There are n coins with different value in a line. Two players take turns to take one or two coins from left side until there are no more coins left. The player who take the coins with the most value wins. Could you please decide the first player will…

Nice one to learn: DP + Game Theoryhttps://lefttree.gitbooks.io/leetcode/content/dynamicProgramming2/coinsInLine2.html In game theory, we assume the other player always take optimal step too. Combining with DP, we put this assumption together with ea…

有 n 个硬币排成一条线.两个参赛者轮流从右边依次拿走 1 或 2 个硬币,直到没有硬币为止.拿到最后一枚硬币的人获胜. 请判定 第一个玩家 是输还是赢? n = 1, 返回 true.n = 2, 返回 true.n = 3, 返回 false.n = 4, 返回 true.n = 5, 返回 true. 解法:DP, 复杂度 O(N), O(N) 最少是n = 3时,返回false,说明当一个player面临只有3个棋子的时候,他肯定会输.dp[i]表示的是,当有i个棋子的时候,先手玩家会不…

变型:如果是最后拿走所有石子那个人输,则f[0] = true 394. Coins in a Line dp[n]表示n个石子,先手的人,是必胜还是必输.拿1个石子,2个石子之后都是必胜,则当前必败:拿1个石子,2个石子之后都是必败,则当前必胜:如果拿1个石子,2个石子之后有必败,则当前必胜. class Solution { public: /** * @param n: An integer * @return: A boolean which equals to true if the…

There are n coins in a line. Two players take turns to take one or two coins from right side until there are no more coins left. The player who take the last coin wins. Could you please decide the first play will win or lose? Have you met this questi…

[题目描述] There are n coins with different value in a line. Two players take turns to take one or two coins from left side until there are no more coins left. The player who take the coins with the most value wins. Could you please decide the first play…

There are n coins with different value in a line. Two players take turns to take one or two coins from left side until there are no more coins left. The player who take the coins with the most value wins. Could you please decide the first player will…

最后更新 这个题做得也不好,dp[n]尝试写了几下,不太对. 应该是类似于gem theory的题. 当只有1个硬币剩下的时候直接拿走,不BB. 剩俩的时候也都拿了.. dp[n]表示剩下多少个硬币. 轮到我们拿第i个硬币的时候,有2种情况: 我们拿这个 i . 对手选择拿1个,就是第i+1个,然后第i+ 2轮到我们,我们再决定. 对手选择拿2个,i+1和i+2, 然后i+3轮到我们. 我们拿这个i,再拿下一个i+1. 对手选择拿1个,就是第i+2, 然后i+3轮到我们. 对手选择拿2个,i+2…

https://codesolutiony.wordpress.com/2015/05/24/lintcode-coins-in-a-line-iii/ A very juicy one! Deserve more consideration. class Solution { public: /** * @param values: a vector of integers * @return: a boolean which equals to true if the first playe…

Recursion + Memorized Search(DP). And apparently, the code below can be iterative with only 3 vars - DP. class Solution { unordered_map<int, bool> cache; public: bool go(int n) { ) return false; ) return true; if(cache.find(n) == cache.end()) { cach…