1056 Mice and Rice(25 分) Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to…

#include <cstdio> #include <climits> #include <cstdlib> #include <vector> #include <list> using namespace std; list<int>::iterator group_pick(list<int> &player, list<int>::iterator &cur, int group_si…

1056. Mice and Rice (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. Th…

1056 Mice and Rice (25 分)   Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order…

题目 Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to become a FatMouse. Fir…

时间限制 30 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to…

1.27刷题2 Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to become a FatMouse…

有n个老鼠,第一行给出n个老鼠的重量,第二行给出他们的顺序.1.每一轮分成若干组,每组m个老鼠,不能整除的多余的作为最后一组.2.每组重量最大的进入下一轮.让你给出每只老鼠最后的排名.很简单,用两个数组模拟一下即可order1存储进入当前一轮老鼠的索引顺序order2存储进入下一轮老鼠的索引顺序 如果当前有groups个组,那么会有groups个老鼠进入下一轮,则没有进入下一轮的排名都为groups+1如果只有一个组,那么最大的那个排名即为1. #include <iostream> #inc…

简单模拟. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<stack> #include<vector> using namespace std…

题意: 输入两个正整数N和M(<=1000),接着输入两行,每行N个数,第一行为每只老鼠的重量,第二行为每只老鼠出战的顺序.输出它们的名次.(按照出战顺序每M只老鼠分为一组,剩余不足M只为一组,每组只能有一个胜者,其他老鼠排名均为这一轮胜者数量+1) AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; int n,m; ],b[]; int num; ];…

题意:略 思路:利用queue来模拟一轮一轮的比赛.自己第一遍做的时候完全没有用queue做的意识,代码写的贼烦最后还只得了17分,非常郁闷.通过本题反映出对queue的应用场景季度不熟悉,STL里面用的最少的就是队列了.另外还有一点,在当前这一轮被淘汰的老鼠排名均为当前组数+1,这一点我也没看出来,自己做的时候拐了18个弯去实现这一点,真是惭愧! 代码: #include <cstdio> #include <queue> using namespace std; struct…

1056. Mice and Rice (25) 时间限制 30 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The…

1056. Mice and Rice (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. Th…

1056. Mice and Rice Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to becom…

Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to become a FatMouse. First…

Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to become a FatMouse. First…

Mice and Rice(queue的用法) Mice and Rice is the name of a programming contest in which each programmer must write a piece of code to control the movements of a mouse in a given map. The goal of each mouse is to eat as much rice as possible in order to b…

1148 Werewolf - Simple Version (20 分) Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game, player #1 said: "Player #2 is a werewolf."; player #2 said: "P…

1026 Table Tennis (30)(30 分) A table tennis club has N tables available to the public. The tables are numbered from 1 to N. For any pair of players, if there are some tables open when they arrive, they will be assigned to the available table with the…

目录 题目介绍 题解 解题思路 代码 参考链接 题目介绍 题目链接 https://pintia.cn/problem-sets/994805342720868352/problems/994805419468242944 题目考点 队列.模拟.重点在模拟,队列只用到了建立.入队.出队.清空(需要自己实现,创建新的队列然后赋值或者swap). 题目难度 PAT甲级25分 题目大意 给定1个图,每个玩家控制1只老鼠移动,每个老鼠的目标是尽可能多地吃大米变成Fat Mouse. \(N_P\)个玩家…

1056 组合数的和(15 分) 给定 N 个非 0 的个位数字,用其中任意 2 个数字都可以组合成 1 个 2 位的数字.要求所有可能组合出来的 2 位数字的和.例如给定 2.5.8,则可以组合出:25.28.52.58.82.85,它们的和为330. 输入格式: 输入在第一行中给出 N(1 < N < 10),随后一行给出 N 个不同的非 0 个位数字.数字间以空格分隔. 输出格式: 输出所有可能组合出来的2位数字的和. 输入样例: 3 2 8 5 输出样例: 330 #include&l…

1072 Gas Station (30)(30 分) A gas station has to be built at such a location that the minimum distance between the station and any of the residential housing is as far away as possible. However it must guarantee that all the houses are in its service…

1067 Sort with Swap(0,*) (25)(25 分) Given any permutation of the numbers {0, 1, 2,..., N-1}, it is easy to sort them in increasing order. But what if Swap(0, *) is the ONLY operation that is allowed to use? For example, to sort {4, 0, 2, 1, 3} we may…

1029 Median(25 分) Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences…

链接:https://www.nowcoder.com/questionTerminal/4b20ed271e864f06ab77a984e71c090f来源:牛客网PAT 1018  Public Bike Management There is a public bike service in Hangzhou City which provides great convenience to the tourists from all over the world. One may rent…

1062 Talent and Virtue (25 分) About 900 years ago, a Chinese philosopher Sima Guang wrote a history book in which he talked about people's talent and virtue. According to his theory, a man being outstanding in both talent and virtue must be a "sage(圣…

1109 Group Photo(25 分) Formation is very important when taking a group photo. Given the rules of forming K rows with N people as the following: The number of people in each row must be N/K (round down to the nearest integer), with all the extra peopl…

1080 Graduate Admission(30 分) It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each app…

1139 First Contact(30 分) Unlike in nowadays, the way that boys and girls expressing their feelings of love was quite subtle in the early years. When a boy A had a crush on a girl B, he would usually not contact her directly in the first place. Instea…

给定N个非0的个位数字,用其中任意2个数字都可以组合成1个2位的数字.要求所有可能组合出来的2位数字的和.例如给定2.5.8,则可以组合出:25.28.52.58.82.85,它们的和为330. 输入格式: 输入在一行中先给出N(1<N<10),随后是N个不同的非0个位数字.数字间以空格分隔. 输出格式: 输出所有可能组合出来的2位数字的和. 输入样例: 3 2 8 5 输出样例: 330 package com.hone.basical; import java.util.Scanner;…