜欢玩‘guitar hero’. 现在有 N (2 ≤ N ≤ 50) 首歌在这个游戏中,他们被标为 1 到 N. 游戏会随机把歌曲分组 P. 更详细的说, 对于 P = <P1, P2, ... PN>, 游戏会在第 i 首之后播放第…

2287: [POJ Challenge]消失之物 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 254  Solved: 140[Submit][Status] Description ftiasch 有 N 个物品, 体积分别是 W1, W2, ..., WN. 由于她的疏忽, 第 i 个物品丢失了. “要使用剩下的 N - 1 物品装满容积为 x 的背包,有几种方法呢?” -- 这是经典的问题了.她把答案记为 Count(i, x) ,想要…

2295: [POJ Challenge]我爱你啊 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 126  Solved: 90[Submit][Status] Description ftiasch是个十分受女生欢迎的同学,所以她总是收到许多情书.虽然她十分有魅力,然而她却是个低调的人.因此她从来不会告诉别人她到底收到了多少情书. ftiasch的好朋友1tthinking想知道她到底收到了多少情书.1tthinking知道,ftiasch每次收…

2296: [POJ Challenge]随机种子 Time Limit: 1 Sec  Memory Limit: 128 MBSec  Special JudgeSubmit: 114  Solved: 54[Submit][Status] Description 1tthinking除了随机算法,其他什么都不会.但是他还是可以ac很多题目,他用的是什么呢?他会选择一个好的随机种子,然后输出答案.往往他选择的一个好的种子可以有99%的概率ac题目. 他会按照下面的规则选择一个种子.首先1tt…

POJ1995 Raising Modulo Numbers 计算(A1B1+A2B2+ ... +AHBH)mod M. 快速幂,套模板 /* * Created: 2016年03月30日 23时01分45秒 星期三 * Author: Akrusher * */ #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <ctime> #…

2292: [POJ Challenge ]永远挑战 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 513  Solved: 201[Submit][Status] Description lqp18_31和1tthinking经常出题来虐ftiasch.有一天, lqp18_31搞了一个有向图,每条边的长度都是1. 他想让ftiasch求出点1到点 N 的最短路."水题啊.", ftiasch这么说道. 所以1tthinking把某些…

id=1125">[POJ 1125]Stockbroker Grapevine 最短路 只是这题数据非常水. . 主要想大牛们试试南阳OJ同题 链接例如以下: http://acm.nyist.net/JudgeOnline/talking.php?pid=426&page=2 数据增大非常多 用到非常多东西才干过 (弱没过,.. 这题就是求最短路寻找全部通路中最大权的最小值外加考验英语水平-- Floyd 208K 0MS 1162B #include using namesp…

虽然A掉了但是时间感人啊.... f( x, k ) 表示使用前 x 种填满容量为 k 的背包的方案数, g( x , k ) 表示使用后 x 种填满容量为 k 的背包的方案数. 丢了第 i 个, 要填满容量为 k 的背包 , 则 ans( i , k ) = ∑ f( i - 1, h ) * g( i + 1 , k - h ) ( 0 <= h <= k ) 这样就转化为经典的背包问题了 f( x , k ) = f( x - 1 , k ) + f( x - 1 , k - w( x…

Tree Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 11570   Accepted: 3626 Description Give a tree with n vertices,each edge has a length(positive integer less than 1001).  Define dist(u,v)=The min distance between node u and v.  Give a…

2292: [POJ Challenge ]永远挑战 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 553  Solved: 230[Submit][Status][Discuss] Description lqp18_31和1tthinking经常出题来虐ftiasch.有一天, lqp18_31搞了一个有向图,每条边的长度都是1. 他想让ftiasch求出点1到点 N 的最短路."水题啊.", ftiasch这么说道. 所以1tth…

2288: [POJ Challenge]生日礼物 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 1003  Solved: 317[Submit][Status][Discuss] Description ftiasch 18岁生日的时候,lqp18_31给她看了一个神奇的序列 A1, A2, ..., AN. 她被允许选择不超过 M 个连续的部分作为自己的生日礼物. 自然地,ftiasch想要知道选择元素之和的最大值.你能帮助她吗? Inpu…

[POJ 3694] Network(割边+LCA) Network Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7971   Accepted: 2902 Description A network administrator manages a large network. The network consists of N computers and M links between pairs of comput…

[POJ 3071] Football(DP) Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4350   Accepted: 2222 Description Consider a single-elimination football tournament involving 2n teams, denoted 1, 2, -, 2n. In each round of the tournament, all tea…

2288: [POJ Challenge]生日礼物 https://lydsy.com/JudgeOnline/problem.php?id=2288 分析: 贪心+堆+链表. 首先把序列变一下,把相邻的同符号的合并起来,让序列的第一个是整数,最后一个也是整数. 如果直接算最大的选的不好算,那么考虑算最小的不选的,正难则反. 然后把所有的整数都加起来,这就是最大的共和.如果此时的段数<=m,那么直接输出就好了.否则,需要选几个数字,来合并它左右的段,以此是段的总数-1. 选的是一个负数,表示,左…